Introductory Chemistry: A Foundation
Introductory Chemistry: A Foundation
9th Edition
ISBN: 9781337399425
Author: Steven S. Zumdahl, Donald J. DeCoste
Publisher: Cengage Learning
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Chapter 18, Problem 46QAP
Interpretation Introduction

(a)

Interpretation:

The given oxidation-reduction reaction should be balanced using the half-reaction method.

Concept Introduction:

The oxidation-reduction reaction is also known as a redox reaction. In this reaction, one reactant is oxidized and other is reduced. In balancing an oxidation-reduction reaction they must be first divided into two half reactions: one is oxidation reaction and other is reduction reaction.

The balancing of redox reaction is complicated as compared to simple balancing. It is necessary to determine the half reactions of reactants undergoing oxidation and reduction. On adding the two half-reactions, net total equation can be obtained. This method of balancing redox reaction is known as half equation method.

The following rules must be followed in balancing redox reaction by half equation method:

  1. Initially, redox reaction is separated into two half equations; oxidation and reduction.
  2. Atoms other than hydrogen and oxygen are balanced first in the unbalanced half equations.
  3. Oxygen atoms are balanced by addition of water on either side of the reaction.
  4. Hydrogen ion/s is added to balance the hydrogen atom.
  5. Electrons are added to balance the charge.
  6. Half reactions are added to get the net total equation.
  7. The further addition of hydroxide ion takes place on both side of the reaction, if the solution is basic in nature to neutralise the hydrogen ion present in the solution.

Expert Solution
Check Mark

Answer to Problem 46QAP

2Als+6H+aq2Al3+aq+3H2g.

Explanation of Solution

The given reaction is as follows:

Als+H+aqAl3+aq+H2g

First step is to separate the two half reaction,

AlsAl3+aq....... (1)

And,

H+aqH2g...... (2)

Now to balance reaction (1), there is + 3 charge on right thus, 3 electrons are added to right,

AlsAl3+aq+3e...... (3)

Similarly, reaction (2) can be balanced by adding hydrogen ion to the left or giving coefficient 2 to hydrogen ion on left thus,

2H+aqH2g

Now, to balance the charge, 2 electrons are added to left side of the reaction arrow thus,

2H+aq+2eH2g..... (4)

Now, adding reaction (3) and (4) to get the net overall reaction,

2AlsAl3+aq+3e32H+aq+2eH2g2Als+6H+aq2Al3+aq+3H2g¯¯

Thus, the balanced reaction by half reaction method will be:

2Als+6H+aq2Al3+aq+3H2g.

Interpretation Introduction

(b)

Interpretation:

The given oxidation-reduction reaction should be balanced using the half-reaction method.

Concept Introduction:

The oxidation-reduction reaction is also known as a redox reaction. In this reaction, one reactant is oxidized and other is reduced. In balancing an oxidation-reduction reaction they must be first divided into two half reactions: one is oxidation reaction and other is reduction reaction.

The balancing of redox reaction is complicated as compared to simple balancing. It is necessary to determine the half reactions of reactants undergoing oxidation and reduction. On adding the two half-reactions, net total equation can be obtained. This method of balancing redox reaction is known as half equation method.

The following rules must be followed in balancing redox reaction by half equation method:

  1. Initially, redox reaction is separated into two half equations; oxidation and reduction.
  2. Atoms other than hydrogen and oxygen are balanced first in the unbalanced half equations.
  3. Oxygen atoms are balanced by addition of water on either side of the reaction.
  4. Hydrogen ion/s is added to balance the hydrogen atom.
  5. Electrons are added to balance the charge.
  6. Half reactions are added to get the net total equation.
  7. The further addition of hydroxide ion takes place on both side of the reaction, if the solution is basic in nature to neutralise the hydrogen ion present in the solution.

Expert Solution
Check Mark

Answer to Problem 46QAP

3S2aq+2NO3aq+8H+aq3Ss+2NOg+4H2O.

Explanation of Solution

The given reaction is as follows:

S2aq+NO3aqSs+NOg

First step is to separate the two half reaction,

S2aqSs....... (1)

And,

NO3aqNOg...... (2)

First reaction 1 is balanced by adding 2 electrons to the right side of the reaction arrow:

S2aqSs+2e...... (3)

Now, to balance reaction to 2 water molecules are added to right side of the reaction arrow:

NO3aqNOg+2H2O

Now, to balance hydrogen atoms, 4 hydrogen ions can be added to left side of the reaction arrow:

NO3aq+4H+NOg+2H2O

To balance the charge, 3 electrons must be added to left,

NO3aq+4H++3eNOg+2H2O..... (4)

Now, adding reaction (3) and (4) to get the net overall reaction,

3×S2aqSs+2e2×NO3aq+4H++3eNOg+2H2O3S2aq+2NO3aq+8H+aq3Ss+2NOg+4H2O¯¯

Thus, the balanced reaction by half reaction method will be:

3S2aq+2NO3aq+8H+aq3Ss+2NOg+4H2O.

Interpretation Introduction

(c)

Interpretation:

The given oxidation-reduction reaction should be balanced using the half-reaction method.

Concept Introduction:

The oxidation-reduction reaction is also known as a redox reaction. In this reaction, one reactant is oxidized and other is reduced. In balancing an oxidation-reduction reaction they must be first divided into two half reactions: one is oxidation reaction and other is reduction reaction.

The balancing of redox reaction is complicated as compared to simple balancing. It is necessary to determine the half reactions of reactants undergoing oxidation and reduction. On adding the two half-reactions, net total equation can be obtained. This method of balancing redox reaction is known as half equation method.

The following rules must be followed in balancing redox reaction by half equation method:

  1. Initially, redox reaction is separated into two half equations; oxidation and reduction.
  2. Atoms other than hydrogen and oxygen are balanced first in the unbalanced half equations.
  3. Oxygen atoms are balanced by addition of water on either side of the reaction.
  4. Hydrogen ion/s is added to balance the hydrogen atom.
  5. Electrons are added to balance the charge.
  6. Half reactions are added to get the net total equation.
  7. The further addition of hydroxide ion takes place on both side of the reaction, if the solution is basic in nature to neutralise the hydrogen ion present in the solution.

Expert Solution
Check Mark

Answer to Problem 46QAP

I2aq+6H2Ol+5Cl2aq2IO3aq+2H+aq+10HClg.

Explanation of Solution

The given reaction is as follows:

I2aq+Cl2aqIO3aq+HClg

First step is to separate the two half reaction,

I2aqIO3aq....... (1)

And,

Cl2aqHClg...... (2)

First reaction 1 is balanced by giving coefficient 2 to IO3aq thus,

I2aq2IO3aq

Next step is to balance oxygen atom by adding 6 water molecule on left thus,

I2aq+6H2Ol2IO3aq

Now, hydrogen atoms are balanced adding 12 hydrogen ions to the right:

I2aq+6H2Ol2IO3aq+12H+aq

Last step is to balance the charge, thus, 10 electrons are added to right side of the reaction arrow.

I2aq+6H2Ol2IO3aq+12H+aq+10e..... (3)

Now to balance reaction (2), chlorine atom is balanced first by giving coefficient 2 to HClg as follows:

Cl2aq2HClg

To balance the hydrogen atom, 2 hydrogen ions are added to left thus,

Cl2aq+2H+aq2HClg

Last step is to balance the charge, thus, two electrons are added to left side of the reaction arrow:

Cl2aq+2H+aq+2e2HClg...... (4)

Now, adding reaction (3) and (4) to get the net overall reaction,

I2aq+6H2Ol2IO3aq+12H+aq+10e       5×Cl2aq+2H+aq+2e2HClgI2aq+6H2Ol+5Cl2aq2IO3aq+2H+aq+10HClg¯¯

Thus, the balanced reaction by half reaction method will be:

I2aq+6H2Ol+5Cl2aq2IO3aq+2H+aq+10HClg.

