Chapter 18.1, Problem 3LC

Interpretation Introduction

Interpretation: The expression for the conversion of the 0.2 mole sheet of zinc to zinc oxide is to be stated.

Concept Introduction: The rate of a chemical reaction is generally expressed as the reactant’s concentration consumed and the product’s concentration formed per unit of time.

Answer to Problem 3LC

The rate of the conversion of the zinc is expressed as $0.44\text{g/day}$ .

Explanation of Solution

Given: $\text{0}\text{.2}\text{mole}$ of zinc sheet is converted to zinc oxide in one month.

The number of grams converted to zinc oxide can be calculated as:

  $\begin{array}{c}\text{Mass}\text{of}\text{zinc}\text{converted}=\text{0}\text{.2}\text{mol}\times \text{Molar}\text{mass}\text{of}\text{zinc}\\ =\text{0}\text{.2}\text{mol}\times 65.38\frac{\text{g}}{\text{mol}}\\ =13.1\text{g}\end{array}$

That means 13.1 gram of zinc is converted to zinc oxide in one month or 30 days.

Thus, the rate of conversion of the zinc is expressed as $\frac{\text{13}\text{.1}\text{g}}{\text{30}\text{days}}=0.44\text{g/day}$