Concept explainers
Interpretation: The structure of 2,3,4,5,6-pentahydroxylhexanal has to be drawn.
Concept Introduction:
In aldehydes, the carbonyl group is attached at the end of the hydrocarbon chain. The carbonyl carbon is bonded to atleast one hydrogen.
Aldehydes have a general formula of
Answer to Problem 70A
The structure of 2,3,4,5,6-pentahydroxylhexanal is,
Explanation of Solution
The compound 2,3,4,5,6-pentahydroxylhexanal is an aldehyde. Aldehydes are organic compounds that have a carbonyl carbon attached to atleast one hydrogen atom. The general formula of aldehyde is
The general structure of an aldehyde is,
Where,
In 2,3,4,5,6-pentahydroxylhexanal,
The parent chain is hexane (six carbon atoms), since it is an aldehyde it becomes hexanal.
The carbonyl carbon occupies the first position.
The prefix “penta-” in pentahydroxyl shows the presence of five-hydroxyl groups.
The substituent hydroxyl is placed in the second, third, fourth, fifth and sixth positions.
The structure of 2,3,4,5,6-pentahydroxylhexanal is,
The structure of 2,3,4,5,6-pentahydroxylhexanal is,
Chapter 20 Solutions
World of Chemistry, 3rd edition
- Which carbocation is more stable?arrow_forwardAre the products of the given reaction correct? Why or why not?arrow_forwardThe question below asks why the products shown are NOT the correct products. I asked this already, and the person explained why those are the correct products, as opposed to what we would think should be the correct products. That's the opposite of what the question was asking. Why are they not the correct products? A reaction mechanism for how we arrive at the correct products is requested ("using key intermediates"). In other words, why is HCl added to the terminal alkene rather than the internal alkene?arrow_forward
- My question is whether HI adds to both double bonds, and if it doesn't, why not?arrow_forwardStrain Energy for Alkanes Interaction / Compound kJ/mol kcal/mol H: H eclipsing 4.0 1.0 H: CH3 eclipsing 5.8 1.4 CH3 CH3 eclipsing 11.0 2.6 gauche butane 3.8 0.9 cyclopropane 115 27.5 cyclobutane 110 26.3 cyclopentane 26.0 6.2 cycloheptane 26.2 6.3 cyclooctane 40.5 9.7 (Calculate your answer to the nearest 0.1 energy unit, and be sure to specify units, kJ/mol or kcal/mol. The answer is case sensitive.) H. H Previous Nextarrow_forwardA certain half-reaction has a standard reduction potential Ered +1.26 V. An engineer proposes using this half-reaction at the anode of a galvanic cell that must provide at least 1.10 V of electrical power. The cell will operate under standard conditions. Note for advanced students: assume the engineer requires this half-reaction to happen at the anode of the cell. Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have? If so, check the "yes" box and calculate the minimum. Round your answer to 2 decimal places. If there is no lower limit, check the "no" box.. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have? If so, check the "yes" box and calculate the maximum. Round your answer to 2 decimal places. If there is no upper limit, check the "no" box. yes, there is a minimum. 1 red Πν no minimum Oyes, there is a maximum. 0 E red Dv By using the information in the ALEKS…arrow_forward
- (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B Bond A Bond C a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. Weakest Bond Strongest Bond b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. c. (5pts) Use principles discussed in lecture, supported by relevant structures, to succinctly explain the why your part b (i) radical is more stable than your part b(ii) radical. Written explanation can be no more than one-two succinct sentence(s)!arrow_forward. 3°C with TH 12. (10pts total) Provide the major product for each reaction depicted below. If no reaction occurs write NR. Assume heat dissipation is carefully controlled in the fluorine reaction. 3H 24 total (30) 24 21 2h • 6H total ● 8H total 34 래 Br2 hv major product will be most Substituted 12 hv Br NR I too weak of a participate in P-1 F₂ hv Statistically most favored product will be major = most subst = thermo favored hydrogen atom abstractor to LL Farrow_forwardFive chemistry project topic that does not involve practicalarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY