Chapter 18, Problem 129A

Interpretation Introduction

Interpretation: The number of moles of solute in $\text{2}\text{.40}\text{L}$ of $\text{0}\text{.66}\text{M}\text{KCl}$ should be determined.

Concept Introduction: The number of moles of solute dissolved in a one-liter solution is termed molarity. It is represented by M.

Answer to Problem 129A

The number of moles of solute in $\text{2}\text{.40}\text{L}$ of $\text{0}\text{.66}\text{M}\text{KCl}$ is $\text{1}\text{.584 mol}$ .

Explanation of Solution

  $\begin{array}{c}\text{Number of moles of solute = Molarity}\times \text{Volume}\\ =\text{0}\text{.66 }\frac{\text{mol}}{\text{L}}\times \text{2}\text{.40}\text{L}\\ \text{n}=\text{1}\text{.584 mol}\end{array}$