Explanation Given Info: The number of photons emitted by laser per second is 1.49 × 10 19 . The wavelength of half of the photons is 488.0 nm and wavelength of other half of photon is 514.5 nm . The power of laser is, P = h c p 2 ( 1 λ 1 + 1 λ 2 ) Here, h is the Planck’s constant. c is the speed of light . p is the number of photons. λ 1 is the wavelength of first half of photons. λ 2 is the wavelength of second half of photon. The Planck’s constant is 6.63 × 10 − 34 J ⋅ s . The speed of light is 3 × 10 8 m / s . Substitute 6.63 × 10 − 34 J ⋅ s for h , 3 × 10 8 m / s for c , 1.49 × 10 19 for p , 488 × 10 − 9 m for λ 1 and 514

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Chapter 31, Problem 84PP

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The power output of the laser in watts.

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Chapter 31, Problem 83GP

Chapter 31, Problem 85PP

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Suppose an argon laser emits 1.49 * 1019 photons per second,half with a wavelength of 488.0 nm and half with a wavelength of514.5 nm. What is the power output of this laser in watts?A. 1.49 W B. 5.76 WC. 5.92 W D. 6.07 W

10% of the energy supplied to a bulb is radiated as visible light. How many photons are emitted per second by a 50 W bulb? Take the wavelength of visible light as 660 nm. A. 2.66 x 1019 B. 1.66 x 1020 C. 1.66 x 1019 D. 2.66 x 1020

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Chapter 31 Solutions

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