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(a)
Interpretation:
The reason for the potassium ion is not given in the equation has to be explained.
Concept introduction:
Balancing reaction:
Balanced reaction is a
Steps in balancing the information
- Step 1: Write the unbalanced equation
- Step 2: Find the coefficient to balance the equation.
- The coefficient should be reduced to the smallest whole number.
(b)
Interpretation:
The reason for the given reaction is a redox reaction has to be explained.
Concept introduction:
Oxidation number:
The oxidation number of an element is zero. The oxidation number of a monoatomic ion equals its charge.
The oxidation number is zero for the summation of the oxidation numbers complete atoms in a complete formula.
The charge on the ion is equal to the summation of the oxidation numbers of complete atoms in poly atomic ion.
The oxidation state of alkali metal
The oxidation state of hydrogen is
An oxidizing agent gains the electrons and is reduced in a chemical reaction and it is electron acceptor.
A reducing agent loses electrons and is oxidized in a chemical reaction and it is electron donor.
The oxidation state is called as oxidation number, which describes degree of oxidation (loss of electrons) of an atom in a chemical compound. Theoretically, the oxidation state is positive, negative or zero.
Oxidation - reduction reaction (Redox reaction): The electrons are transferred to one to other is called oxidation reduction reaction.
(c)
Interpretation:
The oxidizing, reducing agent in the given redox reaction has to be identified.
Concept introduction:
Refer to part (a)
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Chapter 3 Solutions
Chemistry: The Molecular Science
- Aromatic Compunds for Organic ChemistryDraw the sigma complex of the following general reaction: *see attachedarrow_forwardPlease help me to figure this out. I got 24 is that correct? Please step by step help.arrow_forwardThe initial rates method can be used to determine the rate law for a reaction. using the data for the reaction below, what is the rate law for reaction? A+B-C - ALA] At (mot Trial [A] (mol) (MD 2 1 0.075 [B]( 0.075 mo LS 01350 2 0.075 0.090 0.1944 3 0.090 0.075 0.1350 Report value of k with two significant Figurearrow_forward
- Compare trials 1 and 2 where [B] is constant. The rate law can be written as: rate = k[A][B]". rate2 0.090 = 9. rate1 0.010 [A]m 6.0m = 3m [A] m 2.0marrow_forwardCan you please explain this problem to me and expand it so I can understand the full Lewis dot structure? Thanks!arrow_forwardCan you please explain this problem to me and expand it so I can understand the full Lewis dot structure? Thanks!arrow_forward
- Can you please explain this problem to me and expand it so I can understand the full Lewis dot structure? Thanks!arrow_forwardPlease answer the questions in the photos and please revise any wrong answers. Thank youarrow_forward(Please be sure that 7 carbons are available in the structure )Based on the 1H NMR, 13C NMR, DEPT 135 NMR and DEPT 90 NMR, provide a reasoning step and arrive at the final structure of an unknown organic compound containing 7 carbons. Dept 135 shows peak to be positive at 128.62 and 13.63 Dept 135 shows peak to be negative at 130.28, 64.32, 30.62 and 19.10.arrow_forward
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
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