Communication with submerged submarines via radio waves is difficult because seawater is conductive and absorbs electromagnetic waves. Penetration into the ocean is greater at longer wavelengths, so the United States has radio installations that transmit at 76 Hz for submarine communications. What is the approximate wavelength of those extremely low-frequency waves? A. 500 km B. 1000 km C. 2000 km D. 4000 km
Communication with submerged submarines via radio waves is difficult because seawater is conductive and absorbs electromagnetic waves. Penetration into the ocean is greater at longer wavelengths, so the United States has radio installations that transmit at 76 Hz for submarine communications. What is the approximate wavelength of those extremely low-frequency waves? A. 500 km B. 1000 km C. 2000 km D. 4000 km
Communication with submerged submarines via radio waves is difficult because seawater is conductive and absorbs electromagnetic waves. Penetration into the ocean is greater at longer wavelengths, so the United States has radio installations that transmit at 76 Hz for submarine communications. What is the approximate wavelength of those extremely low-frequency waves?
A. 500 km
B. 1000 km
C. 2000 km
D. 4000 km
Interaction between an electric field and a magnetic field.
a cubic foot of argon at 20 degrees celsius is isentropically compressed from 1 atm to 425 KPa. What is the new temperature and density?
Calculate the variance of the calculated accelerations. The free fall height was 1753 mm. The measured release and catch times were:
222.22 800.00
61.11 641.67
0.00 588.89
11.11 588.89
8.33 588.89
11.11 588.89
5.56 586.11
2.78 583.33
Give in the answer window the calculated repeated experiment variance in m/s2.
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