Chapter 18, Problem 61A

Interpretation Introduction

Interpretation : The intermediate in the reaction is to be found.

Concept Introduction : The rate is a method for determining how much something changes over a predetermined period of time. The amount of reactant or product that changes per unit of time is the reaction rate.

Answer to Problem 61A

The intermediate in the reaction is ${\text{N}}_{\text{2}}{\text{O}}_{\text{2}}$ .

Explanation of Solution

Consider the given reactions:

  $\begin{array}{l}\text{2NO}\left(g\right) \to {\text{N}}_{\text{2}}{\text{O}}_{\text{2}}\left(g\right)\left(\text{fast}\right)\hfill \\ {\text{N}}_{\text{2}}{\text{O}}_{\text{2}}\left(g\right)+{\text{O}}_{\text{2}}\left(g\right) \to {\text{2NO}}_{\text{2}}\left(g\right)\left(\text{slow}\right)\hfill \end{array}$

The reactants are $\text{NO}$ and ${\text{O}}_{\text{2}}$ .

The product is ${\text{NO}}_{\text{2}}$ .

The intermediate is ${\text{N}}_{\text{2}}{\text{O}}_{\text{2}}$ .

The overall reaction is given as

  $\text{2NO}\left(g\right) +{\text{O}}_{\text{2}}\left(g\right) \to {\text{2NO}}_{\text{2}}$

A graph that depicts the connection between energy and reaction progress is called a reaction coordinate diagram.

The quantity of energy that must be added is known as the activation energy, and it can be found on the graph at the location where the line curves upward.

The reaction progress curve is given below: