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EBK FUNDAMENTALS OF GENERAL, ORGANIC, A
8th Edition
ISBN: 8220102895805
Author: Peterson
Publisher: PEARSON
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Question
Chapter 19, Problem 19.44AP
(a)
Interpretation Introduction
Interpretation:
The general reaction in which the enzyme ligase catalyse should be determined.
Concept introduction:
Enzyme:
- It is a protein or a molecule which can act as a catalyst for a biological reaction.
- Does not affect the equilibrium point of the reaction.
- Active site of the enzyme is the region where the reaction takes place.
- Enzyme’s activity can be specific which means the activity is limited to a certain substrate and a certain type of reaction and it is referred to as specificity of the enzyme.
Classification of enzymes:
- Oxidoreductases
- Transferases
- Hydrolases
- Isomerases
- Lyases
- Ligases
(b)
Interpretation Introduction
Interpretation:
The general reaction in which the enzyme transmethylase catalyse should be determined.
Concept introduction:
Enzyme:
- It is a protein or a molecule which can act as a catalyst for a biological reaction.
- Does not affect the equilibrium point of the reaction.
- Active site of the enzyme is the region where the reaction takes place.
- Enzyme’s activity can be specific which means the activity is limited to a certain substrate and a certain type of reaction and it is referred to as specificity of the enzyme.
Classification of enzymes:
- Oxidoreductases
- Transferases
- Hydrolases
- Isomerases
- Lyases
- Ligases
(c)
Interpretation Introduction
Interpretation:
The general reaction in which the enzyme reductase catalyse should be determined.
Concept introduction:
Enzyme:
- It is a protein or a molecule which can act as a catalyst for a biological reaction.
- Does not affect the equilibrium point of the reaction.
- Active site of the enzyme is the region where the reaction takes place.
- Enzyme’s activity can be specific which means the activity is limited to a certain substrate and a certain type of reaction and it is referred to as specificity of the enzyme.
Classification of enzymes:
- Oxidoreductases
- Transferases
- Hydrolases
- Isomerases
- Lyases
- Ligases
Expert Solution & Answer
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Chapter 19 Solutions
EBK FUNDAMENTALS OF GENERAL, ORGANIC, A
Ch. 19.1 - Prob. 19.1PCh. 19.1 - The enzyme LDH converts lactate to pyruvate. In...Ch. 19.2 - The cofactors NAD+, Cu2+, Zn2+, coenzyme A, FAD,...Ch. 19.3 - Describe the reactions that you would expect these...Ch. 19.3 - Prob. 19.5PCh. 19.3 - Prob. 19.6PCh. 19.3 - Prob. 19.7PCh. 19.3 - Prob. 19.8PCh. 19.4 - Prob. 19.9KCPCh. 19.5 - Prob. 19.10KCP
Ch. 19.5 - Prob. 19.11PCh. 19.5 - Prob. 19.12PCh. 19.6 - Prob. 19.13PCh. 19.6 - Prob. 19.14PCh. 19.7 - (a) L-Threonine is converted to L-isoleucine in a...Ch. 19.8 - AZT (zidovudine) inhibits the synthesis of the HIV...Ch. 19.8 - Prob. 19.3CIAPCh. 19.8 - Prob. 19.16PCh. 19.9 - Does the enzyme described in each of the following...Ch. 19.9 - Prob. 19.18PCh. 19.9 - Compare the structures of vitamin A and vitamin C....Ch. 19.9 - Prob. 19.20PCh. 19.9 - Prob. 19.21KCPCh. 19.9 - Prob. 19.22PCh. 19.9 - Prob. 19.4CIAPCh. 19.9 - Prob. 19.6CIAPCh. 19.9 - Prob. 19.7CIAPCh. 19.9 - Enzyme levels in blood are often elevated in...Ch. 19.9 - Prob. 19.9CIAPCh. 19.9 - Prob. 19.23PCh. 19 - Prob. 19.24UKCCh. 19 - Prob. 19.25UKCCh. 19 - Prob. 19.26UKCCh. 19 - Prob. 19.27UKCCh. 