Concepts of Genetics (11th Edition)
11th Edition
ISBN: 9780321948915
Author: William S. Klug, Michael R. Cummings, Charlotte A. Spencer, Michael A. Palladino
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Textbook Question
Chapter 23, Problem 21ESP
A 3-inch plant was crossed with a 15-inch plant, and all F1 plants were 9 inches. The F2 plants exhibited a “normal distribution,” with heights of 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, and 15 inches.
- (a) What ratio will constitute the “normal distribution” in the F2?
- (b) What will be the outcome if the F1 plants are testcrossed with plants that are homozygous for all nonadditive alleles?
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A 3-inch plant was crossed with a 15-inch plant, and all F1 plants were 9 inches. The F2 plants exhibited a “normal distribution,” with heights of 3, 4, 5, 6, 7, 8, 9, 10, 11, 12, 13, 14, and 15 inches. (a) What ratio will constitute the “normal distribution” in the F2? (b) What will be the outcome if the F1 plants are testcrossed with plants that are homozygous for all nonadditive alleles?
In a variety of tomato plant ,the leaves maybe pure green,pure white,or variegated (mixture).
a)when 2 variegated plants were crossed,87 offspring were produced,of these 20 were green,46 were variegated and 21 remain died soon after germination.Draw a genetic diagram to explain these results,why did 21 of them died
Assume performing only one cross, which produced 274 flies, which consisted of 193 wild-type flies and 81 white-eyed flies. (a) Based upon this information, what is the most likely genotype of the female parent? (b) How to confirm the above answer with only the result from this one cross?
Chapter 23 Solutions
Concepts of Genetics (11th Edition)
Ch. 23 - A homozygous plant with 20-cm-diameter flowers is...Ch. 23 - The following table shows measurements for fiber...Ch. 23 - The following cable gives the percentage of twin...Ch. 23 - Prob. 1CSCh. 23 - Prob. 2CSCh. 23 - Prob. 3CSCh. 23 - HOW DO WE KNOW? In this chapter, we focused on a...Ch. 23 - CONCEPT QUESTION Review the Chapter Concepts list...Ch. 23 - Define the following: (a) polygenic, (b) additive...Ch. 23 - A dark-red strain and a white strain of wheat are...
Ch. 23 - Height in humans depends on the additive action of...Ch. 23 - An inbred strain of plants has a mean height of 24...Ch. 23 - Erma and Harvey were a compatible barnyard pair,...Ch. 23 - In the following table, average differences of...Ch. 23 - What kind of heritability estimates (broad sense...Ch. 23 - List as many human traits as you can that are...Ch. 23 - Corn plants from a test plot are measured, and the...Ch. 23 - The following variances were calculated for two...Ch. 23 - The mean and variance of plant height of two...Ch. 23 - Prob. 14PDQCh. 23 - Prob. 15PDQCh. 23 - In an assessment of learning in Drosophila, flies...Ch. 23 - Prob. 17PDQCh. 23 - Prob. 18PDQCh. 23 - In a population of 100 inbred, genotypically...Ch. 23 - Many traits of economic or medical significance...Ch. 23 - A 3-inch plant was crossed with a 15-inch plant,...Ch. 23 - In a cross between a strain of large guinea pigs...Ch. 23 - Type A1B brachydactyly (short middle phalanges) is...Ch. 23 - In a series of crosses between two true-breeding...Ch. 23 - Students in a genetics laboratory began an...Ch. 23 - Prob. 26ESPCh. 23 - Canine hip dysplasia is a quantitative trait that...Ch. 23 - Floral traits in plants often play key roles in...Ch. 23 - In 1988, Horst Wilkens investigated blind...
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, biology and related others by exploring similar questions and additional content below.Similar questions
- Given the karyotype shown at right, is this a male or a female? Normal or abnormal? What would the phenotype of this individual be?arrow_forwardFigure 8.10 In pea plants, purple flowers (P) are dominant to white (p), and yellow peas (Y) are dominant to green (y). What are the possible genotypes and phenotypes for a cross between PpYY and ppYy pea plants? How many squares would you need to complete a Punnett square analysis of this cross?arrow_forwardTwo pure-breeding lines of petunia plants are crossed. Line 1 plants grow to a height of 54 cm, and Line 2 plants grow to a height of 18 cm. Petunia plant height is controlled by three genes, A, B and C. Line 1 has the genotype A₁A₁B₁B₁C₁C₁, and line 2 has the genotype A2A2B₂B₂C₂C₂. Assume that genotype alone determines plant height under ideal growth conditions and that the alleles of the three genes are additive. If the F1 plants are self crossed, what is the expected proportion of F2 plants with the genotype A₁A₁B₁B₁C₁C₁ 1/8 1/32 1/16 1/4 1/64arrow_forward
