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Suppose you decide to mill the flat surface described in Problems and 12. The work will be done on a vertical milling machine using a 1.25-in.-diameter end mill (four teeth) (HSS) cutting at 150 sfpm with a feed per tooth of 0.005 in. per tooth cutting at
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- Expert Q&A Done The top surface of a rectangular workpart is machined using a peripheral milling operation. The workpart is 735 mm long by 50 mm wide by 95 mm thick. The milling cutter, which is 60 mm in diameter and has five teeth, overhangs the width of the part equally on both sides. Cutting speed = 80 m/min, chip load = 0.30 mm/tooth, and depth of cut = 7.5 mm. (a) Determine the time required to make one pass across the surface, given that the setup and machine settings provide an approach distance of 5 mm before actual cutting begins and an overtravel distance of 25 mm after 1.2 9. 20 65 73 actual cutting has finished v in seconds. (b) What is the maximum material 3.9 239 removal rate during the cut v in mm3/sec? 0.127 5arrow_forwardthickness is HW3.A block of steel has a length L-600mm and a width W-450mm. The Machined 10mm, once by Peripheral Milling and once by planing Machine.Calculate :Machining time for each operation if you know the following For peripheral milling: cutting speed V =80 m/min, Feed f-0.15mm/rev, the cutter .1 diameter D =50 mm with five teeth and depth of cut d =3mm For planing: clearance on both sides c =25mm, cutting speed V =36.56 m/min, retum to .2 cutting ratio m =0.25, feed f=5 mm/stroke and depth of cut d =5 mm .Calculate Material removal rate in both processes .3 Solutionarrow_forwardNote: All dimensions are in mm Ø 34 A 34 mm diameter x 120 mm shafting will be turned using a lathe to produce a step shafting as shown in the figure. Calculate the required (minimum) total machining time Tm with the following cutting 30 -70- 50 120 conditions: Step Shafting Rough Turn: V = 30 m/min; Max. Depth of Cut = 1.5 mm; Feed = 0.2 mm/rev Finish Turn: V = 60 m/min; Max. Depth of Cut = 0.5 mm; Feed = 0.05 mm/rev Lathe available rpm: 150, 200, 250, 350, 400, 450, 500, 550, 600, 650, 700arrow_forward
- Q1. Calculate the time required to machine a workpiece 170 mm long, 60 mm diameter to 165 mm long 50 mm diameter. The workpiece rotates at 440 rpm, feed is 0.3 mm/rev and maximum depth of cut is 2 mm. Assume total approach and overtravel distance as 5 mm for turning operation. Answer Q2. A gray cast iron surface 280 wide and 540mm long may be machined either on a vertical milling machine, using a 100mm - diameter face mill having eight inserted HSS teeth, or on a horizontal milling machine using an HSS slab mill with eight teeth on a 200-mm. diameter. Which machine has the faster cutting time? The values of feed per tooth and cutting speed for both processes are 0.4mm/tooth and 80m/min, respectively. The depth of cut = 3.0 mm and assume A and O equal to 5. Answerarrow_forwardA cylindrical workpiece has a 14.0 in diameter and has 30 in long. It is to be turned in an engine lathe at the following cutting conditions: cutting speed = 400 ft/min, feed = 0.015 in/rev, and depth of cut = 0.150 in. Determine the time to complete one turning pass if the approach and overtravel allowances are each 0.25 in (total = 0.50 in). Note: 1 ft = 12 inarrow_forwardThe face milling cutter of D = 200 mm used to cut a block which is 200 mm H, 1=480 mm, if f- 0.7 mm/rev is used and the overrun of the cutter is 12 mm and cutting speed 320 mm/min. Calculate the machining time. Cuttinarrow_forward
- An end milling operation is carried out along a straight line path that is 325 mm long. The cut is in a direction parallel to the x‑axis on a CNC machining center. Cutting speed = 30 m/min, and chip load = 0.06 mm. The end milling cutter has two teeth and its diameter = 16.0 mm. The x‑axis uses a DC servomotor connected directly to a leadscrew whose pitch = 6.0 mm. The optical encoder emits 400 pulses per revolution of the screw. Determine (a) feed rate during the cut, (b) rotational speed of the motor, and (c) pulse rate of the encoder at the feed rate indicated.arrow_forwardThe outline of the part in the Figure below is to be profile milled using a 20- mm diameter end mill with two teeth. The part is 10 mm thick. The cutting speed = 125 m/min and feed = 0.10 mm/tooth. The part is also to be drilled with a drill size of 10 mm corresponds to T01 with a cutting speed =75 mm/min and feed = 0.08 mm/rev. The two holes pass completely through the part. 30 rad. 125.75 10 dia., 2 holes Write the part program (G & M code program) for the required machining processes. Use absolute programming with the lower left 25 corner of the part as the origin in the x-y axis system. 150 (All dimensions are in mm.) 25 50 75 35 deg.arrow_forwardIt takes only 12 seconds to mill 0.5" x 5.5" keyway by means of a 40-tooth cutter at a feed rate of 0.249 mm/tooth. Compute the required speed of the cutter in rpm. 70 O65 O 60 75 Aarrow_forward
- solvearrow_forwardA mild steel specimen of Initial diameter of 51.5 mm is turned to final diameter of 48 mm for an initial length of 151 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.1 mm/rev & Depth of cut is 0.5 mm (ii) During machining the tool's approach length is 7 mm, over run length is 2mm (iii) Total time required to complete the turning operation is 48.8 minutes (a) Find number of passes to finish the entire turning operation (b) The actual length of the turning operation in mm ( (c)The time required to complete one single turning operation in minutes (d) Spindle speed in rpmarrow_forwardA mild steel specimen of Initial diameter of 53.5 mm is turned to final diameter of 47 mm for an initial length of 154 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.4 mm/rev & Depth of cut is 0.5 mm (ii) During machining the tool's approach length is 5 mm, over run length is 2mm (iii) Total time required to complete the turning operation is 59.6 minutesarrow_forward
- Precision Machining Technology (MindTap Course Li...Mechanical EngineeringISBN:9781285444543Author:Peter J. Hoffman, Eric S. Hopewell, Brian JanesPublisher:Cengage Learning