Concepts of Genetics (11th Edition)
11th Edition
ISBN: 9780321948915
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
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Chapter 23, Problem 22ESP
In a cross between a strain of large guinea pigs and a strain of small guinea pigs, the F1 are
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A homozygous strain of corn that produces yellow kernels is crossed with another homozygous strain that produces purple kernels. When the F1 are interbred, 197 of the F2 are yellow and 153 are prurple. Give the genotypes of the yellow and purple F2 and propose a genetic model that explains the inheritance of these kernel colors in corn.
Two pure-breeding parents produced a heterozygous female offspring (AaBb) that was then testcrossed with an aabb male. The offspring produced from the testcross included 50 AaBb, 450 Aabb, 450 aaBb, 50 aabb individuals. Describe how you can tell if these two genes are linked or unlinked (What ratio would you expect to see from the testcross if they were not linked?). What were the genotypes of the original parents that produced the heterozygous female? What is the genetic map distance between the two genes?
You carry out a trihybrid cross (a cross in which the parental plants differ for three characters) between a tall pea plant with round, yellow seeds (TT RR YY) and a short pea plant with wrinkled, green seeds (tt rr yy). The parental plants are homozygous for all of the three characters. They are crossed to produce the F1 generation. Tall, round, and yellow are the dominant traits for each character.
What will be the phenotypes of the F1 generation?
Chapter 23 Solutions
Concepts of Genetics (11th Edition)
Ch. 23 - A homozygous plant with 20-cm-diameter flowers is...Ch. 23 - The following table shows measurements for fiber...Ch. 23 - The following cable gives the percentage of twin...Ch. 23 - Prob. 1CSCh. 23 - Prob. 2CSCh. 23 - Prob. 3CSCh. 23 - HOW DO WE KNOW? In this chapter, we focused on a...Ch. 23 - CONCEPT QUESTION Review the Chapter Concepts list...Ch. 23 - Define the following: (a) polygenic, (b) additive...Ch. 23 - A dark-red strain and a white strain of wheat are...
Ch. 23 - Height in humans depends on the additive action of...Ch. 23 - An inbred strain of plants has a mean height of 24...Ch. 23 - Erma and Harvey were a compatible barnyard pair,...Ch. 23 - In the following table, average differences of...Ch. 23 - What kind of heritability estimates (broad sense...Ch. 23 - List as many human traits as you can that are...Ch. 23 - Corn plants from a test plot are measured, and the...Ch. 23 - The following variances were calculated for two...Ch. 23 - The mean and variance of plant height of two...Ch. 23 - Prob. 14PDQCh. 23 - Prob. 15PDQCh. 23 - In an assessment of learning in Drosophila, flies...Ch. 23 - Prob. 17PDQCh. 23 - Prob. 18PDQCh. 23 - In a population of 100 inbred, genotypically...Ch. 23 - Many traits of economic or medical significance...Ch. 23 - A 3-inch plant was crossed with a 15-inch plant,...Ch. 23 - In a cross between a strain of large guinea pigs...Ch. 23 - Type A1B brachydactyly (short middle phalanges) is...Ch. 23 - In a series of crosses between two true-breeding...Ch. 23 - Students in a genetics laboratory began an...Ch. 23 - Prob. 26ESPCh. 23 - Canine hip dysplasia is a quantitative trait that...Ch. 23 - Floral traits in plants often play key roles in...Ch. 23 - In 1988, Horst Wilkens investigated blind...
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- A researcher crosses mice with brown eyes and long tails, and the F1 progeny were recovered in the following numbers and phenotypic classes: F1: 6 apricot, short : 30 brown, long : 15 brown, short : 9 apricot, long You know the genes encoding these traits are autosomal, completely dominant and assort independently. You want to use a chi-square test to analyse these results. a) Making use of the appropriate genetic convention for naming alleles, give the genotype of the male parent in this cross. b) What is your null hypothesis for the chi-square test? c) Give the expected number of individuals in the "brown, long" class. d) You obtain a value of 3.47 for the chi-square test. What conclusion can you make from the results of the chi-square test? P df 0.995 0.975 0.9 0.5 0.1 0.05* 0.025 0.01 0.005 1 0.000 0.000 0.016 0.455 2.706 3.841 5.024 6.635 7.879 2 0.010 0.051 0.211 1.386 4.605 5.991 7.378 9.210 10.597 0.072 0.216 0.584 2.366 6.251 7.815 9.348 11.345 12.838 4 0.207 0.484 1.064 3.357…arrow_forwardConsider the following pedigree. Solid symbols represent individuals affected by the trait. Assume complete penetrance and non-variable expressivity. II 3 4 III 1 2 3 5 6 a) what is the mode of inheritance of this trait? b) Does the ratio of affected to unaffected offspring in generation III-1 to 1II-4 match the expected ratio for this mode of inheritance? Explain your answer in terms of the expected ratio versus the ratio observed. Give a reason for your answer. No mark is assigned for yes or no)arrow_forwardMultiple crosses were made between true-breeding lines of black and yellow Labrador retrievers. All the F1 progeny were yellow. When these progeny were intercrossed, they produced an F2 consisting of 121 yellow, 9 black and 30 chocolate. What epistatic ratio and what kind of epistasis is approximated in the F2? Propose a biochemical pathway for coat color in Labrador retrievers based on the type of epistasis. Correlate each genotype with the phenotype that would occur in your pathway. Also show the frequency of each genotype. A-B- A-bb aaB- aabbarrow_forward