19 - Prob. 19.28APCh. 19 - Explain how the following mechanisms regulate...Ch. 19 - Prob. 19.30APCh. 19 - Prob. 19.31APCh. 19 - Prob. 19.32APCh. 19 - Prob. 19.33APCh. 19 - Prob. 19.34APCh. 19 - Prob. 19.35APCh. 19 - Prob. 19.36APCh. 19 - Prob. 19.37APCh. 19 - Name an enzyme that acts on each molecule. (a)...Ch. 19 - Name an enzyme that acts on each molecule. (a)...Ch. 19 - What features of enzymes make them so specific in...Ch. 19 - Describe in general terms how enzymes act as...Ch. 19 - Prob. 19.42APCh. 19 - Prob. 19.43APCh. 19 - Prob. 19.44APCh. 19 - Prob. 19.45APCh. 19 - Prob. 19.46APCh. 19 - Prob. 19.47APCh. 19 - What is the difference between the lock-and-key...Ch. 19 - Why is the induced-fit model a more likely model...Ch. 19 - Prob. 19.50APCh. 19 - Prob. 19.51APCh. 19 - How do you explain the observation that pepsin, a...Ch. 19 - Prob. 19.53APCh. 19 - Prob. 19.54APCh. 19 - Prob. 19.55APCh. 19 - Prob. 19.56APCh. 19 - Prob. 19.57APCh. 19 - The text discusses three forms of enzyme...Ch. 19 - Prob. 19.59APCh. 19 - Prob. 19.60APCh. 19 - Prob. 19.62APCh. 19 - Prob. 19.63APCh. 19 - The meat tenderizer used in cooking is primarily...Ch. 19 - Prob. 19.65APCh. 19 - Why do allosteric enzymes have two types of...Ch. 19 - Prob. 19.67APCh. 19 - Prob. 19.68APCh. 19 - Prob. 19.69APCh. 19 - Prob. 19.70APCh. 19 - Prob. 19.71APCh. 19 - Prob. 19.72APCh. 19 - Prob. 19.73APCh. 19 - Prob. 19.74APCh. 19 - Prob. 19.75APCh. 19 - Prob. 19.76APCh. 19 - Prob. 19.77APCh. 19 - Prob. 19.78APCh. 19 - Prob. 19.79APCh. 19 - Prob. 19.80CPCh. 19 - Prob. 19.81CPCh. 19 - Prob. 19.82CPCh. 19 - Prob. 19.83CPCh. 19 - Prob. 19.84CPCh. 19 - Prob. 19.85CPCh. 19 - Prob. 19.86CPCh. 19 - Prob. 19.87CPCh. 19 - Prob. 19.88GPCh. 19 - The ability to change a selected amino acid...Ch. 19 - Prob. 19.90GPCh. 19 - Prob. 19.91GP
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- Problem 15 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 4 of 15 4G 54% Done On the following Lineweaver-Burk -1 plot, identify the by dragging the Km point to the appropriate value. 1/V 40 35- 30- 25 20 15 10- T Км -15 10 -5 0 5 ||| 10 15 №20 25 25 30 1/[S] Г powered by desmosarrow_forward1:30 5G 47% Problem 10 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a competitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' s mM¹ with 10 mg pe 20 V' 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
- Problem 14 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:36 CO Problem 9 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of the catalytic efficiency (specificity constant) given that the enzyme concentration in this experiment is 5.0 μ.Μ. 1 [S] ¨‚ μM-1 1 V sμM-1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| O Гarrow_forwardProblem 11 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without a noncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
- Problem 13 of 15 Submit Using the following reaction data points, construct Lineweaver-Burk plots for an enzyme with and without an inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Using the information from this plot, determine the type of inhibitor present. 1 mM-1 1 s mM -1 [S]' V' with 10 μg per 20 54 10 36 20 5 27 2.5 23 1.25 20 Answer: |||arrow_forward12:33 CO Problem 8 of 15 4G. 53% Submit Using the following reaction data points, construct a Lineweaver-Burk plot by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. Based on the plot, determine the value of kcat given that the enzyme concentration in this experiment is 5.0 μM. 1 [S] , мм -1 1 V₁ s μM 1 100.0 0.100 75.0 0.080 50.0 0.060 15.0 0.030 10.0 0.025 5.0 0.020 Answer: ||| Гarrow_forward1:33 5G. 46% Problem 12 of 15 Submit Using the following reaction data points, construct a Lineweaver-Burk plot for an enzyme with and without an uncompetitive inhibitor by dragging the points to their relevant coordinates on the graph and drawing a line of best fit. 1 -1 1 mM [S]' 20 V' s mM¹ with 10 μg per 54 10 36 > ст 5 27 2.5 23 1.25 20 Answer: |||arrow_forward
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