Organic Chemistry
Organic Chemistry
8th Edition
ISBN: 9781305580350
Author: William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher: Cengage Learning
Question
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Chapter 22, Problem 22.8P
Interpretation Introduction

Interpretation:

Reason for the preferential of nitration of pyridine at 3rd position has to be given and also resonance contributors for the intermediate formed by attack of NO2+ at the 2, 3, 4 positions of the conjugate acid of pyridine has to be given.

Expert Solution & Answer
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Explanation of Solution

Pyridine is a base, so in the presence of acid it will be protonated.  For nitration at the 3rd position, the additional positive charge is delocalized on three carbon atoms of the pyridine ring.  In this case, none of the resonance structures has a +2 charge on the same atom.

Organic Chemistry, Chapter 22, Problem 22.8P , additional homework tip  1

For nitration at the 2nd position or 4th position, the additional positive charge on the cation intermediate is also delocalized on three atoms of the pyridine ring, but one of the resonance structure has a +2 charge on nitrogen atom.  This situation is less stable than that happens for nitration at the 3rd position.

Organic Chemistry, Chapter 22, Problem 22.8P , additional homework tip  2

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Chapter 22 Solutions

Organic Chemistry

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