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(a)
Interpretation: Names of the compounds are to be given.
Concept Introduction: The given compounds are inorganic compounds. An inorganic compound consists of a cation and an anion where cation is a positively charged ion and anion is a negatively charged ion. While writing the name of the compound, cation is written first followed by the oxidation state of the metal ion written in roman numerals in parenthesis which is further followed by the name of anion. Oxidation state is written only in cases when the involved metal ion exhibits multiple oxidation states.
(a)
Answer to Problem 21A
The name of compound is Iron (III) nitrate.
Explanation of Solution
Fe is the symbol for Iron. It exhibits +3 oxidation state and the anion is nitrate.
(b)
Interpretation: Names of the compounds are to be given.
Concept Introduction: The given compounds are inorganic compounds. An inorganic compound consists of a cation and an anion where cation is a positively charged ion and anion is a negatively charged ion. While writing the name of the compound, cation is written first followed by the oxidation state of the metal ion written in roman numerals in parenthesis which is further followed by the name of anion. Oxidation state is written only in cases when the involved metal ion exhibits multiple oxidation states.
(b)
Answer to Problem 21A
The name of compound is Cobalt (III) phosphate.
Explanation of Solution
Co is the symbol for Cobalt. It exhibits +3 oxidation state and the anion is phosphate.
(c)
Interpretation: Names of the compounds are to be given.
Concept Introduction: The given compounds are inorganic compounds. An inorganic compound consists of a cation and an anion where cation is a positively charged ion and anion is a negatively charged ion. While writing the name of the compound, cation is written first followed by the oxidation state of the metal ion written in roman numerals in parenthesis which is further followed by the name of anion. Oxidation state is written only in cases when the involved metal ion exhibits multiple oxidation states.
(c)
Answer to Problem 21A
The name of compound is Chromium (III) cyanide.
Explanation of Solution
Cr is the symbol for Chromium. It exhibits +3 oxidation state and the anion is cyanide.
(d)
Interpretation: Names of the compounds are to be given.
Concept Introduction: The given compounds are inorganic compounds. An inorganic compound consists of a cation and an anion where cation is a positively charged ion and anion is a negatively charged ion. While writing the name of the compound, cation is written first followed by the oxidation state of the metal ion written in roman numerals in parenthesis which is further followed by the name of anion. Oxidation state is written only in cases when the involved metal ion exhibits multiple oxidation states.
(d)
Answer to Problem 21A
The name of compound is Aluminium sulfate.
Explanation of Solution
Al is the symbol for Iron. It exhibits +3 oxidation states and it is the only oxidation state that it exhibits. The anion is sulfate.
(e)
Interpretation: Names of the compounds are to be given.
Concept Introduction: The given compounds are inorganic compounds. An inorganic compound consists of a cation and an anion where cation is a positively charged ion and anion is a negatively charged ion. While writing the name of the compound, cation is written first followed by the oxidation state of the metal ion written in roman numerals in parenthesis which is further followed by the name of anion. Oxidation state is written only in cases when the involved metal ion exhibits multiple oxidation states.
(e)
Answer to Problem 21A
The name of compound is Chromium (II) acetate.
Explanation of Solution
Cr is the symbol for Chromium. It exhibits +2 oxidation state and the anion is acetate.
(f)
Interpretation: Names of the compounds are to be given.
Concept Introduction: The given compounds are inorganic compounds. An inorganic compound consists of a cation and an anion where cation is a positively charged ion and anion is a negatively charged ion. While writing the name of the compound, cation is written first followed by the oxidation state of the metal ion written in roman numerals in parenthesis which is further followed by the name of anion. Oxidation state is written only in cases when the involved metal ion exhibits multiple oxidation states.
(f)
Answer to Problem 21A
The name of compound is Ammonium sulfite.
Explanation of Solution
NH4+ is the symbol for Ammonium ion. It is a polyatomic cation with one positive charge. The anion is sulfite.
Chapter 4 Solutions
World of Chemistry
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- TRANSMITTANCE เบบ Please identify the one structure below that is consistent with the 'H NMR and IR spectra shown and draw its complete structure in the box below with the protons alphabetically labeled as shown in the NMR spectrum and label the IR bands, including sp³C-H and sp2C-H stretch, indicated by the arrows. D 4000 OH LOH H₂C CH3 OH H₂C OCH3 CH3 OH 3000 2000 1500 HAVENUMBERI-11 1000 LOCH3 Draw your structure below and label its equivalent protons according to the peak labeling that is used in the NMR spectrum in order to assign the peaks. Integrals indicate number of equivalent protons. Splitting patterns are: s=singlet, d=doublet, m-multiplet 8 3Hb s m 1Hd s 3Hf m 2Hcd 2Had 1He 鄙视 m 7 7 6 5 4 3 22 500 T 1 0arrow_forwardRelative Transmittance 0.995 0.99 0.985 0.98 Please draw the structure that is consistent with all the spectral data below in the box and alphabetically label the equivalent protons in the structure (Ha, Hb, Hc ....) in order to assign all the proton NMR peaks. Label the absorption bands in the IR spectrum indicated by the arrows. INFRARED SPECTRUM 1 0.975 3000 2000 Wavenumber (cm-1) 1000 Structure with assigned H peaks 1 3 180 160 140 120 100 f1 (ppm) 80 60 40 20 0 C-13 NMR note that there are 4 peaks between 120-140ppm Integral values equal the number of equivalent protons 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 1.0 0.0 fl (ppm)arrow_forwardCalculate the pH of 0.0025 M phenol.arrow_forward
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