- 1)se; 12 cM 2)h; 12 cM 3)g; 8 cM 4)se; 8 cMarrow_forwardYellow guinea pigs crossed with white ones always produce cream-colored offspring. Two cream guinea pigs, when crossed, produce yellow, cream, and white offspring in the ratio of 1 yellow : 2 cream : 1 white. What principle of genetics is involved in this cross? (1 point) 2. The shape of radishes may be long, round, or oval. The following results were obtained in the different possible crosses: a. long x oval gave ½ long and ½ oval b. oval x round gave ½ oval and ½ round c. long x round gave all oval d. oval x oval gave ¼ long, ½ oval, and ¼ round Explain these results. Hint: Show genotypes of each cross) (2 points). a. b. c. d. 3. In human blood types, what are the genotypes of the following parents? (2 points). Phenotypes of ParentsPhenotypes of OffspringGenotypes of parents ABABO A x AB½ 0½ 0_______ x _______ A x AB½ ¼¼0_______ x _______ A x A¾00¼_______ x _______ A x O½00½_______…arrow_forwardtype P = n! (p)* (q)"* х! (n - х)! Practice Problem: You cross a true-breeding pea plant with red flowers to a true-breeding pea plant with white flowers. All of your offspring have red flowers. Which gene is dominant? Why? What is the genotype of your offspring? You then cross the offspring to each other. What ratio do you expect? Why? You count 1000 plants and look at their flowers. Your results are as follows: 740 red 260 white Does this follow a simple Mendelian inheritance pattern? Why or why not? DADT 2 MEA SUDI ND D LUT IONSarrow_forward
- The A locus and the D locus are so tightly linked that norecombination is ever observed between them. If Ad/Ad is crossed with aD/aD and the F1 is intercrossed,what phenotypes will be seen in the F2 and in whatproportions?arrow_forwardA series of three-point testcrosses is made to determine the genetic map order of seven linked allele pairs: A/a, B/b, G/g, H/h, Q/q, R/r, and Y/y.From each cross between a triply heterozygous parent listed below, two recombinant classes were noticed as the least frequent among all 8 progeny classes, and are listed at the right in the table. A. For each testcross write the genotype of the F1 heterozygous parent. F1 Parental Phenotype Least frequent F2 Phenotype 1.AHB&ahb AHb & ahB 2.RYh&ryH RYH & ryh 3.BhY&bHy Bhy & bHY 4.qYB&Qyb qYb & QyB 5.AbQ&aBq Abq & aBQ 6.ghR&GHr ghr & GHR B. Write the unified map order of these genes, showing your reasoning.arrow_forwardA purple flowering, smooth seed dihybrid plant (genotype PpSs) is test crossed with a white flowering, wrinkled seed plant (genotype ppss). These produce progeny in the following numbers of four phenotypes: 24:76:74:26 (purple flower + smooth seed coat: purple flower + wrinkled seed coat: white flower + smooth seed coat: white flower + wrinkled seed coat). a) What is the genotype of the original dihybrid plant? Specify which alleles are on each chromosome of the purple flowering, smooth seed plant (i.e. AB/ab or Ab/aB). b) How many map units separate the colour and seed coat genes? Show your calculations.arrow_forward
- A cross was performed using Drosophila melanogaster involving a female known to be heterozygous for both ebony body and sepia eyes and a male known to be homozygous wild type male. The resulting progeny were allowed to mate with one another to produce the data set. Three repetitions of the experiment were conducted. The following data were produced from the crosses. Test these data to determine if they are significantly different from the expected phenotypic ratio. Use the 5% level of significance. Your answer should include the hypothesized cross in genotypes, the Chi-squared value, the critical value and whether you reject or do not reject for each experiment. Wild eye Wild body – 112, Wild eye Ebony body – 40, Sepia eye Wild body – 35, Sepia eye Ebony body – 11arrow_forwardNicotiana glutinosa (2 n = 24) and N. tabacum (2 n = 48) are two closely related plants that can be intercrossed, but the F1 hybrid plants that result are usually sterile. In 1925, Roy Clausen and Thomas Goodspeed crossed N. glutinosa and N. tabacum and obtained one fertile F1 plant . They were able to self-pollinate the flowers of this plant to produce an F2 generation. Surprisingly, the F2 plants were fully fertile and produced viable seeds. When Clausen and Goodspeed examined the chromosomes of the F2 plants, they observed 36 pairs of chromosomes in metaphase I and 36 individual chromosomes in metaphase II. Explain the origin of the F2 plants obtained by Clausen and Goodspeed and the numbers of chromosomes observed.arrow_forwardTable 1: F1 ebony flies - 0 F1 non-ebony flies - 560 F1 stubble flies - 560 F1 non-stubble flies - 0 The researcher collects and crosses male and female flies from the F1 generation. In the resulting offspring, F2, there are both stubble and ebony flies. Draw a Punnett Square to illustrate the F1 cross for the stubbly phenotype showing the individual gametes of each parent and the combination in the resulting offspring.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Human Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage LearningBiology (MindTap Course List)BiologyISBN:9781337392938Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. BergPublisher:Cengage LearningConcepts of BiologyBiologyISBN:9781938168116Author:Samantha Fowler, Rebecca Roush, James WisePublisher:OpenStax College
Human Heredity: Principles and Issues (MindTap Co...
Biology
ISBN:9781305251052
Author:Michael Cummings
Publisher:Cengage Learning
Biology (MindTap Course List)
Biology
ISBN:9781337392938
Author:Eldra Solomon, Charles Martin, Diana W. Martin, Linda R. Berg
Publisher:Cengage Learning
Concepts of Biology
Biology
ISBN:9781938168116
Author:Samantha Fowler, Rebecca Roush, James Wise
Publisher:OpenStax College
How to solve genetics probability problems; Author: Shomu's Biology;https://www.youtube.com/watch?v=R0yjfb1ooUs;License: Standard YouTube License, CC-BY
Beyond Mendelian Genetics: Complex Patterns of Inheritance; Author: Professor Dave Explains;https://www.youtube.com/watch?v=-EmvmBuK-B8;License: Standard YouTube License, CC-BY