Organic Chemistry Study Guide and Solutions
6th Edition
ISBN: 9781936221868
Author: Marc Loudon, Jim Parise
Publisher: W. H. Freeman
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Chapter 27, Problem 27.21P
Interpretation Introduction
(a)
Interpretation:
The hydrogen bonded base pair of hypoxanthine with adenine is to be shown.
Concept introduction:
Hydrogen bonding occurs when a hydrogen atom is covalently bonded to oxygen, nitrogen or fluorine and it develops some partial charge on both the atom. Hydrogen bonds can also be formed between the lone pair of an electronegative atom and hydrogen atom attached with an electronegative atom.
Interpretation Introduction
(b)
Interpretation:
The hydrogen-bonded base pair of hypoxanthine with uracil is to be stated.
Concept introduction:
Hydrogen bonding occurs when a hydrogen atom is covalently bonded to oxygen, nitrogen or fluorine and it develops some partial charge on both the atom. Hydrogen bonds can also be formed between the lone pair of an electronegative atom and hydrogen atom attached with an electronegative atom.
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Researchers analysed a glycopeptide (a peptide carrying one or several oligosaccharide
groups) and determined both the sequence of the peptide and the sequence of the sugar molecule. The
latter was identified as a diholoside coupled to the peptide by an osidic bond. The systematic name
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Question 1
represented according to the Haworth convention. Apart from the furane and/or pyrane cycles all
atoms of this molecule must be given.
DNA Replication1) Construct the complementary strand of DNA (strand II) that would pair with the DNA strand I sequence below. Remember that nucleotides are always added in the 5 prime to 3 prime direction. The base pairing rules are:
DNA DNAadenine (A) always bonds with thymine (T) thymine (T) always bonds with adenine (A) guanine (G) always bonds with cytosine (C) cytosine (C) always bonds with guanine (G)
STRAND I: 3’ T A C T A T A G T C T G T C T C C C A C T 5’
STRAND II: 5’ 3’
Draw a dihydrouridine (D) and a ribothymidine (T) base, number the ring atoms and use an “R” to indicate where the sugar would be located in each case.
Chapter 27 Solutions
Organic Chemistry Study Guide and Solutions
Ch. 27 - Prob. 27.1PCh. 27 - Prob. 27.2PCh. 27 - Prob. 27.3PCh. 27 - Prob. 27.4PCh. 27 - Prob. 27.5PCh. 27 - Prob. 27.6PCh. 27 - Prob. 27.8PCh. 27 - Prob. 27.9PCh. 27 - Prob. 27.10PCh. 27 - Prob. 27.11P
Ch. 27 - Prob. 27.12PCh. 27 - Prob. 27.13PCh. 27 - Prob. 27.14PCh. 27 - Prob. 27.15PCh. 27 - Prob. 27.16PCh. 27 - Prob. 27.17PCh. 27 - Prob. 27.18PCh. 27 - Prob. 27.19PCh. 27 - Prob. 27.20PCh. 27 - Prob. 27.21PCh. 27 - Prob. 27.22PCh. 27 - Prob. 27.23PCh. 27 - Prob. 27.24PCh. 27 - Prob. 27.25PCh. 27 - Prob. 27.26PCh. 27 - Prob. 27.27PCh. 27 - Prob. 27.28PCh. 27 - Prob. 27.29PCh. 27 - Prob. 27.30PCh. 27 - Prob. 27.31PCh. 27 - Prob. 27.32PCh. 27 - Prob. 27.33PCh. 27 - Prob. 27.34PCh. 27 - Prob. 27.35PCh. 27 - Prob. 27.36PCh. 27 - Prob. 27.37PCh. 27 - Prob. 27.38PCh. 27 - Prob. 27.39PCh. 27 - Prob. 27.40PCh. 27 - Prob. 27.41PCh. 27 - Prob. 27.42PCh. 27 - Prob. 27.43APCh. 27 - Prob. 27.44APCh. 27 - Prob. 27.45APCh. 27 - Prob. 27.46APCh. 27 - Prob. 27.47APCh. 27 - Prob. 27.48APCh. 27 - Prob. 27.49APCh. 27 - Prob. 27.50APCh. 27 - Prob. 27.51APCh. 27 - Prob. 27.52APCh. 27 - Prob. 27.53APCh. 27 - Prob. 27.54APCh. 27 - Prob. 27.55APCh. 27 - Prob. 27.56APCh. 27 - Prob. 27.57APCh. 27 - Prob. 27.58APCh. 27 - Prob. 27.59APCh. 27 - Prob. 27.60APCh. 27 - Prob. 27.61APCh. 27 - Prob. 27.62APCh. 27 - Prob. 27.63APCh. 27 - Prob. 27.64APCh. 27 - Prob. 27.65APCh. 27 - Prob. 27.66APCh. 27 - Prob. 27.67APCh. 27 - Prob. 27.68APCh. 27 - Prob. 27.69APCh. 27 - Prob. 27.70APCh. 27 - Prob. 27.71APCh. 27 - Prob. 27.72APCh. 27 - Prob. 27.73APCh. 27 - Prob. 27.74APCh. 27 - Prob. 27.75APCh. 27 - Prob. 27.76APCh. 27 - Prob. 27.77APCh. 27 - Prob. 27.78APCh. 27 - Prob. 27.79APCh. 27 - Prob. 27.80APCh. 27 - Prob. 27.81APCh. 27 - Prob. 27.82APCh. 27 - Prob. 27.83AP
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- On complete hydrolysis, a polypeptide gives two alanine, one leucine, one methionine, one phenylalanine, and one valine residue. Partial hydrolysis gives the following fragments: Ala-Phe, Leu-Met, Val-Ala, Phe-Leu. It is known that the first amino acid in the sequence is valine and the last one is methionine. What is the complete sequence of amino acids?arrow_forwardFor the tripeptide GlyAlaCys a. What amino acid is located at the peptides N-terminal end? b. What amino acid is located at the peptides C-terminal end? c. How many peptide bonds are present? d. How many amide linkages are present?arrow_forward22-42 (a) How many atoms of the peptide bond lie in the same plane? (b) Which atoms are they?arrow_forward
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- 1. Draw the two Watson-Crick Bases Pairs and show how G- C and A-T recognize each other by hydrogen bonding. 2. Draw the full structure of two nucleotides - one from DNA and one from RNA. Point out the key difference between the two. 3. Write out an example of a condensation reaction forming a phosphate-sugar bond. 4. Write out an example of a condensation reaction between a nucleic acid base and a sugar. 5. State the "Central Dogma" of biochemistry.arrow_forwardPart A. Draw the peptide formed between asparagine and histidine. Part B Fill out the following tablearrow_forward5-Bromouracil (BU) resembles thymine sufficiently that BU base-pairs readily with adenine in a DNA helix, and it can readily substitute for thy- mine in DNA replication. However, its electron distribution allows it to resemble cytosine sufficiently that BU can pair with guanine. Show how a few rounds of replication in the presence of BU could convert an A-T base pair to G-C, and identify the products of each round of replication.arrow_forward
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Nucleic acids - DNA and RNA structure; Author: MEDSimplified;https://www.youtube.com/watch?v=0lZRAShqft0;License: Standard YouTube License, CC-BY