(a)
Interpretation:
The name of the given alkene has to be described.
Concept Introduction:
Alkenes can also be two types-
- Unbranched alkenes
- Branched alkenes
(a)
Answer to Problem 30A
The name of the above compound is 2-pentene.
Explanation of Solution
The principle chain contains five carbon atoms and one double bond between C2 and C3. So, the name of the above compound is 2-pentene.
(b)
Interpretation:
The name of the given alkene has to be described.
Concept Introduction:
Alkenes are acyclic or cyclic unsaturated hydrocarbons containing at least one carbon-carbon double bond (C=C) and the general molecular formula CnH2n (where n = number of carbon atoms). Simplest alkene among all is ethylene C2H4 which contains one carbon-carbon double bond.
Alkenes can also be two types-
- Unbranched alkenes
- Branched alkenes
(b)
Answer to Problem 30A
The name of the above compound is 2-pentene.
Explanation of Solution
The principle chain contains five carbon atoms and one double bond between C2 and C3. So, the name of the above compound is 2-pentene.
(c)
Interpretation:
The name of the given alkene has to be described.
Concept Introduction:
Alkenes are acyclic or cyclic unsaturated hydrocarbons containing at least one carbon-carbon double bond (C=C) and the general molecular formula CnH2n (where n = number of carbon atoms). Simplest alkene among all is ethylene C2H4 which contains one carbon-carbon double bond.
Alkenes can also be two types-
- Unbranched alkenes
- Branched alkenes
(c)
Answer to Problem 30A
The name of the above compound is 2,5-dimethylhex-3-ene.
Explanation of Solution
The principle chain contains six carbon atoms, two methyl substituents at C2 and C5 and one double bond between C3 and C4. So, the name of the above compound is 2,5-dimethylhex-3-ene.
(d)
Interpretation:
The name of the given alkene has to be described.
Concept Introduction:
Alkenes are acyclic or cyclic unsaturated hydrocarbons containing at least one carbon-carbon double bond (C=C) and the general molecular formula CnH2n (where n = number of carbon atoms). Simplest alkene among all is ethylene C2H4 which contains one carbon-carbon double bond.
Alkenes can also be two types-
- Unbranched alkenes
- Branched alkenes
(d)
Answer to Problem 30A
The name of the above compound is 3,4,5-trimethylhept-1-ene.
Explanation of Solution
The principle chain contains seven carbon atoms, three methyl substituents at C3, C4 and C5 and one double bond between C1 and C2. So, the name of the above compound is 3,4,5-trimethylhept-1-ene.
Chapter 20 Solutions
World of Chemistry, 3rd edition
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- Predict the major products of this organic reaction. Be sure you use dash and wedge bonds to show stereochemistry where it's important. + ☑ OH 1. TsCl, py .... 文 P 2. t-BuO K Click and drag to start drawing a structure.arrow_forwardConsider this organic reaction: ( Draw the major products of the reaction in the drawing area below. If there won't be any major products, because this reaction won't happen at a significant rate, check the box under the drawing area instead. Click and drag to start drawing a structure. Х : а ค 1arrow_forwardIn the drawing area below, draw the major products of this organic reaction: If there are no major products, because nothing much will happen to the reactant under these reaction conditions, check the box under the drawing area instead. 1. NaH 2. CH3Br ? Click and drag to start drawing a structure. No reaction. : ☐ Narrow_forward
- + Predict the major product of the following reaction. : ☐ + ☑ ค OH H₂SO4 Click and drag to start drawing a structure.arrow_forwardConsider this organic reaction: ... OH CI Draw the major products of the reaction in the drawing area below. If there won't be any major products, because this reaction won't happen at a significant rate, check the box under the drawing area instead. ☐ No Reaction. Click and drag to start drawing a structure. : аarrow_forwardConsider the following reactants: Br Would elimination take place at a significant rate between these reactants? Note for advanced students: by significant, we mean that the rate of elimination would be greater than the rate of competing substitution reactions. yes O no If you said elimination would take place, draw the major products in the upper drawing area. If you said elimination would take place, also draw the complete mechanism for one of the major products in the lower drawing area. If there is more than one major product, you may draw the mechanism that leads to any of them. Major Products:arrow_forward
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