![Physical Chemistry](https://www.bartleby.com/isbn_cover_images/9781133958437/9781133958437_largeCoverImage.gif)
Physical Chemistry
2nd Edition
ISBN: 9781133958437
Author: Ball, David W. (david Warren), BAER, Tomas
Publisher: Wadsworth Cengage Learning,
expand_more
expand_more
format_list_bulleted
Question
Chapter 22, Problem 22.16E
Interpretation Introduction
Interpretation:
The reason as to why the same expression is not obtained when the Laplace-Young equation is derived in a different and incorrect way by writing the area of a sphere in terms of volume and then evaluating
Concept introduction:
Laplace-Young equation is a fundamental equation for the behavior of an interface. This equation relates the pressure difference on either side of an interface with the surface tension and the area of the liquid changes with volume. The Laplace-Young equation is shown below.
Expert Solution & Answer
![Check Mark](/static/check-mark.png)
Trending nowThis is a popular solution!
![Blurred answer](/static/blurred-answer.jpg)
Students have asked these similar questions
Q6. (a)The vander waals equation is used to describe the behaviour
of real gases but still not so useful in many industrial
applications. Explain why?(3)
(b)In kinetic molecular theory of gases it is assumed that
The molecules of the gases occupy negligible volume as compared
to the total volume of the gas' which factor can be actually
described by this postulate?(2)
The energy of the van der Waals bond, which is responsible for a number of the characteristics of water, is about 0.50 eV. (a) At what temperature would the average translational kinetic energy of water molecules be equal to this energy? (b) At that temperature, would water be liquid or gas? Under ordinary everyday conditions, do van der Waals forces play a role in the behavior of water?
1.3 mole of helium gas at a temperature of 276 K is confined to a cubical container whose sides are 12 cm long.Find the mean summed kinetic energy of ALL the atoms in the container in [J].
Chapter 22 Solutions
Physical Chemistry
Ch. 22 - Using the explanation of unbalanced forces as the...Ch. 22 - Show that the right side of equation 22.1 has...Ch. 22 - The text claims that surface tension varies with...Ch. 22 - Prob. 22.4ECh. 22 - Prob. 22.5ECh. 22 - Prob. 22.6ECh. 22 - Prob. 22.7ECh. 22 - Equation 22.6 defines surface tension in terms of...Ch. 22 - Prob. 22.9ECh. 22 - Prob. 22.10E
Ch. 22 - Prob. 22.11ECh. 22 - Prob. 22.12ECh. 22 - Prob. 22.13ECh. 22 - Prob. 22.14ECh. 22 - Prob. 22.15ECh. 22 - Prob. 22.16ECh. 22 - Prob. 22.17ECh. 22 - Prob. 22.18ECh. 22 - Prob. 22.19ECh. 22 - Determine the pressure difference on a droplet of...Ch. 22 - Prob. 22.21ECh. 22 - Prob. 22.22ECh. 22 - Prob. 22.23ECh. 22 - Prob. 22.24ECh. 22 - Prob. 22.25ECh. 22 - Prob. 22.26ECh. 22 - Prob. 22.27ECh. 22 - The Young-Dupr equation, equation 22.16, is...Ch. 22 - Why are capillary rises and depressions not seen...Ch. 22 - Prob. 22.30ECh. 22 - Prob. 22.31ECh. 22 - Prob. 22.32ECh. 22 - Prob. 22.33ECh. 22 - Prob. 22.34ECh. 22 - Prob. 22.35ECh. 22 - Prob. 22.36ECh. 22 - Prob. 22.37ECh. 22 - Prob. 22.38ECh. 22 - A china cup breaks when the ionic or covalent...Ch. 22 - Satellites in space often suffer from vacuum...Ch. 22 - Prob. 22.41ECh. 22 - Prob. 22.42ECh. 22 - Prob. 22.43ECh. 22 - Are the following processes examples of...Ch. 22 - Prob. 22.45ECh. 22 - Early attempts to coat metals with Teflon, poly...Ch. 22 - Prob. 22.47ECh. 22 - Prob. 22.48ECh. 22 - Prob. 22.49E
