Chemistry & Chemical Reactivity
9th Edition
ISBN: 9781133949640
Author: John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher: Cengage Learning
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Textbook Question
Chapter 22, Problem 55GQ
Give a systematic name or the formula for the following:
(a) (NH4)2[CuCl4]
(b) tetraaquadichlorochromium(III) chloride
(c) aquabis(ethylenediamine) thiocyanatocobalt(III) nitrate
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Learning Goal:
This question reviews the format for writing an element's written symbol. Recall that written symbols have a particular format. Written symbols use a form like this:
35 Cl
17
In this form the mass number, 35, is a stacked superscript. The atomic number, 17, is a stacked subscript. "CI" is the chemical symbol for the element chlorine. A general way to show this form is:
It is also correct to write symbols by leaving off the atomic number, as in the following form:
atomic number
mass number Symbol
35 Cl or
mass number Symbol
This is because if you write the element symbol, such as Cl, you know the atomic number is 17 from that symbol. Remember that the atomic number, or number of protons in the nucleus, is what defines the element. Thus, if 17 protons
are in the nucleus, the element can only be chlorine. Sometimes you will only see 35 C1, where the atomic number is not written.
Watch this video to review the format for written symbols.
In the following table each column…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
need help please and thanks dont understand only need help with C-F
Learning Goal:
As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT.
The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7).
Part A - Difference in binding free eenergies
Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol.
The margin of error is 2%.
Part B - Compare difference in free energy to the thermal…
Chapter 22 Solutions
Chemistry & Chemical Reactivity
Ch. 22.1 - Prob. 1RCCh. 22.2 - Prob. 1QCh. 22.2 - 2. Describe the unit cell of austenite.
Ch. 22.2 - Prob. 3QCh. 22.2 - Prob. 1RCCh. 22.2 - Prob. 2RCCh. 22.3 - (a) What is the formula of a complex ion composed...Ch. 22.3 - (a) Determine the metals oxidation number and...Ch. 22.3 - Name the following coordination compounds. (a)...Ch. 22.3 - Prob. 1RC
Ch. 22.3 - 2. What is the oxidation number of the metal in...Ch. 22.3 - Prob. 3RCCh. 22.3 - Prob. 4RCCh. 22.4 - What types of isomers are possible for the...Ch. 22.4 - Prob. 1RCCh. 22.4 - Prob. 2RCCh. 22.4 - Prob. 3RCCh. 22.4 - Prob. 4RCCh. 22.4 - Prob. 1QCh. 22.5 - Prob. 1CYUCh. 22.5 - Prob. 1RCCh. 22.5 - Prob. 2RCCh. 22.6 - Prob. 1QCh. 22.6 - Prob. 2QCh. 22.6 - Prob. 3QCh. 22.6 - Prob. 4QCh. 22.6 - Prob. 1CYUCh. 22.6 - Prob. 1RCCh. 22.6 - How are the d electrons of Pt distributed in a...Ch. 22.6 - What are the electron configurations for Nd and...Ch. 22.6 - Prob. 3CSCh. 22.6 - Prob. 4CSCh. 22.6 - Prob. 5CSCh. 22 - Prob. 1PSCh. 22 - Prob. 2PSCh. 22 - Identify a cation of a first series transition...Ch. 22 - Match up the isoelectronic ions on the following...Ch. 22 - Prob. 5PSCh. 22 - Prob. 6PSCh. 22 - Which of the following ligands is expected to be...Ch. 22 - One of the following nitrogen compounds or ions is...Ch. 22 - Prob. 9PSCh. 22 - Prob. 10PSCh. 22 - Prob. 11PSCh. 22 - Prob. 12PSCh. 22 - Prob. 13PSCh. 22 - Prob. 14PSCh. 22 - Prob. 15PSCh. 22 - Prob. 16PSCh. 22 - Give the name or formula for each ion or compound,...Ch. 22 - Prob. 18PSCh. 22 - Prob. 19PSCh. 22 - Prob. 20PSCh. 22 - Prob. 21PSCh. 22 - Prob. 22PSCh. 22 - Prob. 23PSCh. 22 - Prob. 24PSCh. 22 - Prob. 25PSCh. 22 - Prob. 26PSCh. 22 - Prob. 27PSCh. 22 - Prob. 28PSCh. 22 - Prob. 29PSCh. 22 - Prob. 30PSCh. 22 - In water, the titanium(III) ion, [Ti(H2O)6]3+, has...Ch. 22 - Prob. 32PSCh. 22 - Prob. 33GQCh. 22 - Prob. 34GQCh. 22 - How many unpaired electrons are expected for...Ch. 22 - Prob. 36GQCh. 22 - Which of the following complex ions is (are)...Ch. 22 - Prob. 38GQCh. 22 - How many geometric isomers are possible for the...Ch. 22 - For a tetrahedral complex of a metal in the first...Ch. 22 - Prob. 41GQCh. 22 - Prob. 42GQCh. 22 - Prob. 43GQCh. 22 - A platinum-containing compound, known as Magnuss...Ch. 22 - Prob. 45GQCh. 22 - Prob. 46GQCh. 22 - Prob. 47GQCh. 22 - How many geometric isomers of the complex ion...Ch. 22 - Prob. 49GQCh. 22 - Prob. 50GQCh. 22 - Prob. 51GQCh. 22 - The square-planar complex Pt(en)Cl2 has chloride...Ch. 22 - The complex [Mn(H2O)6]2+ has five unpaired...Ch. 22 - Experiments show that K4[Cr(CN)6] is paramagnetic...Ch. 22 - Give a systematic name or the formula for the...Ch. 22 - When CrCI3 dissolves in water, three different...Ch. 22 - Prob. 57GQCh. 22 - The glycinate ion, H2NCH2CO2, formed by...Ch. 22 - Prob. 59GQCh. 22 - Nickel and palladium both form complexes of the...Ch. 22 - The transition metals form a class of compounds...Ch. 22 - Cerium, as noted in Applying Chemical Principles:...Ch. 22 - Prob. 64GQCh. 22 - Two different coordination compounds containing...Ch. 22 - Prob. 71SCQCh. 22 - Prob. 69SCQCh. 22 - Prob. 70SCQ
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- Please correct answer and don't used hand raitingarrow_forwardneed help please and thanks dont understand a-b Learning Goal: As discussed during the lecture, the enzyme HIV-1 reverse transcriptae (HIV-RT) plays a significant role for the HIV virus and is an important drug target. Assume a concentration [E] of 2.00 µM (i.e. 2.00 x 10-6 mol/l) for HIV-RT. Two potential drug molecules, D1 and D2, were identified, which form stable complexes with the HIV-RT. The dissociation constant of the complex ED1 formed by HIV-RT and the drug D1 is 1.00 nM (i.e. 1.00 x 10-9). The dissociation constant of the complex ED2 formed by HIV-RT and the drug D2 is 100 nM (i.e. 1.00 x 10-7). Part A - Difference in binding free eenergies Compute the difference in binding free energy (at a physiological temperature T=310 K) for the complexes. Provide the difference as a positive numerical expression with three significant figures in kJ/mol. The margin of error is 2%. Part B - Compare difference in free energy to the thermal energy Divide the…arrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- Please correct answer and don't used hand raitingarrow_forwardCan you tell me if my answers are correctarrow_forwardBunsenite (NiO) crystallizes like common salt (NaCl), with a lattice parameter a = 4.177 Å. A sample of this mineral that has Schottky defects that are not supposed to decrease the volume of the material has a density of 6.67 g/cm3. What percentage of NiO molecules is missing? (Data: atomic weight of Ni: 58.7; atomic weight of O: 16).arrow_forward
- A sample of aluminum (face-centered cubic - FCC) has a density of 2.695 mg/m3 and a lattice parameter of 4.04958 Å. Calculate the fraction of vacancies in the structure. (Atomic weight of aluminum: 26.981).arrow_forwardPlease correct answer and don't used hand raitingarrow_forwardPlease correct answer and don't used hand raitingarrow_forward
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