
Concept explainers
(a)
Interpretation:
From the given trials of reactants, a trial that contains Stoichiometric amounts of the reactants has to be determined.
(a)

Explanation of Solution
Given,
Trial | A | B | C | D | E |
Excess | Yes | Yes | Yes | No | No |
Excess | No | No | No | No | Yes |
By observing the given trails, Trial D has no excess reactants present in stoichiometric amounts of reactants.
Assume the volumes are measured with at least graduated cylinders, giving them one decimal place.
(b)
Interpretation:
Number of moles of
Concept introduction:
Number of moles is calculated as follows,
(b)

Explanation of Solution
Given,
Trial | A | B | C | D | E |
Excess | Yes | Yes | Yes | No | No |
Excess | No | No | No | No | Yes |
Number of moles of
Number of moles is calculated.
(c)
Interpretation:
Number of moles of
Concept introduction:
Refer to part (b)
(c)

Explanation of Solution
Given,
Trial | A | B | C | D | E |
Excess | Yes | Yes | Yes | No | No |
Excess | No | No | No | No | Yes |
Number of moles of
Number of moles is calculated.
(d)
Interpretation:
The whole number ratio of
Concept introduction:
Refer to part (b)
(d)

Explanation of Solution
Given,
Trial | A | B | C | D | E |
Excess | Yes | Yes | Yes | No | No |
Excess | No | No | No | No | Yes |
Number of moles of
Number of moles of
The whole number ratio of
The determination of mole ratio is =
Dividing by 4,
The determination of mole ratio is =
The whole number ratio of
(d)
Interpretation:
The chemical formula of the product has to be determined.
(d)

Explanation of Solution
The whole number ratio of
According to the ratio calculation, x is
Want to see more full solutions like this?
Chapter 3 Solutions
Chemistry: The Molecular Science
- Provide steps and explanation please.arrow_forwardDraw a structural formula for the major product of the acid-base reaction shown. H 0 N + HCI (1 mole) CH3 N' (1 mole) CH3 You do not have to consider stereochemistry. ● • Do not include counter-ions, e.g., Na+, I, in your answer. . In those cases in which there are two reactants, draw only the product from 989 CH3 344 ? [Farrow_forwardQuestion 15 What is the major neutral organic product for the following sequence? 1. POCI₂ pyridine ? 2. OsO4 OH 3. NaHSO Major Organic Product ✓ OH OH 'OH OH 'OH 'CIarrow_forward
- Could you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but (color-coded) and step by step so I can understand it better? Thank you! I want to see what they are doingarrow_forward
- Can you please help mne with this problem. Im a visual person, so can you redraw it, potentislly color code and then as well explain it. I know im given CO2 use that to explain to me, as well as maybe give me a second example just to clarify even more with drawings (visuals) and explanations.arrow_forwardPart 1. Aqueous 0.010M AgNO 3 is slowly added to a 50-ml solution containing both carbonate [co32-] = 0.105 M and sulfate [soy] = 0.164 M anions. Given the ksp of Ag2CO3 and Ag₂ soy below. Answer the ff: Ag₂ CO3 = 2 Ag+ caq) + co} (aq) ksp = 8.10 × 10-12 Ag₂SO4 = 2Ag+(aq) + soy² (aq) ksp = 1.20 × 10-5 a) which salt will precipitate first? (b) What % of the first anion precipitated will remain in the solution. by the time the second anion starts to precipitate? (c) What is the effect of low pH (more acidic) condition on the separate of the carbonate and sulfate anions via silver precipitation? What is the effect of high pH (more basic)? Provide appropriate explanation per answerarrow_forwardPart 4. Butanoic acid (ka= 1.52× 10-5) has a partition coefficient of 3.0 (favors benzene) when distributed bet. water and benzene. What is the formal concentration of butanoic acid in each phase when 0.10M aqueous butanoic acid is extracted w❘ 25 mL of benzene 100 mL of a) at pit 5.00 b) at pH 9.00arrow_forward
- Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
- Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning





