Explanation The procedure to make a solution of 1 .00 × 10 –6 M , it is mandatory to make a solution of sodium chloride with higher concentration, then dilute a sample of it to make the more dilute and get the solution of required concentration. For example: Weigh 5.84 g r a m s of NaCl and dilute it to 1000.0 mL to make solution A. Solution A will have a molarity of 0.0999 M (following significant figures carefully). Take 1

5th Edition

ISBN: 9781285199047

Author: John W. Moore, Conrad L. Stanitski

Publisher: Cengage Learning

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Chapter 3, Problem 3.GCP

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The procedure by which 1L of 1.00 × 10–6M NaCl solution is prepared by using balance that could measure mass only to 0.01 g has to be explained.

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Chapter 3, Problem 3.FCP

Chapter 4.1, Problem 4.1PSP

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The procedure by which 1L of 1 .00 × 10 –6 M NaCl solution is prepared by using balance that could measure mass only to 0 .01 g has to be explained.

Solution Summary: The author explains the procedure by which 1L NaCl solution is prepared by using balance that could only measure mass.

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Interpretation:

The procedure by which 1L of 1.00 × 10–6M NaCl solution is prepared by using balance that could measure mass only to 0.01 g has to be explained.

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Chapter 3 Solutions

The procedure by which 1L of 1 .00 × 10 –6 M NaCl solution is prepared by using balance that could measure mass only to 0 .01 g has to be explained.

Solution Summary: The author explains the procedure by which 1L NaCl solution is prepared by using balance that could only measure mass.

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Interpretation: The procedure by which 1L of 1.00 × 10–6M NaCl solution is prepared by using balance that could measure mass only to 0.01 g has to be explained.

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Chapter 3 Solutions

Interpretation:

The procedure by which 1L of 1.00 × 10–6M NaCl solution is prepared by using balance that could measure mass only to 0.01 g has to be explained.