What is the value of each variable after the if statement? a. int n = 1; int k = 2; int r = n; if (k < n) { r = k; } b. int n = 1; int k = 2; int r; if (n < k) { r = k; } else { r = k + n; } c. int n = 1; int k = 2; int r = k; if (r < k) { n = r; } else { k = n; } d. int n = 1; int k = 2; int r = 3; if (r < n + k) { r = 2 * n; } else { k = 2 * r; }

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Answer 1

Textbook Question

Chapter 3, Problem 1RE

What is the value of each variable after the if statement?

a. int n = 1; int k = 2; int r = n;

if (k < n) { r = k; }

b. int n = 1; int k = 2; int r;

if (n < k) { r = k; }

else { r = k + n; }

c. int n = 1; int k = 2;

int r = k; if (r < k) { n = r; }

else { k = n; }

d. int n = 1; int k = 2; int r = 3;

if (r < n + k) { r = 2 * n; }

else { k = 2 * r; }

Expert Solution

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Expert Solution

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

//Assign k to r

r=k

}

//Otherwise

else

{

//Add k+n and store it in r

r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Expert Solution

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

//Assign k to r

n=r

}

//Otherwise

else

{

//Assign n to k

k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Expert Solution

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

//Assign k to r

r=2*n

}

//Otherwise

else

{

//Assign n to k

k=2*r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

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Specifications: Part-1Part-1: DescriptionIn this part of the lab you will build a single operation ALU. This ALU will implement a bitwise left rotation. Forthis lab assignment you are not allowed to use Digital's Arithmetic components.IF YOU ARE FOUND USING THEM, YOU WILL RECEIVE A ZERO FOR LAB2!The ALU you will be implementing consists of two 4-bit inputs (named inA and inB) and one 4-bit output (named out). Your ALU must rotate the bits in inA by the amount given by inB (i.e. 0-15).Part-1: User InterfaceYou are provided an interface file lab2_part1.dig; start Part-1 from this file.NOTE: You are not permitted to edit the content inside the dotted lines rectangle.Part-1: ExampleIn the figure above, the input values that we have selected to test are inA = {inA_3, inA_2, inA_1, inA_0} = {0, 1, 0,0} and inB = {inB_3, inB_2, inB_1, inB_0} = {0, 0, 1, 0}. Therefore, we must rotate the bus 0100 bitwise left by00102, or 2 in base 10, to get {0, 0, 0, 1}. Please note that a rotation left is…

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Answer 2

Textbook Question

Chapter 3, Problem 1RE

What is the value of each variable after the if statement?

a. int n = 1; int k = 2; int r = n;

if (k < n) { r = k; }

b. int n = 1; int k = 2; int r;

if (n < k) { r = k; }

else { r = k + n; }

c. int n = 1; int k = 2;

int r = k; if (r < k) { n = r; }

else { k = n; }

d. int n = 1; int k = 2; int r = 3;

if (r < n + k) { r = 2 * n; }

else { k = 2 * r; }

Expert Solution

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Expert Solution

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

//Assign k to r

r=k

}

//Otherwise

else

{

//Add k+n and store it in r

r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Expert Solution

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

//Assign k to r

n=r

}

//Otherwise

else

{

//Assign n to k

k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Expert Solution

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

//Assign k to r

r=2*n

}

//Otherwise

else

{

//Assign n to k

k=2*r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

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Answer 3

Textbook Question

Chapter 3, Problem 1RE

What is the value of each variable after the if statement?

a. int n = 1; int k = 2; int r = n;

if (k < n) { r = k; }

b. int n = 1; int k = 2; int r;

if (n < k) { r = k; }

else { r = k + n; }

c. int n = 1; int k = 2;

int r = k; if (r < k) { n = r; }

else { k = n; }

d. int n = 1; int k = 2; int r = 3;

if (r < n + k) { r = 2 * n; }

else { k = 2 * r; }

Expert Solution

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Expert Solution

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

//Assign k to r

r=k

}

//Otherwise

else

{

//Add k+n and store it in r

r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Expert Solution

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

//Assign k to r

n=r

}

//Otherwise

else

{

//Assign n to k

k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Expert Solution

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

//Assign k to r

r=2*n

}

//Otherwise

else

{

//Assign n to k

k=2*r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

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Answer 4

Textbook Question

Chapter 3, Problem 1RE

What is the value of each variable after the if statement?

