(a)
Interpretation:
The name of the given alkene has to be described.
Concept Introduction:
Alkenes can also be two types-
- Unbranched alkenes
- Branched alkenes
(a)
Answer to Problem 30A
The name of the above compound is 2-pentene.
Explanation of Solution
The principle chain contains five carbon atoms and one double bond between C2 and C3. So, the name of the above compound is 2-pentene.
(b)
Interpretation:
The name of the given alkene has to be described.
Concept Introduction:
Alkenes are acyclic or cyclic unsaturated hydrocarbons containing at least one carbon-carbon double bond (C=C) and the general molecular formula CnH2n (where n = number of carbon atoms). Simplest alkene among all is ethylene C2H4 which contains one carbon-carbon double bond.
Alkenes can also be two types-
- Unbranched alkenes
- Branched alkenes
(b)
Answer to Problem 30A
The name of the above compound is 2-pentene.
Explanation of Solution
The principle chain contains five carbon atoms and one double bond between C2 and C3. So, the name of the above compound is 2-pentene.
(c)
Interpretation:
The name of the given alkene has to be described.
Concept Introduction:
Alkenes are acyclic or cyclic unsaturated hydrocarbons containing at least one carbon-carbon double bond (C=C) and the general molecular formula CnH2n (where n = number of carbon atoms). Simplest alkene among all is ethylene C2H4 which contains one carbon-carbon double bond.
Alkenes can also be two types-
- Unbranched alkenes
- Branched alkenes
(c)
Answer to Problem 30A
The name of the above compound is 2,5-dimethylhex-3-ene.
Explanation of Solution
The principle chain contains six carbon atoms, two methyl substituents at C2 and C5 and one double bond between C3 and C4. So, the name of the above compound is 2,5-dimethylhex-3-ene.
(d)
Interpretation:
The name of the given alkene has to be described.
Concept Introduction:
Alkenes are acyclic or cyclic unsaturated hydrocarbons containing at least one carbon-carbon double bond (C=C) and the general molecular formula CnH2n (where n = number of carbon atoms). Simplest alkene among all is ethylene C2H4 which contains one carbon-carbon double bond.
Alkenes can also be two types-
- Unbranched alkenes
- Branched alkenes
(d)
Answer to Problem 30A
The name of the above compound is 3,4,5-trimethylhept-1-ene.
Explanation of Solution
The principle chain contains seven carbon atoms, three methyl substituents at C3, C4 and C5 and one double bond between C1 and C2. So, the name of the above compound is 3,4,5-trimethylhept-1-ene.
Chapter 20 Solutions
World of Chemistry, 3rd edition
- Predict the organic products that form in the reaction below: H. H+ + OH H+ Y Note: You may assume you have an excess of either reactant if the reaction requires more than one of those molecules to form the products. In the drawing area below, draw the skeletal ("line") structures of the missing organic products X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Explanation Check Click and drag to start drawing a structure. G X C © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Access +arrow_forward111 Carbonyl Chem Choosing reagants for a Wittig reaction What would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 3 1 2 2. n-BuLi • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Explanation Check Click and drag to start drawing a structure. × ©2025 McGraw Hill LLC. All Rights Reserved. Terms of Usearrow_forwardA student proposes the transformation below in one step of an organic synthesis. There may be one or more reactants missing from the left-hand side, but there are no products missing from the right-hand side. There may also be catalysts, small inorganic reagents, and other important reaction conditions missing from the arrow. • Is the student's transformation possible? If not, check the box under the drawing area. . If the student's transformation is possible, then complete the reaction by adding any missing reactants to the left-hand side, and adding required catalysts, inorganic reagents, or other important reaction conditions above and below the arrow. • You do not need to balance the reaction, but be sure every important organic reactant or product is shown. + T X O O лет-ле HO OH HO OH This transformation can't be done in one step.arrow_forward
- Determine the structures of the missing organic molecules in the following reaction: X+H₂O H* H+ Y OH OH Note: Molecules that share the same letter have the exact same structure. In the drawing area below, draw the skeletal ("line") structures of the missing organic molecules X and Y. You may draw the structures in any arrangement that you like, so long as they aren't touching. Click and drag to start drawing a structure. X Sarrow_forwardPredict the major products of this organic reaction. If there aren't any products, because nothing will happen, check the box under the drawing area instead. No reaction. HO. O :☐ + G Na O.H Click and drag to start drawing a structure. XS xs H₂Oarrow_forwardWhat are the angles a and b in the actual molecule of which this is a Lewis structure? H H C H- a -H b H Note for advanced students: give the ideal angles, and don't worry about small differences from the ideal groups may have slightly different sizes. a = b = 0 °arrow_forward
- What are the angles a and b in the actual molecule of which this is a Lewis structure? :0: HCOH a Note for advanced students: give the ideal angles, and don't worry about small differences from the ideal that might be caused by the fact that different electron groups may have slightly different sizes. a = 0 b=0° Sarrow_forwardDetermine the structures of the missing organic molecules in the following reaction: + H₂O +H OH O OH +H OH X Note: Molecules that share the same letter have the exact same structure. In the drawing area below, draw the skeletal ("line") structure of the missing organic molecule X. Click and drag to start drawing a structure.arrow_forwardIdentify the missing organic reactant in the following reaction: x + x O OH H* + ☑- X H+ O O Х Note: This chemical equation only focuses on the important organic molecules in the reaction. Additional inorganic or small-molecule reactants or products (like H₂O) are not shown. In the drawing area below, draw the skeletal ("line") structure of the missing organic reactant X. Click and drag to start drawing a structure. Carrow_forward
- CH3O OH OH O hemiacetal O acetal O neither O 0 O hemiacetal acetal neither OH hemiacetal O acetal O neither CH2 O-CH2-CH3 CH3-C-OH O hemiacetal O acetal CH3-CH2-CH2-0-c-O-CH2-CH2-CH3 O neither HO-CH2 ? 000 Ar Barrow_forwardWhat would be the best choices for the missing reagents 1 and 3 in this synthesis? 1. PPh3 2 2. n-BuLi 3 Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Explanation Check Click and drag to start drawing a structure.arrow_forwardPredict the products of this organic reaction: NaBH3CN + NH2 ? H+ Click and drag to start drawing a structure. ×arrow_forward
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