Concept explainers
(a)
The mass of the core in kg and solar masses, if the core of diameter is
(a)

Answer to Problem 45Q
Solution:
Explanation of Solution
Given data:
The core of diameter is
Formula used:
Write the expression for radius.
Here,
Write the formula for volume of sphere.
Here,
Write the expression for density
Here,
Explanation:
Recall the expression for radius.
Substitute
Recall the formula for volume of sphere.
Substitute
Recall the expression for density
Substitute
Convert mass kg to solar mass.
Conclusion:
The mass of the core in kg is
(b)
The force of gravity on a 1 kg object at the surface of the core, if the core of diameter is
(b)

Answer to Problem 45Q
Solution:
Explanation of Solution
Given data:
The core of diameter is
The gravity of the mass is
Formula used:
Write the expression for the radius.
Newton’s law of gravitation for the forces between two massive body can be stated by the following equation:
Here,
Explanation:
Recall the result of part (a):
The mass of the core in kg is
Recall the expression for radius.
Substitute
Newton’s law of universal gravitation can be stated by an equation as:
Substitute
The gravitational force due to the gravity of the Earth is provided as
Conclusion:
The gravitation force due to the core of the earth is
(c)
The escape speed from the surface of the core of the star, if the diameter of the core of the star is
(c)

Answer to Problem 45Q
Solution:
Explanation of Solution
Given data:
The core of diameter is
The gravity of the mass is
Formula used:
Escape speed from Earth (
Here, G is the universal gravitational constant, m is the mass of Earth and r is the radius of Earth.
Explanation:
Recall the result of part (a):
The mass of the core in kg is
The radius is
Escape speed from Earth (
Substitute
Further solve,
The escape velocity is large, as it is half of the speed of the light. So, it can be concluded that the gases must have velocity higher than half of the velocity of the light to escape from the core surface of the star. The explosion must be much higher to attained this velocity.
Conclusion:
The speed required by a gas to escape from the surface of the star’s core in m/s is
Want to see more full solutions like this?
Chapter 20 Solutions
EBK LOOSE-LEAF VERSION OF UNIVERSE
- Pls help asaparrow_forward3. If the force of gravity stopped acting on the planets in our solar system, what would happen? a) They would spiral slowly towards the sun. b) They would continue in straight lines tangent to their orbits. c) They would continue to orbit the sun. d) They would fly straight away from the sun. e) They would spiral slowly away from the sun. 4. 1 The free-body diagram of a wagon being pulled along a horizontal surface is best represented by A F N B C 0 Ꭰ FN E a) A b) B c) C app app The app 10 app d) e) ס ח D E 10 apparrow_forwardPls help ASAParrow_forward
- Pls help asaparrow_forwardPls help asaparrow_forwardThe acceleration of an object sliding along a frictionless ramp is inclined at an angle 0 is 9. a) g tano b) g cose c) g sino 10. d) g e) zero A 1.5 kg cart is pulled with a force of 7.3 N at an angle of 40° above the horizontal. If a kinetic friction force of 3.2 N acts against the motion, the cart's acceleration along the horizontal surface will be a) 5.0 m/s² b) 1.6 m/s² c) 2.4 m/s² 11. d) 1.0 m/s² e) 2.7 m/s² What is the net force acting on an object with a mass of 10 kg moving at a constant velocity of 10 m/s [North]? a) 100 N [North] b) 100 N [South] 10 N [North} d) 10 N [South] e) None of these.arrow_forward
- Modified True/False - indicate whether the sentence or statement is true or false. If the statement is false, correct the statement to make it true. 12. An object in uniform circular motion has a constant velocity while experiencing centripetal acceleration. 13. An object travelling in uniform circular motion experiences an outward centrifugal force that tends to pull the object out of the circular path. 14. An object with less inertia can resist changes in motion more than an object with more inertia. 15. For an object sliding on a horizontal surface with a horizontal applied force, the frictional force will always increase as the applied force increases.arrow_forwardPls help asaparrow_forwardAnswer the given question showing step by step by and all necessary working out.arrow_forward
- Stars and GalaxiesPhysicsISBN:9781305120785Author:Michael A. Seeds, Dana BackmanPublisher:Cengage LearningFoundations of Astronomy (MindTap Course List)PhysicsISBN:9781337399920Author:Michael A. Seeds, Dana BackmanPublisher:Cengage LearningStars and Galaxies (MindTap Course List)PhysicsISBN:9781337399944Author:Michael A. SeedsPublisher:Cengage Learning
- AstronomyPhysicsISBN:9781938168284Author:Andrew Fraknoi; David Morrison; Sidney C. WolffPublisher:OpenStaxGlencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-HillHorizons: Exploring the Universe (MindTap Course ...PhysicsISBN:9781305960961Author:Michael A. Seeds, Dana BackmanPublisher:Cengage Learning