a. int n = 1; int k = 2; int r = n;

if (k < n) { r = k; }

b. int n = 1; int k = 2; int r;

if (n < k) { r = k; }

else { r = k + n; }

c. int n = 1; int k = 2;

int r = k; if (r < k) { n = r; }

else { k = n; }

d. int n = 1; int k = 2; int r = 3;

if (r < n + k) { r = 2 * n; }

else { k = 2 * r; }

Expert Solution

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Expert Solution

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

//Assign k to r

r=k

}

//Otherwise

else

{

//Add k+n and store it in r

r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Expert Solution

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

//Assign k to r

n=r

}

//Otherwise

else

{

//Assign n to k

k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Expert Solution

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

//Assign k to r

r=2*n

}

//Otherwise

else

{

//Assign n to k

k=2*r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

Expert Solution

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Expert Solution

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

//Assign k to r

r=k

}

//Otherwise

else

{

//Add k+n and store it in r

r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Expert Solution

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

//Assign k to r

n=r

}

//Otherwise

else

{

//Assign n to k

k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Expert Solution

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

//Assign k to r

r=2*n

}

//Otherwise

else

{

//Assign n to k

k=2*r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Answer 8

Expert Solution

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

a.

//Initialize the variables

int n=1; int k=2; int r=n;

//Check the condition

if (k<n)

{

//Assign k to r

r=k

}

Value of each variable after “if” statement:

n=1, k=2, r=1

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “n” is not greater than “k” and so the value of “r” remains unchanged.

Answer 13

Expert Solution

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

//Assign k to r

r=k

}

//Otherwise

else

{

//Add k+n and store it in r

r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Answer 14

Expert Solution

Answer 15

Expert Solution

Answer 16

Expert Solution

Answer 17

Explanation of Solution

b.

//Initialize the variables

int n=1; int k=2; int r;

//Check the condition

if (n<k)

{

//Assign k to r

r=k

}

//Otherwise

else

{

//Add k+n and store it in r

r=k+n;

}

Value of each variable after “if”statement:

n=1, k=2, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement is true. As the value of “k” is greater than “n” and so the value of “r” is changed to “2”.

Answer 18

Expert Solution

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

//Assign k to r

n=r

}

//Otherwise

else

{

//Assign n to k

k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Answer 19

Expert Solution

Answer 20

Expert Solution

Answer 21

Expert Solution

Answer 22

Explanation of Solution

c.

//Initialize the variables

int n=1; int k=2; int r=k;

//Check the condition

if (r<k)

{

//Assign k to r

n=r

}

//Otherwise

else

{

//Assign n to k

k=n;

}

Value of each variable after “if”statement:

n=1, k=1, r=2

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “k” and it moves to the “else” part where the value of “k” is changed to value of “n” that is “1”. In the first statement, the value of “r” is initialized to value of “k” that is “2”.

Answer 23

Expert Solution

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

//Assign k to r

r=2*n

}

//Otherwise

else

{

//Assign n to k

k=2*r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Answer 24

Expert Solution

Answer 25

Expert Solution

Answer 26

Expert Solution

Answer 27

Explanation of Solution

d.

//Initialize the variables

int n=1; int k=2; int r=3;

//Check the condition

if (r<n+k)

{

//Assign k to r

r=2*n

}

//Otherwise

else

{

//Assign n to k

k=2*r;

}

Value of each variable after “if”statement:

n=1, k=6, r=3

Explanation:

The value assigned to variable “n” is “1”, the condition inside the “if” statement fails. As the value of “r” is not greater than “n+k” and it moves to the “else” part where the value of “k” is changed to value of “2*r” that is “6”. In the first statement, the value of “r” is initialized to “3”.

Answer 28

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