Chapter 2.6, Problem 22P

(a)

Interpretation Introduction

Interpretation: The products for given acid-base reactions have to be determined.

Concept introduction:

According to the explanations by Bronsted-Lowry, if a species loses a proton then it is an acid whereas if a species receives one proton, then it is base.

If a base receives one proton, then the formed species is a conjugate acid whereas an acid lose one proton, then the formed species is a conjugated base.

Mixture of acid and base undergoes equilibrium reaction and it’s ${\text{pk}}_{\text{a}}$-values determine their direction of reaction.

Weak acids are more stable and less reactive, so equilibrium follows the direction of formation weak acids in a reaction.

Lesser the ${\text{pk}}_{\text{a}}$- value of compound will be more acidic. So the equilibrium follows the direction of compounds having low ${\text{pk}}_{\text{a}}$-value to the products of high ${\text{pk}}_{\text{a}}$ value

(b)

Interpretation Introduction

Interpretation:

Among the given reaction the reaction that is product formation favored has to be identified.

Concept introduction:

According to the explanations by Bronsted-Lowry, if a species loses a proton then it is an acid whereas if a species receives one proton, then it is base.

If a base receives one proton, then the formed species is a conjugate acid whereas an acid lose one proton, then the formed species is a conjugated base.

Mixture of acid and base undergoes equilibrium reaction and it’s ${\text{pk}}_{\text{a}}$-values determine their direction of reaction.

Weak acids are more stable and less reactive, so equilibrium follows the direction of formation weak acids in a reaction.

Lesser the ${\text{pk}}_{\text{a}}$- value of compound will be more acidic. So the equilibrium follows the direction of compounds having low ${\text{pk}}_{\text{a}}$-value to the products of high ${\text{pk}}_{\text{a}}$ value