Explanation Given: The body temperature, T = 150 °C Chamber wall temperature, T ' = 25 ° C Stefan Boltzmann’s constant, σ = 5.67 × 10 − 8 Wm -2 K -4 The emissivity of the body, ∈ o = 0.8 Surface area, A = 0.5 m 2 Stefan’s law states that the total energy radiated per unit surface area of a black body in unit time is proportional to its absolute temperature raised to the fourth power. The rate of radiation by the surface is given by: P = ∈ o σ A T 4 Where, P is the rate of radiation in W ∈ o is the emissivity of the body σ is the Stefan Boltzmann’s constant in Wm- 2 K-4 A is the surface area of the body in m 2 T is the temperature in Kelvin(K) Calculation: To convert Celsius degrees to Kelvin add 273 to the Celsius temperature. T = 150 + 273 T = 423 K T ' = 25 + 273 T ' = 298 K The rate of radiation will be: P = ( 0

FUND OF ENG THERMODYN-WILEYPLUS NEXT GEN

9th Edition

ISBN: 9781119840589

Author: MORAN

Publisher: WILEY

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Chapter 2, Problem 2.40P

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The rate at which radiation is emitted by the surface and the net rate at which radiation is exchanged between the surface and the chamber walls.

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Chapter 2, Problem 2.39P

Chapter 2, Problem 2.41P

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FUND OF ENG THERMODYN-WILEYPLUS NEXT GEN

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The rate at which radiation is emitted by the surface and the net rate at which radiation is exchanged between the surface and the chamber walls.

Solution Summary: The author states that the total energy radiated per unit surface area of a black body is proportional to its absolute temperature raised to the fourth power.

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The rate at which radiation is emitted by the surface and the net rate at which radiation is exchanged between the surface and the chamber walls.

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Chapter 2 Solutions