
(a)
Interpretation:
The electron shell has to be identified for the
Concept Introduction:
Electrons are present outside the nucleus of an atom. These electrons are restricted to some specific regions around the nucleus of an atom. Electrons do move rapidly in the space about the nucleus is divided into subspaces that are known as shells, subshells and orbitals.
Electron shells are the space region that is present around the nucleus and this contains electrons that possess approximately same energy and which spend most of their time in the same distance from nucleus. Electron shells are numbered as 1, 2, 3, and so on. The energy of electron increases as the distance between the nucleus and electron shell increases. Electron shell can accommodate electrons and it varies because higher the electron shell number, more is the number of electrons that can be present in it.
Electron subshell is the space region in the electron shell which contains the electrons that have same energy. The number of electron subshell present for each electron shell depends upon the shell number. Electrons are added to the electron subshell in the electron shell. The number of electron subshell that is present in an electron shell depends only on the shell number. If the shell number is 1, then there is only one electron subshell. If the shell number is 2 means then there is two electron subshells and so on.
Electron orbital is the space region in electron subshell where the electrons with specific energy are most likely to be found. An electron orbital can hold only two electrons irrespective of the other considerations. “s” subshell has one orbital, “p” subshell has three orbital, “d” subshell has five orbital and “f” subshell has seven orbitals.
Each and every orbitals have distinct shape. This does not depend upon the shell number. “s” orbital is spherical shape, “p” orbital has two lobes, “d” orbitals have four lobes, and “f” orbital has eight lobes.
Electrons that are present within an orbital “move about” in an orbital. Electron spins on its own either in clockwise or anticlockwise direction. In an orbital, the two electrons that are present will have opposite spin. If one electron spins in clockwise direction, the other electron will spin in anticlockwise direction in an orbital. For two electrons present in the same orbital, this is the most favorable state energetically.
(b)
Interpretation:
The electron shell has to be identified for the
Concept Introduction:
Electrons are present outside the nucleus of an atom. These electrons are restricted to some specific regions around the nucleus of an atom. Electrons do move rapidly in the space about the nucleus is divided into subspaces that are known as shells, subshells and orbitals.
Electron shells are the space region that is present around the nucleus and this contains electrons that possess approximately same energy and which spend most of their time in the same distance from nucleus. Electron shells are numbered as 1, 2, 3, and so on. The energy of electron increases as the distance between the nucleus and electron shell increases. Electron shell can accommodate electrons and it varies because higher the electron shell number, more is the number of electrons that can be present in it.
Electron subshell is the space region in the electron shell which contains the electrons that have same energy. The number of electron subshell present for each electron shell depends upon the shell number. Electrons are added to the electron subshell in the electron shell. The number of electron subshell that is present in an electron shell depends only on the shell number. If the shell number is 1, then there is only one electron subshell. If the shell number is 2 means then there is two electron subshells and so on.
Electron orbital is the space region in electron subshell where the electrons with specific energy are most likely to be found. An electron orbital can hold only two electrons irrespective of the other considerations. “s” subshell has one orbital, “p” subshell has three orbital, “d” subshell has five orbital and “f” subshell has seven orbitals.
Each and every orbitals have distinct shape. This does not depend upon the shell number. “s” orbital is spherical shape, “p” orbital has two lobes, “d” orbitals have four lobes, and “f” orbital has eight lobes.
Electrons that are present within an orbital “move about” in an orbital. Electron spins on its own either in clockwise or anticlockwise direction. In an orbital, the two electrons that are present will have opposite spin. If one electron spins in clockwise direction, the other electron will spin in anticlockwise direction in an orbital. For two electrons present in the same orbital, this is the most favorable state energetically.
(c)
Interpretation:
The electron shell has to be identified for the
Concept Introduction:
Electrons are present outside the nucleus of an atom. These electrons are restricted to some specific regions around the nucleus of an atom. Electrons do move rapidly in the space about the nucleus is divided into subspaces that are known as shells, subshells and orbitals.
