(a) Explanation Given info: The n th state of an electron is 3 . The kinetic energy of an electron is, K = 1 2 m ( 2 π k e 2 n h ) 2 Here, k is the coulomb’s constant. e is the charge of an electron. n is the n th orbital of an electron. h is the Planck’s constant. The value of Planck’s constant is 6.63 × 10 − 34 J ⋅ s . The mass of an electron is 9.11 × 10 − 31 kg . The value of coulomb’s constant is 9 × 10 9 N ⋅ m 2 / C 2 . The charge on an electron is 1.6 × 10 − 19 C . Substitute 6.63 × 10 − 34 J ⋅ s for h , 9.11 × 10 − 31 kg for m , 3 for n , 1.6 × 10 − 19 C for e and 9 × 10 9 for k to calculate K . K = 1 2 × 9 (b) To determine The potential energy of an electron. (c) To determine The total energy of an electron.

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Question

Chapter 31, Problem 21PCE

(a)

To determine

The Kinetic energy of an electron.

(b)

To determine

The potential energy of an electron.

(c)

To determine

The total energy of an electron.

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Chapter 31, Problem 20PCE

Chapter 31, Problem 22PCE

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Determine the distance between the electron and proton in an atom if the potential energy ?U of the electron is 12.6 eV (electronvolt, 1 eV =1.6×10−19=1.6×10−19 J). Give your answer in Angstrom (1 A = 10-10 m).

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