The correct IUPAC name for the given alkane has to be written from the given options. Concept Introduction: Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word. Prefix represents the substituent present in the molecule and its position in the root name. Suffix denotes the presence of functional group if any in the molecule. It can be an alkene , alkyne , alcohol, carboxylic acid , alcohol etc. Root word represents the longest continuous carbon skeleton of the organic molecule. To name an alkane, the first step is to find the longest carbon chain. The next step is to identify the substituents that are present in the longest carbon chain. The numbering has to be given in a way that the substituents get the least numbering.

Question

43) 10.00 ml of vinegar (active ingredient is acetic acid) is titrated to the endpoint using 19.32 ml of 0.250 M sodium hydroxide. What is the molarity of acetic acid in the vinegar? YOU MUST SHOW YOUR WORK. NOTE: MA x VA = MB x VB

Answer 1

Question

Chapter 1.8, Problem 4QQ

Interpretation Introduction

Interpretation:

The correct IUPAC name for the given alkane has to be written from the given options.

Concept Introduction:

Any organic molecule can be named by using certain rules given by IUPAC (International Union for Pure and applied chemistry). IUPAC name consists of three parts in major namely Prefix suffix and root word.

Prefix represents the substituent present in the molecule and its position in the root name.

Suffix denotes the presence of functional group if any in the molecule. It can be an alkene, alkyne, alcohol, carboxylic acid, alcohol etc.

Root word represents the longest continuous carbon skeleton of the organic molecule.

To name an alkane, the first step is to find the longest carbon chain. The next step is to identify the substituents that are present in the longest carbon chain. The numbering has to be given in a way that the substituents get the least numbering.

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43) 10.00 ml of vinegar (active ingredient is acetic acid) is titrated to the endpoint using 19.32 ml of 0.250 M sodium hydroxide. What is the molarity of acetic acid in the vinegar? YOU MUST SHOW YOUR WORK. NOTE: MA x VA = MB x VB

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