- We think that dwarfism in river birch might be inherited as a single-locus, simple Mendelain trait. We have taken a pure breeding normal plant and crossed it with a a pure breeding dwarf plant. The resulting plants were self-pollinated with the following results: Normal River Birch 805 Dwarf River Birch 246 Perform a chi square analysis on this data using the following hypothesis: The mode of inheritance for plant height in the river birch is simple Mendelian. Calculate the chi square value without rounding and then round your final answer to three decimal digits and put it in the space provided.arrow_forwardIn an intra-species cross performed in mustard plants of two different species (Brassica juncea and Brassica oleracea), a tall plant (TT) was crossed with a dwarf (tt) variety in each of the two species. The members of the F1 generation were crossed to produce the F2 generation. Of the F2 plants, Brassica juncea had 60 tall and 20 dwarf plants, while Brassica oleracea had 100 tall and 20 dwarf plants. Use chi-square analysis to analyze these results.arrow_forwardFruit flies express both normal wing shape and vestigial wing shape. The pedigree shows the inheritance of the wing-shape trait over two generations. In the pedigree, squares represent males and circles represent females. Shaded symbols represent an individual with normal wing shape. A cross between individual 4 and individual 5 in the pedigree resulted in the data shown in the table. This data results in a chi-square value of 6.45. Female Male Normal 25 39 Vestigial 22 14 Degrees of Freedom p 1 2 0.05 3.84 5.99 0.01 6.64 9.32 Based on the data, which of the following best supports the claim that this trait exhibits an autosomal dominant inheritance pattern? The results of the cross show that there were no heterozygous dominant females. The chi-square value shows that these results are not typical of this type of cross. The results of the cross show that fewer males exhibited the recessive trait than females. The…arrow_forward
- The production of purple pigment in a certain species of flower is dependent upon two gene loci. You cross two purple flowered plants that are heterozygous at each gene locus. The offspring show the following phenotypes: 91 purple and 68 white.a. What is the simplified phenotypic ratio is observed in the offspring? What mode of inheritance is associated with this ratio? b. What is/are the genotype(s) of the purple offspring? What is/are the genotype(s) of the white offspring?arrow_forwardTwo groups of geneticists, in California and in Chile, begin work to develop a linkage map of the medfly. They both independently find that the loci for body color (B = black, b = gray) and eye shape (R = round, r = star) are linked 28 m.u. apart. They send strains to each other and perform crosses; a summary of all their findings is shown here:a. Provide a genetic hypothesis that explains the three sets of testcross results. b. Draw the key chromosomal features of meiosis in the F1 from a cross of the Californian and Chilean lines.arrow_forwardA purple snow pea plant known to be hybrid for three linked genes (a, b, and d) is testcrossed. The progeny phenotypes and frequencies are: +a+ 86 b+d 56 +ad 78 b++ 49 +++ 12 bad 6 ba+ 515 ++d 460 a) Draw the chromosomes of the trihybrid and tester lined mentioned above. b) Give a map of the gene order with distance.arrow_forward
- A variety of opium poppy with lacerate leaves was crossed with a variety that has normal leaves. All the F1 plants had lacerate leaves. Two F1 plants were then interbred to produce the F2. Of the F2 plants, 249 had lacerate leaves and 16 had normal leaves. What are the genotypes of the plants in the P (parental), F1, and F2 generations? How are lacerate leaves determined in the opium poppy? Note: You can use the symbols A and B to represent the two genes involved. (How do we know there are two?)arrow_forwardYou are working with a hypothetical fly and have found color and wing mutants. Preliminary work indicates that the mutant traits are recessive and the associated genes are not sex-linked, but beyond that, you have no information. You first look at 2 genes, each with 2 alleles. "B" or “b" for body color and "W" or "w" for wing surface. The red-body phenotype is dominant to the yellow-body phenotype and smooth wings are dominant to crinkled wings.arrow_forwardIn a cross in Drosophila, a female heterozygous for the autosomallylinked genes a, b, c, d, and e (abcde/ + + + + +) was testcrossedwith a male homozygous for all recessive alleles (abcde/abcde).Even though the distance between each of the loci was at least3 map units, only four phenotypes were recovered, yielding thefollowing data: Phenotype No. of Flies+ + + + + 440a b c d e 460+ + + + e 48a b c d + 52 Total = 1000 Why are many expected crossover phenotypes missing? Can anyof these loci be mapped from the data given here? If so, determinemap distances.arrow_forward
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