Interpretation Introduction

(d)

Interpretation:

The given oxidation-reduction reaction should be balanced using the half-reaction method.

Concept Introduction:

The oxidation-reduction reaction is also known as a redox reaction. In this reaction, one reactant is oxidized and other is reduced. In balancing an oxidation-reduction reaction they must be first divided into two half reactions: one is oxidation reaction and other is reduction reaction.

The balancing of redox reaction is complicated as compared to simple balancing. It is necessary to determine the half reactions of reactants undergoing oxidation and reduction. On adding the two half-reactions, net total equation can be obtained. This method of balancing redox reaction is known as half equation method.

The following rules must be followed in balancing redox reaction by half equation method:

  1. Initially, redox reaction is separated into two half equations; oxidation and reduction.
  2. Atoms other than hydrogen and oxygen are balanced first in the unbalanced half equations.
  3. Oxygen atoms are balanced by addition of water on either side of the reaction.
  4. Hydrogen ion/s is added to balance the hydrogen atom.
  5. Electrons are added to balance the charge.
  6. Half reactions are added to get the net total equation.
  7. The further addition of hydroxide ion takes place on both side of the reaction, if the solution is basic in nature to neutralise the hydrogen ion present in the solution.

Expert Solution
Check Mark

Answer to Problem 46QAP

AsO4aq+2H+aq+S2aqAsO3aq+H2Ol+Ss.

Explanation of Solution

The given reaction is as follows:

AsO4aq+S2aqAsO3aq+Ss

First step is to separate the two half reaction,

AsO4aqAsO3aq....... (1)

And,

S2aqSs...... (2)

In reaction 1, oxygen atom can be balanced by adding 1 water molecule to the right:

AsO4aqAsO3aq+H2Ol

Now, hydrogen atom can be balanced by adding 2 hydrogen ions to the left thus,

AsO4aq+2H+aqAsO3aq+H2Ol

Last step is to balance the charge, since, there is + 1 charge on left and -1 charge on right thus, two electrons must be added to left thus,

AsO4aq+2H+aq+2eAsO3aq+H2Ol...... (3) Now to balance reaction (2), charge can be balanced by adding 2 electrons to the right,

S2aqSs+2e...... (4)

Now, adding reaction (3) and (4) to get the net overall reaction,

AsO4aq+2H+aq+2eAsO3aq+H2OlS2aqSs+2eAsO4aq+2H+aq+S2aqAsO3aq+H2Ol+Ss¯¯

Thus, the balanced reaction by half reaction method will be:

AsO4aq+2H+aq+S2aqAsO3aq+H2Ol+Ss.

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Chapter 18 Solutions

Introductory Chemistry: A Foundation

Ch. 18 - Prob. 5ALQCh. 18 - Prob. 6ALQCh. 18 - In balancing oxidation-reduction equations, why is...Ch. 18 - What does it mean for a substance to be oxidized?...Ch. 18 - Label the following parts of the galvanic cell....Ch. 18 - Prob. 1QAPCh. 18 - Prob. 2QAPCh. 18 - For each of the following oxidation-reduction...Ch. 18 - For each of the following oxidation-reduction...Ch. 18 - For each of the following oxidation-reduction...Ch. 18 - Prob. 6QAPCh. 18 - Prob. 7QAPCh. 18 - Prob. 8QAPCh. 18 - Explain why, although it is not an ionic compound,...Ch. 18 - Prob. 10QAPCh. 18 - Prob. 11QAPCh. 18 - Prob. 12QAPCh. 18 - Prob. 13QAPCh. 18 - . Assign oxidation states to all of the atoms in...Ch. 18 - Prob. 15QAPCh. 18 - Prob. 16QAPCh. 18 - . What is the oxidation state of chlorine in each...Ch. 18 - . What is the oxidation state of manganese in each...Ch. 18 - Prob. 19QAPCh. 18 - Prob. 20QAPCh. 18 - Prob. 21QAPCh. 18 - Prob. 22QAPCh. 18 - Prob. 23QAPCh. 18 - Prob. 24QAPCh. 18 - Prob. 25QAPCh. 18 - Prob. 26QAPCh. 18 - . Does an oxidizing agent donate or accept...Ch. 18 - Prob. 28QAPCh. 18 - Prob. 29QAPCh. 18 - Prob. 30QAPCh. 18 - Prob. 31QAPCh. 18 - Prob. 32QAPCh. 18 - Prob. 33QAPCh. 18 - Prob. 34QAPCh. 18 - Prob. 35QAPCh. 18 - Prob. 36QAPCh. 18 - Prob. 37QAPCh. 18 - Prob. 38QAPCh. 18 - Prob. 39QAPCh. 18 - Prob. 40QAPCh. 18 - Prob. 41QAPCh. 18 - Prob. 42QAPCh. 18 - Prob. 43QAPCh. 18 - Prob. 44QAPCh. 18 - . Balance each of the following...Ch. 18 - Prob. 46QAPCh. 18 - . Iodide ion, I- , is one of the most easily...Ch. 18 - Prob. 48QAPCh. 18 - Prob. 49QAPCh. 18 - Prob. 50QAPCh. 18 - . In which direction do electrons flow in a...Ch. 18 - Prob. 52QAPCh. 18 - . Consider the oxidation-reduction reaction...Ch. 18 - . Consider the oxidation—reduction reaction...Ch. 18 - Prob. 55QAPCh. 18 - Prob. 56QAPCh. 18 - Prob. 57QAPCh. 18 - Prob. 58QAPCh. 18 - Prob. 59QAPCh. 18 - Prob. 60QAPCh. 18 - Prob. 61QAPCh. 18 - . What are some important uses of electrolysis?Ch. 18 - . Although aluminum is one of the most abundant...Ch. 18 - . The “Chemistry in Focus” segment Water-Powered...Ch. 18 - Prob. 65APCh. 18 - Prob. 66APCh. 18 - Prob. 67APCh. 18 - Prob. 68APCh. 18 - Prob. 69APCh. 18 - Prob. 70APCh. 18 - Prob. 71APCh. 18 - Prob. 72APCh. 18 - Prob. 73APCh. 18 - . To obtain useful electrical energy from an...Ch. 18 - Prob. 75APCh. 18 - Prob. 76APCh. 18 - Prob. 77APCh. 18 - Prob. 78APCh. 18 - . The “pressure” on electrons to flow from one...Ch. 18 - Prob. 80APCh. 18 - Prob. 81APCh. 18 - Prob. 82APCh. 18 - Prob. 83APCh. 18 - . For each of the following unbalanced...Ch. 18 - Prob. 85APCh. 18 - Prob. 86APCh. 18 - Prob. 87APCh. 18 - . Balance each of the following...Ch. 18 - . Balance each of the following...Ch. 18 - . For each of the following oxidation-reduction...Ch. 18 - . For each of the following oxidation-reduction...Ch. 18 - . Assign oxidation sates to all of the atoms in...Ch. 18 - . Assign oxidation states to all of the atoms in...Ch. 18 - Prob. 94APCh. 18 - Prob. 95APCh. 18 - . Assign oxidation states to all of the atoms in...Ch. 18 - Prob. 97APCh. 18 - . In each of the following reactions, identify...Ch. 18 - . Balance each of the following half-reactions....Ch. 18 - Prob. 100APCh. 18 - Prob. 101APCh. 18 - Prob. 102APCh. 18 - . Consider the oxidation—reduction reaction...Ch. 18 - Prob. 104APCh. 18 - Prob. 105CP
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