Physical Chemistry
2nd Edition
ISBN: 9781133958437
Author: Ball, David W. (david Warren), BAER, Tomas
Publisher: Wadsworth Cengage Learning,
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Chapter 22, Problem 22.15E
Interpretation Introduction
Interpretation:
The explanation for the fact that the equation for the internal energy of the system does not break the forest law of
Concept introduction:
The internal energy of the system is defined as the total energy of the system. It is the sum of the kinetic and potential energy of each particle present in the system. The change on the internal energy of the system is given by the expression as shown below.
The change in the internal energy of an isolated system is zero.
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There is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS).
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A mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C.
H₂O(g) + C₁₂O(g) = 2 HOCl(g)
K = 0.0900 at 25°C
с
Calculate the equilibrium concentrations of each gas at 25 °C.
[H₂O]=
[C₁₂O]=
[HOCI]=
M
Σ
M
What units (if any) does the response factor (K) have? Does the response factor (K) depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)?
Chapter 22 Solutions
Physical Chemistry
Ch. 22 - Using the explanation of unbalanced forces as the...Ch. 22 - Show that the right side of equation 22.1 has...Ch. 22 - The text claims that surface tension varies with...Ch. 22 - Prob. 22.4ECh. 22 - Prob. 22.5ECh. 22 - Prob. 22.6ECh. 22 - Prob. 22.7ECh. 22 - Equation 22.6 defines surface tension in terms of...Ch. 22 - Prob. 22.9ECh. 22 - Prob. 22.10E
Ch. 22 - Prob. 22.11ECh. 22 - Prob. 22.12ECh. 22 - Prob. 22.13ECh. 22 - Prob. 22.14ECh. 22 - Prob. 22.15ECh. 22 - Prob. 22.16ECh. 22 - Prob. 22.17ECh. 22 - Prob. 22.18ECh. 22 - Prob. 22.19ECh. 22 - Determine the pressure difference on a droplet of...Ch. 22 - Prob. 22.21ECh. 22 - Prob. 22.22ECh. 22 - Prob. 22.23ECh. 22 - Prob. 22.24ECh. 22 - Prob. 22.25ECh. 22 - Prob. 22.26ECh. 22 - Prob. 22.27ECh. 22 - The Young-Dupr equation, equation 22.16, is...Ch. 22 - Why are capillary rises and depressions not seen...Ch. 22 - Prob. 22.30ECh. 22 - Prob. 22.31ECh. 22 - Prob. 22.32ECh. 22 - Prob. 22.33ECh. 22 - Prob. 22.34ECh. 22 - Prob. 22.35ECh. 22 - Prob. 22.36ECh. 22 - Prob. 22.37ECh. 22 - Prob. 22.38ECh. 22 - A china cup breaks when the ionic or covalent...Ch. 22 - Satellites in space often suffer from vacuum...Ch. 22 - Prob. 22.41ECh. 22 - Prob. 22.42ECh. 22 - Prob. 22.43ECh. 22 - Are the following processes examples of...Ch. 22 - Prob. 22.45ECh. 22 - Early attempts to coat metals with Teflon, poly...Ch. 22 - Prob. 22.47ECh. 22 - Prob. 22.48ECh. 22 - Prob. 22.49E
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