Electron shells are the space region that is present around the nucleus and this contains electrons that possess approximately same energy and which spend most of their time in the same distance from nucleus. Electron shells are numbered as 1, 2, 3, and so on. The energy of electron increases as the distance between the nucleus and electron shell increases. Electron shell can accommodate electrons and it varies because higher the electron shell number, more is the number of electrons that can be present in it.
Electron subshell is the space region in the electron shell which contains the electrons that have same energy. The number of electron subshell present for each electron shell depends upon the shell number. Electrons are added to the electron subshell in the electron shell. The number of electron subshell that is present in an electron shell depends only on the shell number. If the shell number is 1, then there is only one electron subshell. If the shell number is 2 means then there is two electron subshells and so on.
Electron orbital is the space region in electron subshell where the electrons with specific energy are most likely to be found. An electron orbital can hold only two electrons irrespective of the other considerations. “s” subshell has one orbital, “p” subshell has three orbital, “d” subshell has five orbital and “f” subshell has seven orbitals.
Each and every orbitals have distinct shape. This does not depend upon the shell number. “s” orbital is spherical shape, “p” orbital has two lobes, “d” orbitals have four lobes, and “f” orbital has eight lobes.
Electrons that are present within an orbital “move about” in an orbital. Electron spins on its own either in clockwise or anticlockwise direction. In an orbital, the two electrons that are present will have opposite spin. If one electron spins in clockwise direction, the other electron will spin in anticlockwise direction in an orbital. For two electrons present in the same orbital, this is the most favorable state energetically.
(d)
Interpretation:
The electron shell has to be identified for the
Concept Introduction:
Electrons are present outside the nucleus of an atom. These electrons are restricted to some specific regions around the nucleus of an atom. Electrons do move rapidly in the space about the nucleus is divided into subspaces that are known as shells, subshells and orbitals.
Electron shells are the space region that is present around the nucleus and this contains electrons that possess approximately same energy and which spend most of their time in the same distance from nucleus. Electron shells are numbered as 1, 2, 3, and so on. The energy of electron increases as the distance between the nucleus and electron shell increases. Electron shell can accommodate electrons and it varies because higher the electron shell number, more is the number of electrons that can be present in it.
Electron subshell is the space region in the electron shell which contains the electrons that have same energy. The number of electron subshell present for each electron shell depends upon the shell number. Electrons are added to the electron subshell in the electron shell. The number of electron subshell that is present in an electron shell depends only on the shell number. If the shell number is 1, then there is only one electron subshell. If the shell number is 2 means then there is two electron subshells and so on.
Electron orbital is the space region in electron subshell where the electrons with specific energy are most likely to be found. An electron orbital can hold only two electrons irrespective of the other considerations. “s” subshell has one orbital, “p” subshell has three orbital, “d” subshell has five orbital and “f” subshell has seven orbitals.
Each and every orbitals have distinct shape. This does not depend upon the shell number. “s” orbital is spherical shape, “p” orbital has two lobes, “d” orbitals have four lobes, and “f” orbital has eight lobes.
Electrons that are present within an orbital “move about” in an orbital. Electron spins on its own either in clockwise or anticlockwise direction. In an orbital, the two electrons that are present will have opposite spin. If one electron spins in clockwise direction, the other electron will spin in anticlockwise direction in an orbital. For two electrons present in the same orbital, this is the most favorable state energetically.

