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Solve the one-dimensional heat conduction problem 6 using the Rayleigh-Ritz method. For the heat conduction problem, the total potential can be defined as
Use the approximate solution
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- What is the answerarrow_forward3. For two dimension heat conduction in a plate as shown in figure 3, find the temperature distribution T (x,y) by solving the boundary value problem. a2T + ду? Use the steady state heat conduction equation as: Ty=n = 1 Tx=0 = 1 H = T Tx=n = 1 L = TT y Ty=o = 0 Figure 3arrow_forwardHelp mearrow_forward
- Please help with this questionarrow_forwardBi = 1/2arrow_forwardThe initial temperature distribution of a 5 cm long stick is given by the following function. The circumference of the rod in question is completely insulated, but both ends are kept at a temperature of 0 °C. Obtain the heat conduction along the rod as a function of time and position ? (x = 1.752 cm²/s for the bar in question) 100 A) T(x1) = 1 Sin ().e(-1,752 (³¹)+(sin().e (-1,752 (²) ₁ + 1 3π TC3 .....) 100 t + ··· ....... 13) T(x,t) = 200 Sin ().e(-1,752 (²t) + (sin (3). e (-1,752 (7) ²) t B) 3/3 t + …............) C) T(x.t) = 200 Sin ().e(-1,752 (²t) (sin().e(-1,752 (7) ²) t – D) T(x,t) = 200 Sin ().e(-1,752 (²)-(sin().e (-1,752 (²7) ²) t E) T(x.t)=(Sin().e(-1,752 (²t)-(sin().e(-1,752 (²) t+ t + ··· .........) t +.... t + ··· .........) …..)arrow_forward
- 1. The general form of linear second-order differential equation can be written in the form: و بار / كلية الهندسة Q4)/ grap dy q(x)y = r(x) d'y +p(x) dx dy b. dx - F(x)y = F(x) x2 dy dx - xy = C. d. r2 d?y dx2 -f(x)y = F(x) 2431)(5-1) 3 (3-21)2 a. (221 -91i) / 169 b. (21 + 52i)/ 13 c. (-90+220i)/169 d. (-7+17i)/ 13 2. Simplify: الحدار المك المراغة 3. If the roots of second order differential equation is complex conjugate, then the gene contain: a. sinusoidal functions and exponentials b. constant and two exponentials c. two constants and two exponentials d. two constants and one exponential 5 4. The order and degree of the differential: 3(3 - + 4y = sinx* are: d²y a. First-order, First-degree- b. First-order, second-degree Second -order, First -degree d. Second -order, second-degree dx2 lo - 2i tisi. 8- 12i 5. The particular solution of (D² + 4)y = cos 2x is equal to: a. sin 2x b. cos 2x 13+159 C. 4 cos 2x d. 4 sin 2x 5-12 lo Best wishes الامتحانية د. مازن ياسین عبود رئيس القسم بن فاضل…arrow_forward3.10 By neglecting lateral temperature variation in the analysis of fins, h,T. 木 H two-dimensional conduction is modeled as a one-dimensional H problem. То examine this T, h,T. approximation, consider a semi- infinite plate of thickness 2H. The base is maintained at uniform temperature T,. The plate exchanges heat by convection at its semi- infinite surfaces. The heat transfer coefficient is h and the ambient temperature is T.. Determine the heat transfer rate at the base.arrow_forwardFind the two-dimensional temperature distribution T(x,y) and midplane temperature T(B/2,W/2) under steady state condition. The density, conductivity and specific heat of the material are ρ =1200 kg/m 3, k=400 W/m.K, and cp=2500 J/kg.K, respectively. A uniform heat flux q =1000 W/m 2 is applied to the upper surface. The right and left surfaces are also kept at 0oC. Bottom surface is insulated.arrow_forward
- The amount of heat conducted through a wall of length r is given by Fourier's Law:. CONDUCTION RATE EQUATION T FOURIER'S LAW q, = -k A dT dx T, >T, where q, is the heat flux, k is a proportionality factor, Ais the wall's cross-sectional area, and 4 is the temperature gradient throughout the wall. Our friend Matt Labb wants to find T2 (temperature of the wall's rightmost edge) given q,, k, and A. Is this possible? If so, briefly explain how to find Tp. If not, briefly explain why.arrow_forwardFind the two-dimensional temperature distribution T(x,y) and midplane temperature T(B/2,W/2) under steady state condition. The density, conductivity and specific heat of the material are p=(1200*32)kg/mº, k=400 W/m.K, and cp=2500 J/kg.K, respectively. A uniform heat flux 9" =1000 W/m² is applied to the upper surface. The right and left surfaces are also kept at 0°C. Bottom surface is insulated. 9" (W/m) T=0°C T=0°C W=(10*32)cm B=(30*32)cmarrow_forwardThxarrow_forward
- Principles of Heat Transfer (Activate Learning wi...Mechanical EngineeringISBN:9781305387102Author:Kreith, Frank; Manglik, Raj M.Publisher:Cengage Learning