(a)
Interpretation:
The given results are consistent with piperidine has to be shown.
Concept Introduction:
Hofmann Elimination: It is a type of reaction where an
In Hofmann Elimination, a quaternary ammonium halide first treated with moist
(b)
Interpretation:
Two additional molecules with molecular formula
Concept Introduction:
Hofmann Elimination: It is a type of reaction where an
In Hofmann Elimination, a quaternary ammonium halide first treated with moist
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Organic Chemistry
- Write the equilibrium-constant expressions and obtainnumerical values for each constant in. (a) the basic dissociation of aniline, C6H5NH2. (b) the acidic dissociation of hypochlorous acid,HClO. (c) the acidic dissociation of methyl ammoniumhydrochloride, CH3NH3Cl. (d) the basic dissociation of NaNO2. (e) the dissociation of H3AsO3to H3O+and AsO33-. (f) the reaction of C2O42-with H2O to give H2C2O4and OH-. show solutionarrow_forwardHow do triphenylphosphine and borane form a Lewis acid-base adduct? (a) The phosphorus atom in triphenylphosphine is less electronegative than the boron atom in borane and is thus attracted to boron to form the bond. (b) The phosphorus in triphenylphosphine exchanges with the boron from borane. (c) Triphenylphosphine donates the lone pair on its phosphorus to the electron-deficient boron in borane. (d) Triphenylphosphine donates a phenyl ring from its phosphorus to the electron-deficient boron in borane. (e) The phosphorus in triphenylphosphine accepts a proton from the proton-rich borane.arrow_forwardGiven the chemical equation in the synthesis of benzoic acid from toluene and potassium permanganate: C7H8(I) + 2KMnO4(aq) → KC7H5O2 + 2MnO2 (s) + KOH (aq) + H2O (I) KC2H5O2 (aq) + HCl (aq) → C7H8O2 (s) + KCl (aq) MW: C7H8 = 92.14 KMnO4 = 158.03 MnO2 = 86.94 KC7H5O2 = 160.21 C7H8O2 = 122 Density: C7H8 = 0.87 g/mL KMnO4 = 2.7 g/mL KC7H5O2 = 1.5 g/mL C7H8O2 = 1.27 g/mL If 1 mL of toluene and 4 mL of 50% w/v potassium permanganate solution are used to synthesize the benzoic acid in a reflux set-up, calculate the theoretical yield of benzoic acid. Show your complete solution and underline your final answer.arrow_forward
- 1. Write the equilibrium-constant expressions and obtain numerical values for each constant in(a) the basic dissociation of aniline, C6H5NH2 .(b) the acidic dissociation of hypochlorous acid, HClO.(c) the acidic dissociation of methyl ammonium hydrochloride, CH3NH3Cl.(d) the basic dissociation of NaNO2 .(e) the dissociation of H3AsO3 to H3O + and AsO33- 2. The chemicals A and B react as follows to produce C and D: A + B ↔ C + DKe = [C] [D] [A] [B] The equilibrium constant Ke has a value of 0.30. Assume 0.20 mol of A and 0.50 mol of B are dissolved in 1.00 L, and the reaction proceeds. Calculate the concentrations of reactants [A], [B] and products [C], [D] at equilibrium. Using step-by-step processarrow_forwardPropose two additional structural formulas (excluding stereoisomers) for C5H11N that are also consistent with the results obtained by Hofmann.arrow_forward(b) Compound L, C4H9BR undergoes the substitution reaction with ammonia, NH3 to form butan-2-amine. The reaction of compound L with magnesium, Mg in ether produced compound M. The hydrolysis reaction of compound L with water, H2O produced compound N. Compound P is produced when compound N reacts with sodium, Na. Sebatian L, C4H»Br menjalani tindak balas penukargantian dengan ammonia, NH3 untuk menghasilkan butan-2-amina. Tindak balas bagi sebatian L dengan magnesium, Mg dalam ether menghasilkan sebatian M. Tindak balas hidrolisis bagi sebatian L dengan air, H2O menghasilkan sebatian N. Sebatian P dihasilkan apabila sebatian N bertindak balas dengan natrium, Na. (i) Draw the structural formula of compounds L, M, N and P. Lukiskan formula struktur bagi sebatian L, M, N dan P. (ii) Name the type of chemical reaction for the formation of compound N.arrow_forward
- (a) Draw the three isomers of benzenedicarboxylic acid.(b) The isomers have melting points of 210 °C, 343 °C, and 427 °C. Nitration of the isomers at all possible positions was once used to determine their structures. The isomer that melts at 210 °C gives two mononitro isomers. The isomer that melts at 343 °C gives three mononitro isomers. The isomer that melts at 427 °C gives only one mononitro isomer. Show which isomer has which melting point.arrow_forwardDraw a scheme to show how one would separate a mixture of naphthalene and aniline (Hint: aniline is an organic base that reacts with HCl(aq) to form a salt).arrow_forwardThere are eight primary amines with the molecular formula C5H13N . (a) Name and draw a structural formula for each amine. (b) Which of these amines are chiral?arrow_forward
- Given a chemical test to distinguish between:(i) Ethane and ethane(ii) Ethanol and ethanoic acid(iii) Soaps and Detergentsarrow_forwarda) If the pH value of an aqueous solution of trimethylamine [(CH3) 3N] is 10.75, what should be the molarity of this solution? (CH3) 3N + H2O ↔ (CH3) 3NH + + OH-, Kb = 6.3 × 10-5 b) What will be the pH of the solution prepared by dissolving 8.35 g of aniline hydrochloride (C6H5NH3 + Cl-) in 750 mL of 0.215 M aniline (C6H5NH2)? Is this solution an effective buffer? Explain (Kb = 7.4 × 10-10 for aniline, C: 12.0 g / mol, H: 1.0 g / mol, N: 14.0 g / mol, Cl: 35.4 g / mol) .arrow_forwardDraw the structure of the predominant form of CF3CH2OH (pK a = 12.4) at pH = 6.arrow_forward
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning