Interpretation:
The ratio used in carbon -14 dating to be defined.
Concept introduction:
Radioactive decay is unstable nuclei that lose energy by emitting radiation in a spontaneous process. Until they form stable atoms unstable atoms undergo radioactive decay, often of a dissimilar element.
![Check Mark](/static/check-mark.png)
Answer to Problem 49A
The ratio that is used in carbon 14 dating is carbon 12 + carbon 13. This ratio constant in living organisms because organisms are regularly taking in carbon compounds; they contain same ratio of carbon-14 to carbon-12 and carbon-13 that found in atmosphere.
Explanation of Solution
The ratio that is used in carbon 14 dating is carbon 12 + carbon 13. Whenever animals consume plants, carbon-14 atoms that were part of the plant turn into the part of animal. This is because organisms are regularly taking in carbon compounds; they contain same ratio of carbon-14 to carbon-12 and carbon-13 that found in atmosphere. After they die, organisms no longer absorb new carbon compounds, and carbon-14 they already consist of continues to decay.
Carbon 12 + carbon 13 are the ratio that is used in carbon 14 dating. After animals are dying, organisms no longer absorb new carbon compounds thus carbon-14 they already consist of continues to decay.
Chapter 24 Solutions
Chemistry: Matter and Change
Additional Science Textbook Solutions
Applications and Investigations in Earth Science (9th Edition)
Campbell Biology (11th Edition)
Laboratory Experiments in Microbiology (12th Edition) (What's New in Microbiology)
Human Anatomy & Physiology (2nd Edition)
Chemistry: A Molecular Approach (4th Edition)
Genetic Analysis: An Integrated Approach (3rd Edition)
- 3. Two solutions are prepared using the same solute: Solution A: 0.14 g of the solute dissolves in 15.4 g of t-butanol Solution B: 0.17 g of the solute dissolves in 12.7 g of cyclohexane Which solution has the greatest freezing point change? Show calculations and explain.arrow_forward2. Give the ground state electron configuration (e.g., 02s² σ*2s² П 2p²) for these molecules and deduce its bond order. Ground State Configuration Bond Order H2+ 02- N2arrow_forward1. This experiment is more about understanding the colligative properties of a solution rather than the determination of the molar mass of a solid. a. Define colligative properties. b. Which of the following solutes has the greatest effect on the colligative properties for a given mass of pure water? Explain. (i) 0.01 mol of CaCl2 (ii) 0.01 mol of KNO3 (iii) 0.01 mol of CO(NH2)2 (an electrolyte) (an electrolyte) (a nonelectrolyte)arrow_forward
- 5. b. For Trials 2 and 3, the molar mass of the solute was 151 g/mol and 143 g/mol respectively. a. What is the average molar mass of the solute ? b. What are the standard deviation and the relative standard deviation (%RSD) for the molar mass of the solute ?arrow_forwardShow work. Don't give Ai generated solutionarrow_forward2. Explain why ice cubes formed from water of a glacier freeze at a higher temperature than ice cubes formed from water of an under- ground aquifer. Photodynamic/iStockphotoarrow_forward
- Show reaction mechanism. don't give Ai generated solutionarrow_forward7. Draw the Lewis structures and molecular orbital diagrams for CO and NO. What are their bond orders? Are the molecular orbital diagrams similar to their Lewis structures? Explain. CO Lewis Structure NO Lewis Structure CO Bond Order NO Bond Order NO Molecular Orbital Diagram CO Molecular Orbital Diagramarrow_forward5. The existence of compounds of the noble gases was once a great surprise and stimulated a great deal of theoretical work. Label the molecular orbital diagram for XeF (include atom chemical symbol, atomic orbitals, and molecular orbitals) and deduce its ground state electron configuration. Is XeF likely to have a shorter bond length than XeF+? Bond Order XeF XeF+arrow_forward
- 6. Draw the molecular orbital diagram shown to determine which of the following is paramagnetic. B22+ B22+, B2, C22, B22 and N22+ Molecular Orbital Diagram B2 C22- B22- N22+ Which molecule is paramagnetic?arrow_forward3. Put the following species in order of increasing bond length by using molecular orbital diagrams and calculating their bond orders: F2, F2, F2+ Molecular Orbital Diagram F2 F2 F2+ Bond Order Shortest bond: Longest bondarrow_forward3. Put the following species in order of increasing bond length by using molecular orbital diagrams and calculating their bond orders: F2, F2, F2+ Molecular Orbital Diagram F2 F2 F2+ Bond Orderarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305957404/9781305957404_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781259911156/9781259911156_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305577213/9781305577213_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9780078021558/9780078021558_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781305079373/9781305079373_smallCoverImage.gif)
![Text book image](https://www.bartleby.com/isbn_cover_images/9781118431221/9781118431221_smallCoverImage.gif)