
Concept explainers
Interpretation:
The
Concept introduction:
Organic compounds are named systematically by using IUPAC rules.
Name of the organic compounds are given according to the number of carbon present in the molecule for example
If any halogens are present in the molecule, the name of the halogens as follows.
Naming the substituted
- (1) Name the parent alkane (long alkyl chain)
- (2) Number the carbon
- (3) Name and number the substituent
If the molecules have the multiple substituents, the compound named as di, tri, tetra, Penta, etc.
If the molecules having functional group, the name of the compound is given below. Numbering should be starts from the functional group of the given molecule.
The given compound is an alcohol
Example is given below
The given compound is an acid (
The amides are derivatives of acids and it is named as the ending of alkane with amide.
For example
If the molecule is ester,
Esters end with “ate”
Example
The given compound is an
The given compound is
The given compound is an

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Chapter 23 Solutions
Chemistry: Atoms First
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- calculate the equilibrium concentration of H2 given that K= 0.017 at a constant temperature for this reaction. The inital concentration of HBr is 0.050 M.2HBr(g) ↔ H2(g) + Br2(g)a) 4.48 x 10-2 M b) 5.17 x 10-3 Mc) 1.03 x 10-2 Md) 1.70 x 10-2 Marrow_forwardtrue or falsegiven these two equilibria with their equilibrium constants:H2(g) + CI2(l) ↔ 2HCI(g) K= 0.006 CI2(l) ↔ CI2(g) K= 0.30The equilibrium contstant for the following reaction is 1.8H2(g) + CI2 ↔ 2HCI(g)arrow_forwardI2(g) + CI2(g) ↔ 2ICIK for this reaction is 81.9. Find the equilibrium concentration of I2 if the inital concentration of I2 and CI2 are 0.010 Marrow_forward
- true or false,the equilibrium constant for this reaction is 0.50.PCI5(g) ↔ PCI3(g) + CI2(g)Based on the above, the equilibrium constant for the following reaction is 0.25.2PCI5(g) ↔. 2PCI3(g) + 2CI2(g)arrow_forwardtrue or false, using the following equilibrium, if carbon dioxide is added the equilibrium will shift toward the productsC(s) + CO2(g) ↔ 2CO(g)arrow_forward2S2O2/3- (aq) + I2 (aq) ---> S4O2/6- (aq) +2I- (aq) Experiment I2 (M) S2O3- (M) Initital Rate (M/s) 1 0.01 0.01 0.0004 2 0.01 0.02 0.0004 3 0.02 0.01 0.0008 Calculate the overall order for this reaction using the table data a) 3b) 0c) 2d) 1arrow_forward
- the decomposition of N2O5 is the first order with a half-life of 1.98 minutes. If the inital concentration of N2O5 is 0.200 M, what is the concentration after 6 minutes?a) 0.612 Mb) 0.035 Mc) 0.024 Md) 0.100 Marrow_forward20.00 mL of 0.150 M HCI is titrated with 0.075 M NaOH. What volume of NaOH is needed?a) 50 mLb) 20 mLc) 40 mLd) 26.66 mLarrow_forward20.00 mL of 0.150 M NaOH is titrated with 37.75 mL of HCI. What is the molarity of the HCI?a) 0.150 Mb) 0.079 Mc) 0.025 Md) 0.050 Marrow_forward
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