Experiencing MIS
8th Edition
ISBN: 9780134792736
Author: KROENKE
Publisher: PEARSON
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Chapter 4, Problem 1ARQ
Explanation of Solution
Need of business professional to know about computer hardware:
The business professional must be well savvy with the basic computer hardware components and the various units of bytes that has been used to size the computer hardware which are useful for doing the work that saves time in many different ways that are explained as follows:
Primary hardware components:
- The Primary hardware components are consisting of many electronics components that are existing in the form of input devices, output, storage to keep the data and instruction for future and the computer components or software programs to store the instructions.
- The main hardware component for any computer is the Central Processing Unit (CPU) that is also known as the Brain of the computer, for performing all the activities and execution of instructions.
- The CPU can be able to perform all the given instructions that might be in the form of Arithmetic and Logical Instructions for performing arithmetic operations and logical comparisons and then store the result in the memory.
- Computer contains storage devices for storing the data and to save instructions and programs, in the magnetic disk or in the computer hard disk for storing the data permanently.
- Optical storage devices such as CD (Compact Disk) or DVD (Digital Versatile Disk) can also be used for storing the data and as a medium for transferring the data from one computer to another.
Types of hardware:
- The hardware type can be any of the form of personal Computers including the desktop and laptops such as Apple Mac pro that is considered one of the modern personal computers.
- Other types of the hardware might be in the form of tablets including the e-book readers such as iPads, Kindle Fire, Microsoft announced Surface etc...
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Methods (Ch6) - Review
1. (The MyRoot method) Below is a manual implementation of the Math.sqrt() method in Java.
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public class SquareRoot {
public static void main(String[] args) {
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public static double myRoot(int number) {
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double root old;
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root old root;
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} while (Math.abs(root_old-root)>1.8E-6);
return root;
}
// Method that calculates the square root of double variables
public static double myRoot(double number) {
double root;
root number/2;
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do {
root old root;
root (root_old+number/root_old)/2;
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Chapter 4 Solutions
Experiencing MIS
Ch. 4.2 - Prob. 1SWCh. 4.2 - Prob. 2SWCh. 4.2 - Prob. 3SWCh. 4.2 - Prob. 4SWCh. 4.2 - Prob. 5SWCh. 4.2 - Prob. 6SWCh. 4 - Prob. 1EGDQCh. 4 - Prob. 2EGDQCh. 4 - Prob. 3EGDQCh. 4 - Prob. 4EGDQ
Ch. 4 - Prob. 1ARQCh. 4 - Prob. 2ARQCh. 4 - Prob. 3ARQCh. 4 - Prob. 4ARQCh. 4 - Prob. 1UYKCh. 4 - Prob. 2UYKCh. 4 - Prob. 3UYKCh. 4 - Prob. 4CECh. 4 - Prob. 5CECh. 4 - Prob. 6CECh. 4 - Prob. 7CECh. 4 - Prob. 8CECh. 4 - Prob. 9CSCh. 4 - Prob. 10CSCh. 4 - Prob. 11CSCh. 4 - Prob. 12CSCh. 4 - Prob. 13CSCh. 4 - Prob. 14MLMCh. 4 - Prob. 15MLM
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