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Concept explainers
(a)
Interpretation:
Carbon forms more compound than the other element the reason should be identified.
Concept introduction:
Electronic configuration of carbon is
(a)
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Answer to Problem 23.1QP
Answer
Catenation of the carbon atom (a).
Explanation of Solution
To find: Carbon forms more compound than the other element
Catenation of the carbon atom.
Carbon forms the covalent bond with other atoms or other carbon atoms through catenation and forms longer chain and structures.
(b)
Interpretation:
Carbon forms more compound than the other element the reason should be identified.
Concept introduction:
Electronic configuration of carbon is
(b)
![Check Mark](/static/check-mark.png)
Answer to Problem 23.1QP
Answer
Tetravalency of the carbon atom (b).
Explanation of Solution
To find Tetravalency of the carbon atom
Electronic configuration of carbon is
The outer electronic configuration of the carbon is four electrons that will be participating in the bond formation. Totally carbon will form four covalent bonds with the other atoms or carbon atoms. Moreover size of the carbon atom is small which form more strong covalent bond because of these reasons which make the Carbon forms more compound than the other element.
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Chapter 23 Solutions
Chemistry: Atoms First
- 2. 200 LOD For an unknown compound with a molecular ion of 101 m/z: a. Use the molecular ion to propose at least two molecular formulas. (show your work) b. What is the DU for each of your possible formulas? (show your work) C. Solve the structure and assign each of the following spectra. 8 6 4 2 (ppm) 150 100 50 ō (ppm) 4000 3000 2000 1500 1000 500 HAVENUMBERI-11arrow_forwardComplete the spectroscopy with structurearrow_forwardComplete the spectroscopy with structurearrow_forward
- Given the following concentrations for a system, calculate the value for the reaction quotient: Cl2(g)+ CS2(g) ⇌ CCl4(g)+ S2Cl2(g) Cl2 = 31.1 atm CS2 = 91.2 atm CCl4 = 2.12 atm S2Cl2 = 10.4 atmarrow_forwardMatch each chemical or item with the proper disposal or cleanup mwthod, Not all disposal and cleanup methods will be labeled. Metal sheets C, calcium, choroide solutions part A, damp metal pieces Part B, volumetric flask part A. a.Return to correct lables”drying out breaker. Place used items in the drawer.: Rinse with deionized water, dry as best you can, return to instructor. Return used material to the instructor.: Pour down the sink with planty of running water.: f.Pour into aqueous waste container. g.Places used items in garbage.arrow_forwardWrite the equilibrium constant expression for the following reaction: HNO2(aq) + H2O(l) ⇌ H3O+(aq) + NO2-(aq)arrow_forward
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