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Chapter 3 Solutions
General, Organic, and Biological Chemistry
- Using the bond energy values, calculate the energy that must be supplied or is released upon the polymerization of 755 monomers. If energy must be supplied, provide a positive number; if energy is released, provide a negative number. Hint: Avogadro’s number is 6.02 × 1023.arrow_forward-AG|F=2E|V 3. Before proceeding with this problem you may want to glance at p. 466 of your textbook where various oxo-phosphorus derivatives and their oxidation states are summarized. Shown below are Latimer diagrams for phosphorus at pH values at 0 and 14: Acidic solution -0.93 +0.38 -0.51 -0.06 H3PO4 →H4P206 H3PO3 H3PO2 → P→ PH3 -0.28 -0.50 → -0.50 Basic solution 3-1.12 -1.57 -2.05 -0.89 PO HPO →→H2PO2 P PH3 -1.73 a) Under acidic conditions, H3PO4 can be reduced into H3PO3 directly (-0.28V), or via the formation and reduction of H4P2O6 (-0.93/+0.38V). Calculate the values of AG's for both processes; comment. (3 points) 0.5 PH, 0.0 -0.5- 2 3 9 3 -1.5 -2.0 Pa H,PO H,PO H,PO -3 -1 0 2 4 Oxidation state, N 2 b) Frost diagram for phosphorus under acidic conditions is shown. Identify possible disproportionation and comproportionation processes; write out chemical equations describing them. (2 points) c) Elemental phosphorus tends to disproportionate under basic conditions. Use data in…arrow_forwardThese two reactions appear to start with the same starting materials but result in different products. How do the chemicals know which product to form? Are both products formed, or is there some information missing that will direct them a particular way?arrow_forward
- What would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 3 1 2 2. n-BuLi • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Explanation Check Click and drag to start drawing a structure. 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Priva ×arrow_forwardPredict the products of this organic reaction: Explanation Check IN NaBH3CN H+ ? Click and drag to start drawing a structure. D 5 C +arrow_forwardPredict the products of this organic reaction: H3O+ + ? • Draw all the reasonable products in the drawing area below. If there are no products, because no reaction will occur, check the box under the drawing area. • Include both major and minor products, if some of the products will be more common than others. • Be sure to use wedge and dash bonds if you need to distinguish between enantiomers. No reaction. Click and drag to start drawing a structure. dmarrow_forward
- Iarrow_forwardDraw the anti-Markovnikov product of the hydration of this alkene. this problem. Note for advanced students: draw only one product, and don't worry about showing any stereochemistry. Drawing dash and wedge bonds has been disabled for esc esc ☐ Explanation Check F1 1 2 F2 # 3 F3 + $ 14 × 1. BH THE BH3 2. H O NaOH '2 2' Click and drag to start drawing a structure. F4 Q W E R A S D % 905 LL F5 F6 F7 © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accessibility < & 6 7 27 8 T Y U G H I F8 F9 F10 F11 F12 9 0 J K L P + // command option Z X C V B N M H H rol option commandarrow_forwardAG/F-2° V 3. Before proceeding with this problem you may want to glance at p. 466 of your textbook where various oxo-phosphorus derivatives and their oxidation states are summarized. Shown below are Latimer diagrams for phosphorus at pH values at 0 and 14: -0.93 +0.38 -0.50 -0.51 -0.06 H3PO4 →H4P206 →H3PO3 →→H3PO₂ → P → PH3 Acidic solution Basic solution -0.28 -0.50 3--1.12 -1.57 -2.05 -0.89 PO HPO H₂PO₂ →P → PH3 -1.73 a) Under acidic conditions, H3PO4 can be reduced into H3PO3 directly (-0.28V), or via the formation and reduction of H4P206 (-0.93/+0.38V). Calculate the values of AG's for both processes; comment. (3 points) 0.5 PH P 0.0 -0.5 -1.0- -1.5- -2.0 H.PO, -2.3+ -3 -2 -1 1 2 3 2 H,PO, b) Frost diagram for phosphorus under acidic conditions is shown. Identify possible disproportionation and comproportionation processes; write out chemical equations describing them. (2 points) H,PO 4 S Oxidation stale, Narrow_forward
- 4. For the following complexes, draw the structures and give a d-electron count of the metal: a) Tris(acetylacetonato)iron(III) b) Hexabromoplatinate(2-) c) Potassium diamminetetrabromocobaltate(III) (6 points)arrow_forward2. Calculate the overall formation constant for [Fe(CN)6]³, given that the overall formation constant for [Fe(CN)6] 4 is ~1032, and that: Fe3+ (aq) + e = Fe²+ (aq) E° = +0.77 V [Fe(CN)6]³ (aq) + e¯ = [Fe(CN)6] (aq) E° = +0.36 V (4 points)arrow_forward5. Consider the compounds shown below as ligands in coordination chemistry and identify their denticity; comment on their ability to form chelate complexes. (6 points) N N A B N N N IN N Carrow_forward
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