Chapter 24, Problem 61A

Interpretation Introduction

Interpretation:

On the basis of figure 24.7 $\text{C}\text{a}$ is radioactive or not to be explained.

Concept introduction:

Radioactive decay is unstable nuclei that lose energy by emitting radiation in a spontaneous process. Until they form stable atoms unstable atoms undergo radioactive decay, often of a dissimilar element.

Answer to Problem 61A

$\text{C}\text{a}$ Isotope has 20 protons and 19 neutrons. $\text{C}\text{a}$ is radioactive.

Explanation of Solution

$\text{C}\text{a}$ Isotope has 20 protons and 19 neutrons. From the number of proton and neutron it gives that neutron to proton ratio is less than 1. From band stability atoms it does not include neutron to proton ratios of less than 1. Thus $\text{C}\text{a}$ is radioactive.

Conclusion

From band stability atoms that have low atomic numbers (less than 20) is most stable nuclei are those with neutron-to-proton ratios of 1:1.