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Why is nitrogen a good choice for the study of ideal gas behavior around room temperature?arrow_forward(Q31) Given that a sample of krypton gas effuses in 22.7 minutes, how long (in minutes) will it take an equal volume of oxygen gas in the same apparatus at the same temperature and pressure to effuse? (Report to one decimal place)arrow_forwardThis relationship is known as Graham’s Law of Effusion. Since both gases are at the same temperature, they must have the same average kinetic energy (½ mv2), where m is mass and v is velocity (like speed). Since both gases have the same average kinetic energy, you can state that ½ mLvL2 = ½ mHvH2. Multiplying both sides by 2 gives you mLvL2 = mHvH2. Rearranging the equation to get both masses on the same side of the equation will give you mL/mH = VH2/VL2. In 3a and 3b, you probably noticed that the heavy gas particles took twice as long to diffuse as the light gas particles. This means that the light gas particles are moving twice as fast, VH/VL = ½. Therefore, VH2/VL2 = ¼. If the light gas was Ne, what would be a reasonable identity for the heavy gas? Explain.arrow_forward
- To prevent tank rupture during deep-space travel, an engineering team is studying the effect of temperature on gases confined to small volumes. What is the pressure of 2.00 molmol of gas DD measured at 251 ∘C∘C in a 1.75-LL container assuming real behavior?arrow_forwardTorricelli, who invented the barometer, used mercury in its construction because mercury has a very high density, which makes it possible to make a more compact barometer than one based on a less dense fluid. Calculate the density of mercury using the observation that the column of mercury is 760 mm high when the atmospheric pressure is 1.01 × 105 Pa. Assume the tube containing the mercury is a cylinder with a constant cross-sectional area.arrow_forwardP1C.4 Calculate the volume occupied by 1.00 mol N2 using the van der Waals equation expanded into the form of a virial expansion at (a) its critical temperature, (b) its Boyle temperature. Assume that the pressure is 10 atm throughout. At what temperature is the behaviour of the gas closest to that of a perfect gas? Use the following data: Tc = 126.3 K, TB = 327.2 K,a = 1.390 dm6 atm mol−2, b = 0.0391 dm3 mol−1.arrow_forward
- A closed-ended manometer is filled with gas. The ∆h of the column of Hg in the manometer is3.56 cm. What is the pressure of gas in the manometer (in atm)?arrow_forwardGay-Lussac’s Law The temperature of a sample of gas in a steel tank at 30.0 kPa is increasedfrom –100.0 ̊ to 1.00 x 103 ̊C to 25.0 ̊. What is the final pressure inside the tank?arrow_forwardG.319.arrow_forward
- Methane CH4 is a gas at room temperature. What is its root mean square velocityarrow_forwardTo prevent tank rupture during deep-space travel, an engineering team is studying the effect of temperature on gases confined to small volumes. What is the pressure of 2.00 molmol of gas DD measured at 251 ∘C∘C in a 1.75-LL container assuming ideal behavior?arrow_forward(a) Using the Lennard-Jones parameters, determine the van der Waals radius for xenon. (ɛ and o for xenon are 1.77 kJ•mol-1 and 4.10 Å, respectively.) 4.0 (b) Use this radius to determine the fraction of the volume occupied by 1.22 mol of xenon at 25°C and 1.00 atm. 4.0 Supporting Materialsarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Physical ChemistryChemistryISBN:9781133958437Author:Ball, David W. (david Warren), BAER, TomasPublisher:Wadsworth Cengage Learning,Chemistry for Engineering StudentsChemistryISBN:9781337398909Author:Lawrence S. Brown, Tom HolmePublisher:Cengage Learning
![Text book image](https://www.bartleby.com/isbn_cover_images/9781133958437/9781133958437_smallCoverImage.gif)
Physical Chemistry
Chemistry
ISBN:9781133958437
Author:Ball, David W. (david Warren), BAER, Tomas
Publisher:Wadsworth Cengage Learning,
![Text book image](https://www.bartleby.com/isbn_cover_images/9781337398909/9781337398909_smallCoverImage.gif)
Chemistry for Engineering Students
Chemistry
ISBN:9781337398909
Author:Lawrence S. Brown, Tom Holme
Publisher:Cengage Learning
DISTINCTION BETWEEN ADSORPTION AND ABSORPTION; Author: 7activestudio;https://www.youtube.com/watch?v=vbWRuSk-BhE;License: Standard YouTube License, CC-BY
Difference Between Absorption and Adsorption - Surface Chemistry - Chemistry Class 11; Author: Ekeeda;https://www.youtube.com/watch?v=e7Ql2ZElgc0;License: Standard Youtube License