
Concept explainers
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Concept Introduction:
Electrons are present outside the nucleus of an atom. These electrons are restricted to some specific regions around the nucleus of an atom. Electrons do move rapidly in the space about the nucleus is divided into subspaces that are known as shells, subshells and orbitals.
Electron shells are the space region that is present around the nucleus and this contains electrons that possess approximately same energy and which spend most of their time in the same distance from nucleus. Electron shells are numbered as 1, 2, 3, and so on. The energy of electron increases as the distance between the nucleus and electron shell increases. Electron shell can accommodate electrons and it varies because higher the electron shell number, more is the number of electrons that can be present in it.
Electron subshell is the space region in the electron shell which contains the electrons that have same energy. The number of electron subshell present for each electron shell depends upon the shell number. Electrons are added to the electron subshell in the electron shell. The number of electron subshell that is present in an electron shell depends only on the shell number. If the shell number is 1, then there is only one electron subshell. If the shell number is 2 means then there is two electron subshells and so on.
Electron orbital is the space region in electron subshell where the electrons with specific energy are most likely to be found. An electron orbital can hold only two electrons irrespective of the other considerations. “s” subshell has one orbital, “p” subshell has three orbital, “d” subshell has five orbital and “f” subshell has seven orbitals.
Each and every orbitals have distinct shape. This does not depend upon the shell number. “s” orbital is spherical shape, “p” orbital has two lobes, “d” orbitals have four lobes, and “f” orbital has eight lobes.
Electrons that are present within an orbital “move about” in an orbital. Electron spins on its own either in clockwise or anticlockwise direction. In an orbital, the two electrons that are present will have opposite spin. If one electron spins in clockwise direction, the other electron will spin in anticlockwise direction in an orbital. For two electrons present in the same orbital, this is the most favorable state energetically.

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Chapter 3 Solutions
General, Organic, and Biological Chemistry
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- Highlight each glycosidic bond in the molecule below. Then answer the questions in the table under the drawing area. HO- HO- -0 OH OH HO NG HO- HO- OH OH OH OH NG OHarrow_forward€ + Suppose the molecule in the drawing area below were reacted with H₂ over a platinum catalyst. Edit the molecule to show what would happen to it. That is, turn it into the product of the reaction. Also, write the name of the product molecule under the drawing area. Name: ☐ H C=0 X H- OH HO- H HO- -H CH₂OH ×arrow_forwardDraw the Haworth projection of the disaccharide made by joining D-glucose and D-mannose with a ẞ(1-4) glycosidic bond. If the disaccharide has more than one anomer, you can draw any of them. Click and drag to start drawing a structure. Xarrow_forward
- Epoxides can be opened in aqueous acid or aqueous base to produce diols (molecules with two OH groups). In this question, you'll explore the mechanism of epoxide opening in aqueous acid. 2nd attempt Be sure to show all four bonds at stereocenters using hash and wedge lines. 0 0 Draw curved arrows to show how the epoxide reacts with hydronium ion. 100 +1: 1st attempt Feedback Be sure to show all four bonds at stereocenters using hash and wedge lines. See Periodic Table See Hint H A 5 F F Hr See Periodic Table See Hintarrow_forward03 Question (1 point) For the reaction below, draw both of the major organic products. Be sure to consider stereochemistry. > 1. CH₂CH₂MgBr 2. H₂O 3rd attempt Draw all four bonds at chiral centers. Draw all stereoisomers formed. Draw the structures here. e 130 AN H See Periodic Table See Hint P C Brarrow_forwardYou may wish to address the following issues in your response if they are pertinent to the reaction(s) you propose to employ:1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Please make it in detail and draw it out too in what step what happens. Thank you for helping me!arrow_forward
- 1) Chemoselectivity (why this functional group and not another?) 2) Regioselectivity (why here and not there?) 3) Stereoselectivity (why this stereoisomer?) 4) Changes in oxidation state. Everything in detail and draw out and write it.arrow_forwardCalculating the pH at equivalence of a titration 3/5 Izabella A chemist titrates 120.0 mL of a 0.7191M dimethylamine ((CH3)2NH) solution with 0.5501 M HBr solution at 25 °C. Calculate the pH at equivalence. The pk of dimethylamine is 3.27. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HBr solution added. pH = ☐ ✓ 18 Ar Boarrow_forwardAlcohols can be synthesized using an acid-catalyzed hydration of an alkene. An alkene is combined with aqueous acid (e.. sulfuric acid in water). The reaction mechanism typically involves a carbocation intermediate. > 3rd attempt 3343 10 8 Draw arrows to show the reaction between the alkene and hydronium ion. that 2nd attempt Feedback 1st attempt تعمال Ju See Periodic Table See Hint F D Ju See Periodic Table See Hintarrow_forward
- General, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage LearningIntroductory Chemistry: A FoundationChemistryISBN:9781337399425Author:Steven S. Zumdahl, Donald J. DeCostePublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning


