General, Organic, and Biological Chemistry - 4th edition
4th Edition
ISBN: 9781259883989
Author: by Janice Smith
Publisher: McGraw-Hill Education
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Question
Chapter 21, Problem 83P
Interpretation Introduction
Interpretation:
The non-competitive inhibition process needs to be explained, using given representation for an enzyme, inhibitor and substrate.
Concept introduction:
Non-competitive inhibition is also an enzyme inhibition. In this process the enzyme binds to the enzyme but not to the active site which changes the enzyme's shape. Then the substrate can no longer be able to recognize the active site of the enzyme.
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Chapter 21 Solutions
General, Organic, and Biological Chemistry - 4th edition
Ch. 21.2 - In addition to the amino and carboxyl groups, what...Ch. 21.2 - Draw both enantiomers of each amino acid in...Ch. 21.2 - Which of the following amino acids is naturally...Ch. 21.3 - Draw the structure of the amino acid valine at...Ch. 21.3 - Identify the amino acid shown with all uncharged...Ch. 21.4 - Identify the N-terminal and C-terminal amino acid...Ch. 21.4 - Prob. 21.4PCh. 21.4 - Prob. 21.4PPCh. 21.4 - Prob. 21.5PCh. 21.4 - Prob. 21.5PP
Ch. 21.4 - Prob. 21.6PPCh. 21.5 - Prob. 21.6PCh. 21.6 - Prob. 21.7PCh. 21.6 - Prob. 21.8PCh. 21.6 - Prob. 21.9PCh. 21.7 - Why is hemoglobin more water soluble than ...Ch. 21.8 - Prob. 21.7PPCh. 21.8 - Prob. 21.11PCh. 21.9 - Prob. 21.8PPCh. 21.9 - Prob. 21.12PCh. 21.9 - Prob. 21.9PPCh. 21.9 - Prob. 21.13PCh. 21.10 - Prob. 21.14PCh. 21.10 - Prob. 21.15PCh. 21.10 - Prob. 21.16PCh. 21.10 - Prob. 21.17PCh. 21.10 - The nerve gas sarin acts as a poison by covalently...Ch. 21.10 - Prob. 21.19PCh. 21.10 - Explain why the proteins involved in blood...Ch. 21 - The amino acid alanine is a solid at room...Ch. 21 - Why is phenylalanine water soluble but...Ch. 21 - Draw the structure of a naturally occurring amino...Ch. 21 - Draw the structure of a naturally occurring amino...Ch. 21 - For each amino acid: [1] draw the L enantiomer in...Ch. 21 - For each amino acid: [1] draw the L enantiomer in...Ch. 21 - Draw both enantiomers of each amino acid and label...Ch. 21 - Which of the following Fischer projections...Ch. 21 - For each amino acid: [1] give the name; [2] give...Ch. 21 - For each amino acid: [1] give the name; [2] give...Ch. 21 - (a) Identify the amino acid shown with all...Ch. 21 - Prob. 32PCh. 21 - Prob. 33PCh. 21 - Draw the structure of the neutral, positively...Ch. 21 - Locate the peptide bond in the dipeptide shown in...Ch. 21 - Label the N-terminal and C-terminal amino acids in...Ch. 21 - Melittin, the principal toxin of bee venom,...Ch. 21 - Cobratoxin is a neurotoxin found in the venom of...Ch. 21 - (a) Draw the structure of the two possible...Ch. 21 - (a) Draw the structure of the two possible...Ch. 21 - For each tripeptide: [1] draw the structure of the...Ch. 21 - For each tripeptide: [1] draw the structure of the...Ch. 21 - Prob. 43PCh. 21 - For each tripeptide: [1] identify the amino acids...Ch. 21 - What amino acids are formed by hydrolysis of the...Ch. 21 - Prob. 46PCh. 21 - Prob. 47PCh. 21 - Draw the structures of the amino acids formed when...Ch. 21 - Prob. 49PCh. 21 - Prob. 50PCh. 21 - Prob. 51PCh. 21 - Trypsin is a digestive enzyme that hydrolyzes...Ch. 21 - What type of intermolecular forces exist between...Ch. 21 - What type of interaction occur at each of the...Ch. 21 - Which peptide in each pair contains amino acids...Ch. 21 - Decide if the side chains of the amino acid...Ch. 21 - Which type of protein structure is indicated in...Ch. 21 - Label each of the following diagrams as...Ch. 21 - Prob. 59PCh. 21 - Prob. 60PCh. 21 - Prob. 61PCh. 21 - Prob. 62PCh. 21 - Compare - keratin and hemoglobin with regard to...Ch. 21 - Compare collagen and myoglobin with regard to each...Ch. 21 - Prob. 65PCh. 21 - Prob. 66PCh. 21 - Describe the function or biological activity of...Ch. 21 - Describe the function or biological activity of...Ch. 21 - Prob. 69PCh. 21 - Prob. 70PCh. 21 - What class of enzyme catalyzes each of the...Ch. 21 - What class of enzyme catalyzes each of the...Ch. 21 - Prob. 73PCh. 21 - Prob. 74PCh. 21 - Prob. 75PCh. 21 - What kind of reaction is catalyzed by each of the...Ch. 21 - Prob. 77PCh. 21 - How will each of the following changes affect the...Ch. 21 - Prob. 79PCh. 21 - Prob. 80PCh. 21 - Prob. 81PCh. 21 - Prob. 82PCh. 21 - Prob. 83PCh. 21 - Prob. 84PCh. 21 - Prob. 85PCh. 21 - Prob. 86PCh. 21 - Why must vegetarian diets be carefully balanced?Ch. 21 - Prob. 88PCh. 21 - Sometimes an incision is cauterized (burned) to...Ch. 21 - Why is insulin administered by injection instead...Ch. 21 - Prob. 91PCh. 21 - The silk produced by a silkworm is a protein with...Ch. 21 - Explain the difference in the mechanism of action...Ch. 21 - Prob. 94PCh. 21 - Prob. 95CPCh. 21 - Suggest a reason for the following observation....
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- 5. A solution of sucrose is fermented in a vessel until the evolution of CO2 ceases. Then, the product solution is analyzed and found to contain, 45% ethanol; 5% acetic acid; and 15% glycerin by weight. If the original charge is 500 kg, evaluate; e. The ratio of sucrose to water in the original charge (wt/wt). f. Moles of CO2 evolved. g. Maximum possible amount of ethanol that could be formed. h. Conversion efficiency. i. Per cent excess of excess reactant. Reactions: Inversion reaction: C12H22O11 + H2O →2C6H12O6 Fermentation reaction: C6H12O6 →→2C2H5OH + 2CO2 Formation of acetic acid and glycerin: C6H12O6 + C2H5OH + H₂O→ CH3COOH + 2C3H8O3arrow_forwardShow work. don't give Ai generated solution. How many carbons and hydrogens are in the structure?arrow_forward13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…arrow_forward
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