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How much time would be required to shape a flat surface 254 mm (1 in.) wide and 203 mm (8 in.) long on a hydraulic drive shaper, using a cutting speed of 45-7 m (150 ft)per minute, a feed of 0.51 mm (0.020 in.) per stroke, and an overrun of
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- calculate the time taken to complete a 300 mm long cut on an aluminium plate using a 75 mm diameter slab mill with 6 teeth.arrow_forwardPlease need within 30 min Thank you.arrow_forwardacross the surface and (b) the maximum metal removal rate during cutting A slab milling operation is performed on the top surface of a steel rectangular workpiece 12.0 in long by 2.5 in wide. The helical milling cutter, which has a 3.0 in diameter and ten teeth, is set up to overhang the width of the part on both sides. Cutting speed is 125 ft/min, feed is 0.006 in/tooth, and depth of cut = 0.300 in. Determine (a) the actual machining time to make one pass across the surface and (b) the maximum metal removal rate during the cut. (c) If an additional approach distance of 0.5 in is provided at the beginning of the pass (before cutting begins), and an overtravel distance is provided at the end of the pass equal to the cutter radius plus 0.5 in, what is the duration of the feed motion.arrow_forward
- 17) A50-mm-dia endmill cuts 6061 aluminum with 30% tool engagement at a depth of 6 mm. The tool rotates at 200 rpm and is feeding at 250 mm/min. There are 2 teeth set at a rake angle of 10°. a. Calculate the required power of cutting. b. Determine the spindle torque. c. Determine the cutting force on each tooth. d. If the thrust force is measured to be 350N, estimate the tool-chip interface friction coefficient. How could you physically verify your power estimate?arrow_forwardPuanlar) 16 The outside diameter of a cylinder made of titanium alloy is to be turned. The starting diameter is 400 mm and the length is 1100 mm. The feed is 0.35 mm/rev and the depth of cut is 2.5 mm. The cut will be made with a cemented carbide cutting tool whose Taylor tool life parameters are: n= 0.24 and C=450. Units for the Taylor equation are min for tool life and m/min for cutting speed. Compute the cutting speed that will allow the tool life to be just equal to the cutting time for this part. V vT" = C. %3D Ce Tm 1. %3D 19 fv 25 31 37 43 49 187.9 m/min b) 325.8 m /min 275.8 m/min d) 226.6 m/minarrow_forwardThe time required to saw a rectangular piece of stainless steel plate 3.5 meters long and 2.25 meters wide is 3/4 hour. the average feed per stroke of hacksaw is 0.25 mm. Calculate the required speed of the power saw in rpm in doing the crosswise cutting operation if the thickness is 25 mm. O125 O 200 O 150 O 175arrow_forward
- Turning Operation In a production turning operation, the foreman has decreed that a single pass must be completed on the cylindrical workpiece in 4.8 min. The piece is 400 mm long and 150 mm in diameter. Using a feed = 0.43 mm/rev and a depth of cut = 4.0 mm, what cutting speed must be used to meet this machining time requirement? Hint: Re-arrange the Tm equation to find v in m/min Tm= T.DO.L v.f 1.522arrow_forwardQ24. For the below figure please write its part program. The depth of the cut is 0.25 inches (Finishing operation), while the tool's diameter is 0.5 inches. Consider the speed and feed. -0.75- - - 1.0 60⁰ RO.25 (0, 0) 0.75-arrow_forwardsolve correctlyarrow_forward
- How much machining time required to turn a mild steel rod from 65mm to 58 mm over a length of 100 mm by turning using a carbide insert. If the approach length and over run length is = 5 mm, Cutting speed is 20 m/min and feed is =0.2 mm/rev, and the depth of cut is 0.5mm Darrow_forwardThe outline of the part in the Figure below is to be profile milled using a 20- mm diameter end mill with two teeth. The part is 10 mm thick. The cutting speed = 125 m/min and feed = 0.10 mm/tooth. The part is also to be drilled with a drill size of 10 mm corresponds to T01 with a cutting speed =75 mm/min and feed = 0.08 mm/rev. The two holes pass completely through the part. 30 rad. 125.75 10 dia., 2 holes Write the part program (G & M code program) for the required machining processes. Use absolute programming with the lower left 25 corner of the part as the origin in the x-y axis system. 150 (All dimensions are in mm.) 25 50 75 35 deg.arrow_forwardThe end of a large tubular workpart is to be faced on a NC vertical boring mill. The part has an outside diameter of 38.0 in and an inside diameter of 24.0 in. If the facing operation is performed at a rotational speed of 40.0 rev/min, feed of 0.015 in/rev, and depth of cut of 0.180 in, determine (a) the cutting time to complete the facing operation and the cutting speeds and metal removal rates at the beginning and end of the cut.arrow_forward
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