Explanation Given data : Consider that radio station broadcasts the power 10 W of electromagnetic waves. Explanation: Consider the following expression that relates the intensity of wave with electric field amplitude. I = c ε 0 E 0 2 2 (1) Here, ε 0 is permittivity of free space, which is generally known as 8.85 × 10 − 12 C 2 N ⋅ m 2 , and c is the velocity of light in vacuum, which is generally 3 × 10 8 m s . Consider the following expression that relates the intensity of wave with power and area of cross-section. I = P A (2) Here, A is cross-sectional area of the spherical space, which is generally known as 4 π r 2 . Consider that r is the distance from the antenna. Compare equations (1) and (2). P A = c ε 0 E 0 2 2 Substitute 4 π r 2 for A , P 4 π r 2 = c ε 0 E 0 2 2 Re-arrange the equation. r 2 = 2 P 4 π c ε 0 E 0 2 Apply square root on both sides of the equation. r = 2 P 4 π c ε 0 E 0 2 Substitute 10 W for P , 2.0 × 10 − 3 V m for E 0 , 3 × 10 8 m s for c , and 8

College Physics: A Strategic Approach (3rd Edition)

3rd Edition

ISBN: 9780321879721

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Question

Chapter 25, Problem 36P

To determine

To find: The distance from the antenna when the electric field amplitude is 2.0×10−3 Vm .

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Chapter 25, Problem 35P

Chapter 25, Problem 37P

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Chapter 25 Solutions

College Physics: A Strategic Approach (3rd Edition)

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The distance from the antenna when the electric field amplitude is 2.0 × 10 − 3 V m .

Solution Summary: The author explains how to find the distance from the antenna when the electric field amplitude is 2.0times 10-3

To find: The distance from the antenna when the electric field amplitude is 2.0×10−3 Vm .

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Chapter 25 Solutions