Organic Chemistry
4th Edition
ISBN: 9780073402772
Author: Janice G. Smith
Publisher: MCG
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 25, Problem 25.7P
Interpretation Introduction
Interpretation: The structure of the compound with molecular formula
Concept introduction: Degree of unsaturation is used to determine the total number of rings and pi bonds present in compound by just looking at the molecular formula. It does not specify the total number of rings and total number of pi bonds individually.
NMR spectroscopy is a technique used to determine a unique structure of the compounds. It identifies the carbon-hydrogen bonding of an organic compound. A hydrogen atom is called as a proton in the NMR spectroscopy.
The number of NMR signal in a compound is equal to the number of chemically non-equivalent protons present in that compound. The more the shielded proton less will be its chemical shift value and the corresponding signal will be produced at the right-hand side or lower frequency region or vice versa.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
What is the structure of an unknown compound with molecular formula C6H15N that gives the following 1H NMR absorptions: 0.9 (singlet, 1 H), 1.10 (triplet, 3 H), 1.15 (singlet, 9 H), and 2.6 (quartet, 2 H) ppm?
How could 1H NMR spectroscopy be used to distinguish between each pair of compounds?
Compound X (molecular formula C10H120) was treated with NH2NH2, ¯OH to yield compound Y (molecular formula C10H14). Match
the 1H NMR spectra of X and Y to the corresponding structures of X and Y.
Compound NH2NH2 Compound
'H NMR of X
6 H
OH
Y
1 H
5H
8.
6.
4
ppm
or
H NMR of Y
6 H
2H
5H
1 H
multiplet
multiplet
8.
6.
4.
3.
1
nnm
2.
2.
3,
O:
Chapter 25 Solutions
Organic Chemistry
Ch. 25 - Prob. 25.1PCh. 25 - Draw the structure of a compound of molecular...Ch. 25 - Prob. 25.3PCh. 25 - Prob. 25.4PCh. 25 - Prob. 25.5PCh. 25 - Arrange the compounds in order of increasing...Ch. 25 - Prob. 25.7PCh. 25 - Prob. 25.8PCh. 25 - Problem 25.7
Draw the product of each...Ch. 25 - Prob. 25.10P
Ch. 25 - Prob. 25.11PCh. 25 - Prob. 25.12PCh. 25 - Prob. 25.13PCh. 25 - Prob. 25.14PCh. 25 - Prob. 25.15PCh. 25 - Prob. 25.16PCh. 25 - Prob. 25.17PCh. 25 - Prob. 25.18PCh. 25 - Draw the products of each acidbase reaction....Ch. 25 - Prob. 25.20PCh. 25 - Prob. 25.21PCh. 25 - Prob. 25.22PCh. 25 - Prob. 25.23PCh. 25 - Problem 25.22
Which nitrogen atom in each compound...Ch. 25 - Which N atom in each drug is more basic? a. b. c.Ch. 25 - Prob. 25.26PCh. 25 - Prob. 25.27PCh. 25 - Prob. 25.28PCh. 25 - Prob. 25.29PCh. 25 - Prob. 25.30PCh. 25 - Problem 25.28
Draw the major product formed in...Ch. 25 - Prob. 25.32PCh. 25 - Prob. 25.33PCh. 25 - Problem 25.31
Devise a synthesis of each compound...Ch. 25 - Prob. 25.35PCh. 25 - Problem 25.33
What starting materials are needed...Ch. 25 - Problem 25.34
(a) What two components are needed...Ch. 25 - Prob. 25.38PCh. 25 - Prob. 25.39PCh. 25 - Prob. 25.40PCh. 25 - 25.37 Varenicline (trade name Chantix) is a drug...Ch. 25 - Prob. 25.42PCh. 25 - Prob. 25.43PCh. 25 - Prob. 25.44PCh. 25 - Prob. 25.45PCh. 25 - Prob. 25.46PCh. 25 - Prob. 25.47PCh. 25 - Prob. 25.48PCh. 25 - Decide which N atom in each molecule is most basic...Ch. 25 - 25.44 Rank the nitrogen atoms in each compound in...Ch. 25 - 25.45 Explain why nitroaniline is a stronger base...Ch. 25 - 25.46 Explain the observed difference in the...Ch. 25 - 25.47 Why is pyrrole more acidic than...Ch. 25 - How would you prepare 3-phenyl-1-propanamine...Ch. 25 - Prob. 25.55PCh. 25 - Prob. 25.56PCh. 25 - Prob. 25.57PCh. 25 - Prob. 25.58PCh. 25 - 25.51 How would you separate toluene , benzoic...Ch. 25 - 25.52 Draw the products formed when methylaniline ...Ch. 25 - Prob. 25.61PCh. 25 - Prob. 25.62PCh. 25 - Prob. 25.63PCh. 25 - Prob. 25.64PCh. 25 - Prob. 25.65PCh. 25 - Prob. 25.66PCh. 25 - Prob. 25.67PCh. 25 - Prob. 25.68PCh. 25 - 25.60 A chiral amine A having the configuration...Ch. 25 - 25.61 Draw a stepwise mechanism for each...Ch. 25 - 25.62 Draw a stepwise mechanism for the following...Ch. 25 - Prob. 25.72PCh. 25 - Tertiary (3) aromatic amines react with NaNO2 and...Ch. 25 - Prob. 25.74PCh. 25 - Devise a synthesis of