Chapter 24, Problem 38A

Interpretation Introduction

Interpretation:

Isotope produces by the alpha decay of uranium-234 is needs to be explained.

Concept introduction:

To keep the radioisotopes stable, both the neutrons and the protons number must be decreased in alpha decay. These powerful nuclei often decay by releasing alpha particles.

Answer to Problem 38A

Isotope which is formed due to the alpha decay of Uranium-234 is Thorium.

Explanation of Solution

Any radioisotope which undergoes alpha decay loses two protons and reduces mass number by 4.

In alpha decay of uranium, uranium-234 produces an element which have two less protons number than Uranium and its mass number four less than Uranium-234. That means it produces Thorium

Therefore, the balanced nuclear equation is

$\text{U}+\text{p}\to \text{T}\text{h}+\text{H}\text{e}$

Hence, the isotope which is formed due to the alpha decay of Uranium-234 is Thorium.

Conclusion

Alpha decay is described as the loss of He nucleus. A He nucleus comprises of 2 protons and 2 neutrons.