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Concept explainers
(a)
Interpretation:
Product and balanced net ionic equation for the given aqueous solution should be written.
Concept introduction:
Most of the ionic compounds are soluble in water, very few of the ionic compounds are sparingly soluble, and some of the ionic compounds are insoluble in water. When it is soluble in water ions gets separated in the solution.
Soluble compounds in water
Almost all the salts of
Almost all the salts of
Salts of F- are soluble. But some of the fluoride salt of
Salts of
Insoluble compounds in water:
Most of the salts of
Most of the metal hydroxides and oxides are insoluble in water but some of the alkali metal hydroxides,
(a)
![Check Mark](/static/check-mark.png)
Answer to Problem 28PS
Product and balanced net ionic equation for the given aqueous solution is,
Explanation of Solution
The given compound is lead nitrate and potassium bromidewhich is soluble in water. In this reaction Pb2+ and K+ cations exchange the anions (NO3- and Br-) to give lead bromide and potassium nitrate.
Balance the equation,
Balance the bromine atom in the given equation, when balancing the equation, we should not alter the subscripts and we can change coefficients.
There are two bromine atoms in the right side and one bromine atom in the left side. Therefore two molecule of sodium bromide is added to left side of reaction. Therefore the balanced equation is given below.
Balance the sodium atom in the given equation, there are two sodium atoms in the left side and one sodium atom in the right side. Therefore two molecule of sodium nitrate is added to right side of reaction. Therefore the balanced equation is given below.
Therefore the balanced equation is given below.
Almost all the salts of
In this reaction, all the soluble ionic dissociates and forms the ions in solution.
The ionic equation is given below,
To get the net ionic equation, remove the spectator ions. Therefore the net ionic equation is given below,
(b)
Interpretation:
Product and balanced net ionic equation for the given aqueous solution should be written.
Concept introduction:
Most of the ionic compounds are soluble in water, very few of the ionic compounds are sparingly soluble, and some of the ionic compounds are insoluble in water. When it is soluble in water ions gets separated in the solution.
Soluble compounds in water
Almost all the salts of
Almost all the salts of
Salts of F- are soluble. But some of the fluoride salt of
Salts of
Insoluble compounds in water:
Most of the salts of
Most of the metal hydroxides and oxides are insoluble in water but some of the alkali metal hydroxides,
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 28PS
Product and balanced net ionic equation for the given aqueous solution is,
Explanation of Solution
The given compound is calcium nitrate and potassium fluoride which is soluble in water. In this reaction Ca2+ and K+ cations exchange the anions (NO3- and F-) to give calcium fluoride and potassium nitrate.
Balance the equation,
Balance the fluorine atom in the given equation, when balancing the equation, we should not alter the subscripts and we can change coefficients.
There are two fluorine atoms in the right side and one fluorine atom in the left side. Therefore two molecule of potassium fluoride is added to left side of reaction. Therefore the balanced equation is given below.
Balance the potassium atom in the given equation, there are two potassium atoms in the left side and one potassium atom in the right side. Therefore two molecule of potassium nitrate is added to right side of reaction. Therefore the balanced equation is given below.
Therefore the balanced equation is given below.
Almost all the salts of
In this reaction, all the soluble ionic dissociates and forms the ions in solution.
The ionic equation is given below,
To get the net ionic equation, remove the spectator ions. Therefore the net ionic equation is given below,
(c)
Interpretation:
Product and balanced net ionic equation for the given aqueous solution should be written.
Concept introduction:
Most of the ionic compounds are soluble in water, very few of the ionic compounds are sparingly soluble, and some of the ionic compounds are insoluble in water. When it is soluble in water ions gets separated in the solution.
Soluble compounds in water
Almost all the salts of
Almost all the salts of
Salts of F- are soluble. But some of the fluoride salt of
Salts of
Insoluble compounds in water:
Most of the salts of
Most of the metal hydroxides and oxides are insoluble in water but some of the alkali metal hydroxides,
(c)
![Check Mark](/static/check-mark.png)
Answer to Problem 28PS
Product and balanced net ionic equation for the given aqueous solution is,
Explanation of Solution
The given compound is calcium nitrate and sodium oxalatewhich is soluble in water. In this reaction Ca2+ and Na+ cations exchange the anions (NO3- and C2O42-) to give calciumoxalate and sodium nitrate.
Balance the equation,
Balance the sodium atom in the given equation, when balancing the equation, we should not alter the subscripts and we can change coefficients.
There are two sodium atoms in the left side and one sodium atom in the right side. Therefore two molecule of sodium nitrate is added to right side of reaction. Therefore the balanced equation is given below.
Therefore the balanced equation is given below.
Almost all the salts of
In this reaction, all the soluble ionic dissociates and forms the ions in solution.
The ionic equation is given below,
To get the net ionic equation, remove the spectator ions. Therefore the net ionic equation is given below,
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Chapter 3 Solutions
Chemistry & Chemical Reactivity
- 2. 200 LOD For an unknown compound with a molecular ion of 101 m/z: a. Use the molecular ion to propose at least two molecular formulas. (show your work) b. What is the DU for each of your possible formulas? (show your work) C. Solve the structure and assign each of the following spectra. 8 6 4 2 (ppm) 150 100 50 ō (ppm) 4000 3000 2000 1500 1000 500 HAVENUMBERI-11arrow_forwardComplete the spectroscopy with structurearrow_forwardComplete the spectroscopy with structurearrow_forward
- Given the following concentrations for a system, calculate the value for the reaction quotient: Cl2(g)+ CS2(g) ⇌ CCl4(g)+ S2Cl2(g) Cl2 = 31.1 atm CS2 = 91.2 atm CCl4 = 2.12 atm S2Cl2 = 10.4 atmarrow_forwardMatch each chemical or item with the proper disposal or cleanup mwthod, Not all disposal and cleanup methods will be labeled. Metal sheets C, calcium, choroide solutions part A, damp metal pieces Part B, volumetric flask part A. a.Return to correct lables”drying out breaker. Place used items in the drawer.: Rinse with deionized water, dry as best you can, return to instructor. Return used material to the instructor.: Pour down the sink with planty of running water.: f.Pour into aqueous waste container. g.Places used items in garbage.arrow_forwardWrite the equilibrium constant expression for the following reaction: HNO2(aq) + H2O(l) ⇌ H3O+(aq) + NO2-(aq)arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co
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