Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 3, Problem 3.6.2P
To determine
(a)
The lightest American Standard Channel section for a tension member using the Load and Resistance Factor Design (LRFD) method.
To determine
(b)
The lightest American Standard Channel section for a tension member using Allowable Strength Design (ASD) method.
Expert Solution & Answer
Trending nowThis is a popular solution!
Students have asked these similar questions
Design a welded connection. The given loads are service loads. Use Fy =50 ksi for the angle tension member and Fy=36 ksi for the gusset plate. Show your results on a sketch, complete with dimensions.
a. Use LRFD.
b. Use ASD.
Design a welded connection for an MC9x23.9 of A572 Grade 50 steel connected to
a 3/8-inch-thick gusset plate (Figure 6). The gusset plate is A36 steel. Show your results on a
sketch, complete with dimensions.
= 3/8"
Figure 6
D = 48 k
L = 120 k
MC9 x 23.9
a. Use LRFD.
b. Use ASD.
Problem 7: The load that will be applied to the connection shown has a live load - to - dead load
ratio of 3.0. Investigate all limit states. All structural steel is A36, and the weld is a 1/4-inch fillet
weld with E70 electrodes. Note that the tension member is a double-angle shape, and both of the
angles are welded as shown. Use ASD. Determine the following.
5"
5"
2L5 X 32 X 5/16 LLBB
-t = ³/8"
Maximum service load that can be applied without
exceeding the allowable capacity on yielding on
gross area of the tension member (double angle).
Maximum service load that can be applied without
exceeding the allowable fracture on the net area
of the tension member (double angle).
Maximum service load that can be applied without
exceeding the allowable block shear strength.
Considering the weld metal and base metal
strength, calculate the maximum service load that
can be applied.
Chapter 3 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 3 - Prob. 3.2.1PCh. 3 - Prob. 3.2.2PCh. 3 - Prob. 3.2.3PCh. 3 - Prob. 3.2.4PCh. 3 - Prob. 3.2.5PCh. 3 - Prob. 3.2.6PCh. 3 - Prob. 3.3.1PCh. 3 - Prob. 3.3.2PCh. 3 - Prob. 3.3.3PCh. 3 - Prob. 3.3.4P
Ch. 3 - Prob. 3.3.5PCh. 3 - Prob. 3.3.6PCh. 3 - Prob. 3.3.7PCh. 3 - Prob. 3.3.8PCh. 3 - Prob. 3.4.1PCh. 3 - Prob. 3.4.2PCh. 3 - Prob. 3.4.3PCh. 3 - Prob. 3.4.4PCh. 3 - Prob. 3.4.5PCh. 3 - Prob. 3.4.6PCh. 3 - Prob. 3.5.1PCh. 3 - Prob. 3.5.2PCh. 3 - Prob. 3.5.3PCh. 3 - Prob. 3.5.4PCh. 3 - Prob. 3.6.1PCh. 3 - Prob. 3.6.2PCh. 3 - Prob. 3.6.3PCh. 3 - Select an American Standard Channel shape for the...Ch. 3 - Prob. 3.6.5PCh. 3 - Use load and resistance factor design and select a...Ch. 3 - Select a threaded rod to resist a service dead...Ch. 3 - Prob. 3.7.2PCh. 3 - Prob. 3.7.3PCh. 3 - Prob. 3.7.4PCh. 3 - Prob. 3.7.5PCh. 3 - Prob. 3.7.6PCh. 3 - Prob. 3.8.1PCh. 3 - Prob. 3.8.2PCh. 3 - Prob. 3.8.3PCh. 3 - Prob. 3.8.4PCh. 3 - Prob. 3.8.5P
Knowledge Booster
Similar questions
- Considering the following steel connection. The plates in Pink are 9mm steel plates. The middle plate (Yellow) is 18mm thick. The width of the plate is 100mm. The maximum allowable tension stresses on any of the plates is 100Mpa in Gross Area Yielding and 150 Mpa for Net Area or Tension Rupture. The bolts used are 8mm in diameter, the holes are 10mm in diameter, no need to add 1.6mm. The bolts allow a maximum of 280 Mpa of shear. Determine the maximum allowable "P" of the connection in kN.arrow_forward1.A tension member is 25 mm thick plate as shown. The bolts are 20 mm. diameter high-strength bolts. The steel is A36. Compute the following: 130 mm 25 mm 0 0 a) The design strength for LFRD. b) The allowable strength for ASD. 25 mm CIVIL ENGINEERING STEEL DESIGNarrow_forwardsubject: Steel Design 1. A992 steel is used for the tension member shown. The bolts are 3/4 inch in diameter. The connection is to a 3/8 in.thick gusset plate. a. Determine the nominal strength based on the gross area. b. Determine the nominal strength based on the effective net are.arrow_forward
