Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Question
Chapter 3, Problem 3.4.5P
To determine
(a)
The design strength.
To determine
(b)
The allowable strength.
Expert Solution & Answer
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Students have asked these similar questions
A double-angle shape is shown in the figure. The steel is
A36, and the holes are for 2-inch-diameter bolts.
Assume that A₂ = 0.75An.
Ae
1
2
Determine the design tensile strength for LRFD.
Determine the allowable strength for ASD.
CIVIL ENGINEERING
- STEEL DESIGN
AL
Section
2L5 x 3 x 516 LLBB
Two plates each with thickness t = 16 mm are bolted together with 6 – 22 mm diameter bolts forming
a lap connection. Bolt spacing are as follows: S1 = 40 mm, S2 = 80 mm, S3 = 100 mm. Bolt hole
diameter = 25 mm. Using A36 steel having Fy = 248 MPa and Fu = 400 MPa.
P P
S
- P
S2
S2
DETERMINE:
1. Determine the allowable load Pa based on bearing at bolt holes. (ASD)
2. Determine the ultimate load Pu based on block shear.
Please answer number 1, please show all the solutions step by step.
Chapter 3 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 3 - Prob. 3.2.1PCh. 3 - Prob. 3.2.2PCh. 3 - Prob. 3.2.3PCh. 3 - Prob. 3.2.4PCh. 3 - Prob. 3.2.5PCh. 3 - Prob. 3.2.6PCh. 3 - Prob. 3.3.1PCh. 3 - Prob. 3.3.2PCh. 3 - Prob. 3.3.3PCh. 3 - Prob. 3.3.4P
Ch. 3 - Prob. 3.3.5PCh. 3 - Prob. 3.3.6PCh. 3 - Prob. 3.3.7PCh. 3 - Prob. 3.3.8PCh. 3 - Prob. 3.4.1PCh. 3 - Prob. 3.4.2PCh. 3 - Prob. 3.4.3PCh. 3 - Prob. 3.4.4PCh. 3 - Prob. 3.4.5PCh. 3 - Prob. 3.4.6PCh. 3 - Prob. 3.5.1PCh. 3 - Prob. 3.5.2PCh. 3 - Prob. 3.5.3PCh. 3 - Prob. 3.5.4PCh. 3 - Prob. 3.6.1PCh. 3 - Prob. 3.6.2PCh. 3 - Prob. 3.6.3PCh. 3 - Select an American Standard Channel shape for the...Ch. 3 - Prob. 3.6.5PCh. 3 - Use load and resistance factor design and select a...Ch. 3 - Select a threaded rod to resist a service dead...Ch. 3 - Prob. 3.7.2PCh. 3 - Prob. 3.7.3PCh. 3 - Prob. 3.7.4PCh. 3 - Prob. 3.7.5PCh. 3 - Prob. 3.7.6PCh. 3 - Prob. 3.8.1PCh. 3 - Prob. 3.8.2PCh. 3 - Prob. 3.8.3PCh. 3 - Prob. 3.8.4PCh. 3 - Prob. 3.8.5P
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Similar questions
- 3. A plate with width of 300mm and thickness of 20mm is to be connected to two plates of the same width with half the thickness by 24mm diameter bolts, as shown. The rivet holes have a diameter of 2mm larger than the rivet diameter. The plate is A36 steel with yield strength F,-248MPa and ultimate strength F,-400MPa. a. Determine the design strength of the section. b. Determine the allowable strength of the section 24mm 30mmarrow_forwardGive me right solutionarrow_forwardThe given angle bar L125x75x12 with Ag = 2,269 sq.mm. is connected to a gusset plate using 20 mm diameter bolts as shown in the figure. Using A36 steel with Fy = 248 MPa and Fu = 400 MPa, determine the following: 2. Determine the nominal tensile strength of the 12 mm thick, A36 angle bar shown based on: a. Gross yielding b. Tensile rupture Bolts used for the connection are 20 mm in diameter. O O O O O O O Effective net area of the tension member if the shear lag factor is 0.80. Select the correct response: 1,516.1 1,354.4 1,431.2 1,221.6arrow_forward
- 4. Calculate the design strength (ocPn) of W24X76 with length of 12 ft. and pinned ends. A572 Grade50 steel is used. E=29x103 ksi. Show your work in detail. ASTM Classification A36 A572 Grade 50 A992 Grade 50 A500 Grade B (HSS rect, sq) A500 Grade B (HSS round) A53 Grade B Yield Strength F, (ksi) 36 50 50 46 42 35 Ultimate Strength F (ksi) 58 65 65 58 58 60arrow_forwardTensile Strength A PL 3/8 x 7 tension member is connected with three 1-inch-diameter bolts, as shown in Figure P3.2-1. The steel is A36. Assume that Ae = An %3D and compute the following. a. The design strength for LRFD. b. The allowable strength for ASD. PL %x7 O o oarrow_forwardPlease have a Given, Find & Solution.Will Thumbs Up. Thank Youarrow_forward
- STEEL ANALYSIS full solution and final answer to 4 decimal places plsarrow_forwardGive me right solutionarrow_forwardA C8 × 11.5 is connected to a gusset plale with 22 mm diameter bolts as shown. The steel is A572 Grade 50. If the member is subjected to dead load and live load only, what is the total scrvice load capacity if the live-to-dead load ratio is 3? Assume that Ae = 0.85Ap. a. Use LRFD. b. Use ASD. Properties of A572 Grade 50: Fy = 345 MPa C8 × 11.5 Fu = 448 MPa Properties of C8 x 11.5: Ag = 2,181 mm? br = 57.4 mm d= 203.2 mm Lw = 5.6 mm lf = 9.9 mmarrow_forward
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