To measure signal propagation in a nerve in the arm, the nerve is triggered near the armpit. The peak of the action potential is measured at the elbow and then, 4.0 ms later, 24 cm away from the elbow at the wrist. a. What is the speed of propagation along this nerve? b. A determination of the speed made by measuring the time between the application of a stimulus at the armpit and the peak of an action potential at the elbow or the wrist would be inaccurate. Explain the problem with this approach, and why the noted technique is preferable.
To measure signal propagation in a nerve in the arm, the nerve is triggered near the armpit. The peak of the action potential is measured at the elbow and then, 4.0 ms later, 24 cm away from the elbow at the wrist. a. What is the speed of propagation along this nerve? b. A determination of the speed made by measuring the time between the application of a stimulus at the armpit and the peak of an action potential at the elbow or the wrist would be inaccurate. Explain the problem with this approach, and why the noted technique is preferable.
To measure signal propagation in a nerve in the arm, the nerve is triggered near the armpit. The peak of the action potential is measured at the elbow and then, 4.0 ms later, 24 cm away from the elbow at the wrist.
a. What is the speed of propagation along this nerve?
b. A determination of the speed made by measuring the time between the application of a stimulus at the armpit and the peak of an action potential at the elbow or the wrist would be inaccurate. Explain the problem with this approach, and why the noted technique is preferable.
To measure signal propagation in a nerve in the arm, the nerve is triggered near the armpit. The peak of the action potential is measured at the elbow and then, 4.0 ms later, 24 cm away from the elbow at the wrist.a. What is the speed of propagation along this nerve?b. A determination of the speed made by measuring the time between the application of a stimulus at the armpit and the peak of an action potential at the elbow or the wrist would be inaccurate. Explain the problem with this approach, and why the noted technique is preferable.
B1. There are approximately 20.1 million households that use TVs in the Philippines. On the average, each TV uses 75 W of power and is turned on for 8.0 hours a day. If the electrical energy costs 8.75 PHP per kWh, how much money is spent every day in keeping 20.1 million TVs turned on?a. 105.5 M
b. 206.6 M
c. 307.7 M
d. 408.8 M
B2. Refer to question number 4, find the electrical energy dissipated every day by the 20.1 million households. a. 1.16?106?
b. 2.16?106?
c. 3.16?106?
d. 4.16?106J
4. The circuit contains four parallel plate capacitors, all initially uncharged and with no dielectric material between their plates. A switch is closed to complete the circuit at time t=0, so current begins to flow at that time and we wait enough time for the capacitors to become (very close to) fully charged.
a. What is the equivalent capacitance of this circuit?
b. What is the charge stored on the 125 µF capacitor?
If we now insert a neoprene rubber dielectric into all of the capacitors, how will the answers change?
c. What is the equivalent capacitance of this circuit?
d. What is the charge stored on the 125 µF capacitor?
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