Introduction To Finite Element Analysis And Design
Introduction To Finite Element Analysis And Design
2nd Edition
ISBN: 9781119078722
Author: Kim, Nam H., Sankar, Bhavani V., KUMAR, Ashok V., Author.
Publisher: John Wiley & Sons,
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Chapter 2, Problem 13E

Using the Galerkin method, calculate the approximate solution of the following differential equation in the form of u ( x ) = c 1 x + c 2 1 2 x 2 .

d d x ( x d u d x ) = x 0 x 1 u ( 0 ) = 0 d u d x ( 1 ) = 1

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1. The figure shows a car jack to support 400kg (W=400kg). In the drawing, the angle (0) varies between 15 and 70 °. The links are machined from AISI 1020 hot-rolled steel bars with a minimum yield strength of 380MPa. Each link consists of two bars, one on each side of the central bearings. The bars are 300mm in length (/) and 25 mm in width (w). The pinned ends have the buckling constant (C) of 1.4 for out of plane buckling. The design factor (nd) is 2.5. (1) Find the thickness (t) of the bars and the factor of safety (n). (2) Check if the bar is an Euler beam. D
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UNIVERSIDAD NACIONAL DE SAN ANTONIO ABAD DEL CUSCO PRIMER EXAMEN PARCIAL DE MECÁNICA DE FLUIDOS I ............ Cusco, 23 de setiembre de 2024 AP. Y NOMBRES: ........ 1.- Para el tanque de la figura: a) Calcule la profundidad de la hidrolina si la profundidad del agua es de 2.8 m y el medidor del fondo del tanque da una lectura de 52.3kPa. b) Calcule la profundidad del agua si la profundidad de la hidrolina es 6.90 m y el medidor de la parte inferior del tanque registra una lectura de 125.3 kPa. Hidrolina Sp=0.90 Abertura Agua sup suge to but amulor quit y 2.- Calcule la magnitud de la fuerza resultante sobre el área A-B y la ubicación del centro de presión. Señale la fuerza resultante sobre el área y dimensione su ubicación con claridad. 3.5 ft 12 in: Oil (38-0.93) 14 in 8 in

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