Chapter 22, Problem 22.66QP

Interpretation Introduction

Interpretation:

The value of $\Delta$ for transition of electrons in $d^1$ system when $\lambda \text{ = 680 nm}$ has to be calculated.

Concept Introduction:

When ligands approach the metal ion the degeneracy in d-orbitals of the metal ion is destroyed and they split into two different energy levels. In case of tetrahedral complex, the $d_{x^2-y^2}{d}_{z^2}$ are occupy lower energy level and the $d_{xy},d_{xz},d_{yz}$ occupy higher energy level.  The energy gap between these two set of orbitals is termed as crystal field splitting energy.

The energy can be denoted by $\Delta$ and it is calculated using the formula,

$\begin{array}{l}\Delta =\text{h}\nu \\ \text{= }\frac{hc}{\lambda }\end{array}$

Where,

$\begin{array}{l}h=\text{Planck's constant}\\ \text{c}\text{= velocity of light}\\ \nu \text{= frequency}\\ \lambda \text{= wavelength }\end{array}$