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Concept explainers
(a)
Interpretation:
Given acid–base reaction should be completed and the name of the hydrochloride salt formed has to be given.
Concept introduction:
According to the explanations by Bronsted-Lowry, if a species loses a proton then it is an acid whereas if a species receives one proton, then it is base.
If a base receives one proton, then the formed species is a conjugate acid whereas an acid lose one proton, then the formed species is a conjugated base.
If nitrogen atom in amine group is attached with four atoms or group of atoms then the compound can be named as the salt of the corresponding amine.
For the naming of the salt, ending of the corresponding amine “-amine (pyridine, aniline)” is replaced by “ammonium (pyridinium, anilinium)” and anion name is given as suffix.
(b)
Interpretation:
Given acid–base reaction should be completed and the name of the hydrochloride salt formed has to be given.
Concept introduction:
According to the explanations by Bronsted-Lowry, if a species loses a proton then it is an acid whereas if a species receives one proton, then it is base.
If a base receives one proton, then the formed species is a conjugate acid whereas an acid lose one proton, then the formed species is a conjugated base.
If nitrogen atom in amine group is attached with four atoms or group of atoms then the compound can be named as the salt of the corresponding amine.
For the naming of the salt, ending of the corresponding amine “-amine (pyridine, aniline)” is replaced by “ammonium (pyridinium, anilinium)” and anion name is given as suffix.
Amines react with strong acid to form a hydrochloride salt.
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Chapter 23 Solutions
Organic Chemistry
- Classify each pair of molecules according to whether or not they can participate in hydrogen bonding with one another. Participate in hydrogen bonding CH3COCH3 and CH3COCH2CH3 H2O and (CH3CH2)2CO CH3COCH3 and CH₂ CHO Answer Bank Do not participate in hydrogen bonding CH3CH2OH and HCHO CH3COCH2CH3 and CH3OHarrow_forwardNonearrow_forwardQ4: Comparing (3S,4S)-3,4-dimethylhexane and (3R,4S)-3,4-dimethylhexane, which one is optically active? Briefly explain.arrow_forward
- Nonearrow_forwardNonearrow_forwardGiven the standard enthalpies of formation for the following substances, determine the reaction enthalpy for the following reaction. 4A (g) + 2B (g) → 2C (g) + 7D (g) AHrxn =?kJ Substance AH in kJ/mol A (g) - 20.42 B (g) + 32.18 C (g) - 72.51 D (g) - 17.87arrow_forward
- Determine ASran for Zn(s) + 2HCl(aq) = ZnCl2(aq) + H2(aq) given the following information: Standard Entropy Values of Various Substance Substance So (J/mol • K) 60.9 Zn(s) HCl(aq) 56.5 130.58 H2(g) Zn2+(aq) -106.5 55.10 CI (aq)arrow_forward3) Catalytic hydrogenation of the compound below produced the expected product. However, a byproduct with molecular formula C10H12O is also formed in small quantities. What is the by product?arrow_forwardWhat is the ΔHorxn of the reaction? NaOH(aq) + HCl(aq) → H2O(l) + NaCl(aq) ΔHorxn 1= ________ kJ/molarrow_forward
- = +92kJ ΔΗ = +170kJ Use the following reactions: 2NH3(9) N2(g) + 3H2(g) → 11/N2(g) + 2H2O (1) → NO2(g) + 2H2(g) Determine the DH° of this reaction: NO2(g) + H2(g) → 2(g) → 2H2O(l) + NH3(9) ΔΗarrow_forwardDetermine the entropy change for the reaction SO2(g) + O2(g) following information: Standard Entropy Values of Various Substance Substance SO2(g) 02(g) SO3(g) So (J/mol K) 248.2 205.0 256.8 → SO3(g) given thearrow_forwardIndicate which one of the following reactions most certainly results in a negative AS sys. O1402(g) + 3NH4NO3 (s) + C10 H22(1) → 3N2(g) + 17H2O(g) + 10CO2(g) ○ CO2(aq) = CO2(g) ○ H₂O(g) = H₂O(s) CaCO3(g) = CaO(s) + CO2(g) O CuSO4.5H2O(s) = CuSO4(s) + 5H2O(g)arrow_forward
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