Concept explainers
(a)
To find: The number of negative zeros of
(a)
Answer to Problem 116E
Exactly one negative zeros
Explanation of Solution
Given: A graph of
For negative zeros to check number of sign changes in
So, here one time sign change.
Thus, exactly one real negative zeros.
(b)
To find: The number of positive zeros of
(b)
Answer to Problem 116E
Exactly 4, 2 and 0 positive zeros
Explanation of Solution
Given: A graph of
For positive zeros to check number of sign changes in
Now see number of times sign changes.
So, here four time sign change.
Thus, exactly four real positive zeros or less than four even zeros.
Number of positive real zeros 4, 2 and 0 possible zeros.
The degree of polynomial is 5 (odd) and leading coefficient positive.
As
(c)
To find: The possible rational zero of f .
(c)
Answer to Problem 116E
Explanation of Solution
Given: A graph of
The possible rational zeros are
Thus,
(d)
To check:
(d)
Answer to Problem 116E
Explanation of Solution
Given: A graph of
First check the factor of
Thus,
It is lower bound.
Chapter 2 Solutions
Precalculus with Limits: A Graphing Approach
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