- Select an American Standard Channel shape for the following tensile loads: dead load = 54 kips, live load = 80 kips, and wind load = 75 kips. The connection will be with longitudinal welds. Use an estimated shear lag factor of U = 0.85. (In a practical design, once the member was selected and the connection designed, the value of U would be computed and the member design could be revised if necessary.) The length is 17.5 ft. Use Fy=50 ksi and Fu=65 ksi. a. Use LRFD. b. Use ASD.arrow_forwardDetermine the adequacy of the hanger connection in Figure P7.8-2 Account for prying action. a. Use LRFD. b. Use ASD.arrow_forwardSelect a threaded rod to resist a service dead load of 45 kips and a service live load of 5 kips. Use A36 steel. a. U36 LRFD. b. Use ASD.arrow_forward
- The details of an end bearing stiffener are shown in Figure . The stiffener plates are 9⁄16-inch thick, and the web is 3⁄16-inch thick. The stiffeners are clipped 1⁄2 inch to provide clearance for the flange-to-web welds. All steel is A572 Grade 50. a. Use LRFD and determine the maximum factored concentrated load that can be supported. b. Use ASD and determine the maximum service concentrated load that can be supported.arrow_forwardCompute the maximum acceptable tensile SERVICE LOAD that may act on a single tee section that is connected to a gusset plate using welds 12 inches long, as shown in the figure. The service live load is three times the dead load. Use A992 steel. USE LRFD ONLY, no block shear will occur. WT12 x 38 Longitudinal welds 11.2 in? y = 3.0 in. Given: Properties of WT12 × 38: Ag = Use A992 Steel: F, = 50 ksi Fu = 65 ksi bf = 8.99in. %3D %3D LL = 3 DL %3D %3D tw y = centroidal distance bf C. What is the Governing Ultimate Tensile Capacity based on Net Fracture Round your answer to 3 decimal places.arrow_forwardCheck the bolted section of the given gusset plate connection assuming that the connection is done by M12 bolts with a staggered arrangement. The maximum design tensile axial force to be sustained is Ned = 168 kN. Assume a grade of S235 steel. P. Gusset plate BỘ do=13mm Gusset plate O DO t=16mm t-16mm1 Ni.Ed FO NtEd do=13mm do3D13mm G. 40mm 40mm 140 mm 240mm 30mmarrow_forward
- Problem 3. An un-equal leg angle L8x4x2 made of ASTM A242 steel (Fy = 50 ksi, Fu = 70 ksi) is used as a tension member and connected to a gusset plate as shown in Figure 2 (a to d). ASABINCAT SALLALALALALALALALAL w₁ Weld * Gusset Rate 3 (c) Longitudinal and transverse welds O 18x4x2 Gusset Plate Steel Type: A242 18x4x2 bolts: 3/4 dia. Steel Type: A242 T (d) Bolted connection (d) Calculate factored fracture strength of the tension member in Figure 2(c). (e) Calculate factored fracture strength of the tension member in Figure 2(d). (f) What is the maximum permissible length for this tension member?arrow_forward4. Determine the design strength of the connection shown in the Figure below. Thebolts are 25 mm diameter A490 bolts with the threads not in the plane of shear.A36 steel is used (Fy = 250 MPa, Fu = 400 MPa).a. Compute the shear strength for all bolts.b. Compute the bearing strength for the tension member on all bolts.c. Compute the bearing strength for the gusset plate on all bolts.d. Compute the tensile strength of the tension member.e. Compute the design strength of the connection.arrow_forwardQ1. Design the bolted connection. When a bracket is bolted to the flange of a column using a bracket plate as shown in fig. Using bracket plate. Using M20 bolts of grade 4.6 given: column section=ISWB 600 Bracket plate thickness =11 p=450KN E=270mm p=55mm bolt size=M20arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage Learning
Steel Design (Activate Learning with these NEW ti...
Civil Engineering
ISBN:9781337094740
Author:Segui, William T.
Publisher:Cengage Learning