A planer has a 10-hp motor, and 75% of the motor output is available at the cutting tool. The specific power for cutting cast iron metal is
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- Note: Read the question carefully and give me right solutions according to the question. In orthogonal cutting of steel tube of 150 mm diameter and 2 mm thick, the cutting force was 130 kg and feed force was 35 kg for chip thickness of 0.3mm. The orthogonal cut was taken at 60 meter per minute with a feed of 0.14 mm/rev. If the back rack angle of the cutting tool was - 8 o (minus 8 degree), then calculate the shear strain and strain energy per unit volume.arrow_forwardFrom the speed chart below, determine the correct cutting speed for performing a facing cut on Brass with a milling machine using a 0.5 in. diameter ball-nose end-mill Surface Speed (Ft/Min) 400 Aluminum 300 Brass/Bronze Low Carbon Steel Cast Iron 200 100 80 70 60 Alloy Steel 50 40 Diameter (in) www. 10 0.4 0.3 0.2 0.1 Cutting Speed (RPM) I 10 זזזזזױן 20 30 40 50 60 70 80 100 200 400 500 - 600 700 800 300 1000 2000 3000 - 4000 5000 - 6000 7000 8000 10000arrow_forwardA part to be turned in an engine lathe must have a surface finish of 1.6 μm. The part is made of a free machining aluminum alloy. Cutting speed = 150 m/min. The nose radius on the tool = 0.75 mm. Determine the feed that will achieve the specified surface finish.arrow_forward
- The outside diameter of a cylinder made of steel is to be turned. The starting diameter is 120 mm and the length is 1400 mm. The feed is 0.3 mm/rev and the depth of cut is 2.5mm. The cut will be made with a cemented carbide cutting tool whose Taylor tool life parameters are: n= 0.33 and C=500. Units for the Taylor equation are min for tool life and m/min for cutting speed. Compute the cutting speed that will allow the tool life to be just equal to the cutting time required to complete this turning operation.arrow_forwardIn a turning operation on low carbon steel with hardness = 135 HB, the cutting speed = 180 m/min, feed = 0.35 mm/rev, and depth of cut = 6.5 mm. The original work piece has 26 mm Diameter and 120 mm Length. How much power will the lathe draw in performing this operation if its mechanical efficiency = 90% and operator's efficiency = 82%? The specific energy is 3.8 J/mm³arrow_forwardThe following data was obtained from an orthogonal cutting test. Rake angle = 20° Depth of cut = 6 mm Feed rate = 0.25 mm/rev Cutting speed = 0.6 m/s Chip length before cutting = 29.4 mm Vertical cutting force = 1050 N Horizontal cutting force = 630 N Chip length after cutting = 12.9 mm Using Merchant's analysis, calculate (a) Magnitude of resultant force, (b) shear plane angle, (c) friction force and friction angle, and (d) various energies consumed.arrow_forward
- Parvinbhaiarrow_forwardRake angle=20 degree, Depth of cut=6 mm, Feed rate =0.25mm/rev,Cutting speed=0.6 m/s, chip length before cutting=29.4mm, vertical cutting force= 1050 NHorizontal cutting force=630, chip length after cutting=12.9Using Merchant’s analysis calculate(a) direction and magnitude of resultant force(b) friction force and friction angle(c) shear plane anglearrow_forwardacross the surface and (b) the maximum metal removal rate during cutting A slab milling operation is performed on the top surface of a steel rectangular workpiece 12.0 in long by 2.5 in wide. The helical milling cutter, which has a 3.0 in diameter and ten teeth, is set up to overhang the width of the part on both sides. Cutting speed is 125 ft/min, feed is 0.006 in/tooth, and depth of cut = 0.300 in. Determine (a) the actual machining time to make one pass across the surface and (b) the maximum metal removal rate during the cut. (c) If an additional approach distance of 0.5 in is provided at the beginning of the pass (before cutting begins), and an overtravel distance is provided at the end of the pass equal to the cutter radius plus 0.5 in, what is the duration of the feed motion.arrow_forward
- (11,00 Puanlar) 39 An orthogonal cutting operation is being carried out under the following conditions: t0=0,38 mm, tc=0,65 mm, width of the cut= 2.5 mm, V= 3.5 m/s, rake angle=D 6 , Fc= 515 N, and Ft= 210 N. Calculate the percentage of the total energy that is dissipated in the shear plane. The power input in cutting= F.V Power for shearing=F,V, t I'c tan ø = Iccos a tc 1-re sin a cin -1-arrow_forwardIt is required to reduce the thickness of cast iron workpiece with dimensions (L x w x t) of (230 mm x 120 mm x 25 mm) to 22 mm using shaper machine. Given that average cutting speed is 21 m/min, feed 1.2 mm/double stroke, and return/cutting time ratio is 3/4. The approach at each end is 72 mm. If the permissible depth of cut is 2 mm, determine the cutting time in the following cases: i) Using shaper with a mechanically driven ram. ii) Using shaper with a hydraulically driven ram. Solution: i) Mechanically ( ii) Hydraulicallyarrow_forward3) The following data are available from orthogonal cutting experiment, Depth of cut t, = 0.13 mm, width of cut w = 2.5 mm, rake angle a = -5°, cutting speed v = 2 m/s, Chip thickness, t= 0.23 mm, cutting force, F. = 430 N, thrust force, F = 280 N. Determine the following: Shear angle Friction Coefficient u (using F= µ N) Shear Stress t,S Shear strain y on the shear plane. Power required to perform the operation. Gross power required if the efficiency of the machine is 85%. Specific Energy, Utarrow_forward
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