each compound from benzene....Ch. 25 - Prob. 25.76PCh. 25 - Prob. 25.77PCh. 25 - Prob. 25.78PCh. 25 - Prob. 25.79PCh. 25 - Synthesize each compound from benzene. Use a...Ch. 25 - Prob. 25.81PCh. 25 - Devise a synthesis of each compound from benzene,...Ch. 25 - Prob. 25.83PCh. 25 - 25.72 Three isomeric compounds A, B, and C, all...Ch. 25 - 25.73 Treatment of compound D with LiAlH4 followed...Ch. 25 - Prob. 25.86PCh. 25 - 25.75 Rank the following compounds in order of...Ch. 25 - Prob. 25.88PCh. 25 - Prob. 25.89PCh. 25 - Prob. 25.90P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Following are 1H-NMR spectra for compounds G, H, and I, each with the molecular formula C5H12O. Each is a liquid at room temperature, is slightly soluble in water, and reacts with sodium metal with the evolution of a gas. (a) Propose structural formulas of compounds G, H, and I. (b) Explain why there are four lines between 0.86 and 0.90 for compound G. (c) Explain why the 2H multiplets at 1.5 and 3.5 for compound H are so complex.arrow_forwardPhenacetin, a substance formerly used in over-the-counter headache remedies, has the formula C10H13NO2. Phenacetin is neutral and does not dissolve in either acid or base. When warmed with aqueous NaOH, phenacetin yields an amine, C8H11NO, whose 1H NMR spectrum is shown. When heated with HI, the amine is cleaved to an aminophenol, C6H7NO. What is the structure of phenacetin, and what are the structures of the amine and the aminophenol?arrow_forwardAscaridole is a natural product that has been used to treat intestinal worms. Explain why the two methyls on the isopropyl group in ascaridole appear in its 1H-NMR spectrum as four lines of equal intensity, with two sets of two each separated by 7 Hz.arrow_forward
- A 13C NMR spectrum of commercially available 2,4-pentanediol, shows five peaks at 23.3, 23.9, 46.5, 64.8, and 68.1 . Explain.arrow_forwardThe 1H NMR spectrum shown is that of a cyclic ether with the formula C4H8O. Propose a structure.arrow_forwardCompound H (C8H6O3) gives a precipitate when treated with hydroxylamine in aqueous ethanol and a silver mirror when treated with Tollens solution. Following is its 1H-NMR spectrum. Deduce the structure of compound H.arrow_forward
- A compound of unknown structure gave the following spectroscopic data: Mass spectrum: M+=88.1 IR: 3600 cm-1 1ΗNMR: 1.4 δ (2 H, quartet, J=7 Hz); 1.2 δ (6H, singlet): 1.0 δ (1 H, singlet); 0.9 δ (3 H, triplet, J=7 Hz) 13CNMR: 74, 35, 27, 25 δ (a) Assuming that the compound contains C and H but may or may not contain O, give three possible molecular formulas (b) How many protons (H) does the compound contain? (c) What functional groups(s) does the compound contain? (d) How many carbons does the compound contain? (e) What is the molecular formula of the compound? (f) What is the structure of the compound? (g) Assign peaks in the molecule’s 1HNMR spectrum corresponding to specific protons.arrow_forward3-Methyl-2-butanol has five signals in its 13C NMR spectrum at 17.90, 18.15, 20.00, 35.05, and 72.75 . Why are the two methyl groups attached to C3 nonequivalent? Making a molecular model should be helpful.arrow_forwardThe 'H NMR spectrum of compound A (C3H100) has four signals: a multiplet at 8 = 7.25-7.32 ppm (5 H), a singlet at d = 5.17 ppm (1 H), a quartet at d = 4.98 ppm (1 H), and a doublet at ô = 1.49 ppm (3 H). There are 6 signals in its 13C NMR spectrum. The IR spectrum has a broad absorption in the -3200 cm-1 region. Compound A reacts with KMNO4 in a basic solution followed by acidification to give compound B with the molecular formula C7H6O2. Draw structures for compounds A and B.arrow_forward
- Nonearrow_forwardidentify the compound with molecular formula C2H6O that gives this 1H NMR spectrum.arrow_forwardwhat is is the structure of a compound of molecular formula c 10 h 14 o 2 that shows a strong ir absorption at 3150-2850 cm − 1 and give the following 1 h nmr absorptions: 1.4 (triplet, 6 h), 4.0 (quarter, 4h), and 6.8 (singlet, 4h) ppm?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
NMR Spectroscopy; Author: Professor Dave Explains;https://www.youtube.com/watch?v=SBir5wUS3Bo;License: Standard YouTube License, CC-BY